如何让Selenium 2.0等待页面加载?
当前回答
如果有人使用硒化物:
public static final Long SHORT_WAIT = 5000L; // 5 seconds
$("some_css_selector").waitUntil(Condition.appear, SHORT_WAIT);
更多条件可以在这里找到: http://selenide.org/javadoc/3.0/com/codeborne/selenide/Condition.html
其他回答
The best way to wait for page loads when using the Java bindings for WebDriver is to use the Page Object design pattern with PageFactory. This allows you to utilize the AjaxElementLocatorFactory which to put it simply acts as a global wait for all of your elements. It has limitations on elements such as drop-boxes or complex javascript transitions but it will drastically reduce the amount of code needed and speed up test times. A good example can be found in this blogpost. Basic understanding of Core Java is assumed.
http://startingwithseleniumwebdriver.blogspot.ro/2015/02/wait-in-page-factory.html
您可以尝试这段代码,让页面完全加载,直到找到元素为止。
public void waitForBrowserToLoadCompletely() {
String state = null;
String oldstate = null;
try {
System.out.print("Waiting for browser loading to complete");
int i = 0;
while (i < 5) {
Thread.sleep(1000);
state = ((JavascriptExecutor) driver).executeScript("return document.readyState;").toString();
System.out.print("." + Character.toUpperCase(state.charAt(0)) + ".");
if (state.equals("interactive") || state.equals("loading"))
break;
/*
* If browser in 'complete' state since last X seconds. Return.
*/
if (i == 1 && state.equals("complete")) {
System.out.println();
return;
}
i++;
}
i = 0;
oldstate = null;
Thread.sleep(2000);
/*
* Now wait for state to become complete
*/
while (true) {
state = ((JavascriptExecutor) driver).executeScript("return document.readyState;").toString();
System.out.print("." + state.charAt(0) + ".");
if (state.equals("complete"))
break;
if (state.equals(oldstate))
i++;
else
i = 0;
/*
* If browser state is same (loading/interactive) since last 60
* secs. Refresh the page.
*/
if (i == 15 && state.equals("loading")) {
System.out.println("\nBrowser in " + state + " state since last 60 secs. So refreshing browser.");
driver.navigate().refresh();
System.out.print("Waiting for browser loading to complete");
i = 0;
} else if (i == 6 && state.equals("interactive")) {
System.out.println(
"\nBrowser in " + state + " state since last 30 secs. So starting with execution.");
return;
}
Thread.sleep(4000);
oldstate = state;
}
System.out.println();
} catch (InterruptedException ie) {
ie.printStackTrace();
}
}
在python中,你可以简单地使用:
driver.implicitly_wait(30)
使用隐式等待等待页面上的每个元素直到给定的时间。
driver.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS);
这将等待页面上的每个元素30秒。
另一种等待是显式等待或有条件等待,在这个等待直到给定条件。
WebDriverWait wait = new WebDriverWait(driver, 40);
WebElement element = wait.until(ExpectedConditions.elementToBeClickable(By.id("someid")));
在id中,给出静态元素id,一旦页面加载,它就会不小心显示在页面上。
我使用node + selenium-webdriver(现在的版本是3.5.0)。我所做的是:
var webdriver = require('selenium-webdriver'),
driver = new webdriver.Builder().forBrowser('chrome').build();
;
driver.wait(driver.executeScript("return document.readyState").then(state => {
return state === 'complete';
}))
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