你也可以创建边界的颜色你的愿望..

view.layer.borderColor = [UIColor colorWithRed:r/255.0 green:g/255.0 blue:b/255.0 alpha:1.0].CGColor;

*r,g,b是0到255之间的值。

试试下面的代码:

view.layer.borderColor =  [UIColor redColor].CGColor;
view.layer.borderWidth= 2.0;
[view setClipsToBounds:YES];

我想把这个添加到@marczking的答案(选项1)作为评论，但我在StackOverflow上的低级状态阻止了这一点。

我把@marczking对Objective c的回答做了一个移植，非常有魅力，谢谢@marczking!

UIView+Border.h：

#import <UIKit/UIKit.h>

IB_DESIGNABLE
@interface UIView (Border)

-(void)setBorderColor:(UIColor *)color;
-(void)setBorderWidth:(CGFloat)width;
-(void)setCornerRadius:(CGFloat)radius;

@end

UIView+Border.m：

#import "UIView+Border.h"

@implementation UIView (Border)
// Note: cannot use synthesize in a Category

-(void)setBorderColor:(UIColor *)color
{
    self.layer.borderColor = color.CGColor;
}

-(void)setBorderWidth:(CGFloat)width
{
    self.layer.borderWidth = width;
}

-(void)setCornerRadius:(CGFloat)radius
{
    self.layer.cornerRadius = radius;
    self.layer.masksToBounds = radius > 0;
}

@end

view.layer.borderWidth = 1.0
view.layer.borderColor = UIColor.lightGray.cgColor

(self。view。layer setBorderColor: [uicolcolorwithred:0.265 green:0.447 blue:0.767 alpha:1.0f].CGColor];

@IBInspectable在iOS 9和Swift 2.0上为我工作

extension UIView {

@IBInspectable var borderWidth: CGFloat {
get {
        return layer.borderWidth
    }
    set(newValue) {
        layer.borderWidth = newValue
    }
}

@IBInspectable var cornerRadius: CGFloat {
    get {
        return layer.cornerRadius
    }
    set(newValue) {
        layer.cornerRadius = newValue
    }
}

@IBInspectable var borderColor: UIColor? {
    get {
        if let color = layer.borderColor {
            return UIColor(CGColor: color)
        }
        return nil
    }
    set(newValue) {
        layer.borderColor = newValue?.CGColor
    }
}