如何让Selenium 2.0等待页面加载?


当前回答

这段代码将等待页面上的所有元素都加载到DOM中。

WebDriver driver = new WebDriver();
WebDriverWait wait = new WebDriverWait(driver, timeout);

wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//*")));

其他回答

The best way to wait for page loads when using the Java bindings for WebDriver is to use the Page Object design pattern with PageFactory. This allows you to utilize the AjaxElementLocatorFactory which to put it simply acts as a global wait for all of your elements. It has limitations on elements such as drop-boxes or complex javascript transitions but it will drastically reduce the amount of code needed and speed up test times. A good example can be found in this blogpost. Basic understanding of Core Java is assumed.

http://startingwithseleniumwebdriver.blogspot.ro/2015/02/wait-in-page-factory.html

Use:

driver.manage().timeOuts().implicitlyWait(10, TimeUnit.SECONDS);

这意味着对网页上元素的任何搜索都需要时间来加载。implicitlyWait在抛出异常之前设置。 TimeUnit显示您想要等待的任何方式(秒、分、小时和天)。

伙计,所有这些答案都需要太多代码。这应该是一个简单的事情,因为它很常见。

为什么不注入一些简单的Javascript与web驱动程序和检查。 这就是我在webscraper课上使用的方法。Javascript是相当基本的,即使你不知道它。

def js_get_page_state(self):
"""
Javascript for getting document.readyState
:return: Pages state. See doc link below.
"""
ready_state = self.driver.execute_script('return document.readyState')
if ready_state == 'loading':
    self.logger.info("Loading Page...")
elif ready_state == 'interactive':
    self.logger.info("Page is interactive")
elif ready_state == 'complete':
    self.logger.info("The page is fully loaded!")
return ready_state

更多信息见“文档”。MDN Web Docs的readyState: https://developer.mozilla.org/en-US/docs/Web/API/Document/readyState

隐式和显式的等待更好。

但是如果你在Java中处理一个异常,那么你可以使用这个来等待页面重新加载:

Thead.sleep(1000);

使用这个函数

public void waitForPageLoad(ChromeDriver d){
        String s="";
        while(!s.equals("complete")){
        s=(String) d.executeScript("return document.readyState");
        try {
            Thread.sleep(1000);
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        }

    }