我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
我有两个JavaScript数组:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
我希望输出为:
var array3 = ["Vijendra","Singh","Shakya"];
输出数组应删除重复的单词。
如何在JavaScript中合并两个数组,以便从每个数组中只获得唯一的项目,其顺序与它们插入原始数组的顺序相同?
当前回答
我学会了一种用扩展运算符连接两个数组的小方法:
var array1 = ['tom', 'dick', 'harry'];
var array2 = ['martin', 'ricky'];
array1.push(...array2);
“…”扩展运算符将以下数组拆分为单个项,然后push可以将它们作为单独的参数处理。
其他回答
//1.merge two array into one array
var arr1 = [0, 1, 2, 4];
var arr2 = [4, 5, 6];
//for merge array we use "Array.concat"
let combineArray = arr1.concat(arr2); //output
alert(combineArray); //now out put is 0,1,2,4,4,5,6 but 4 reapeat
//2.same thing with "Spread Syntex"
let spreadArray = [...arr1, ...arr2];
alert(spreadArray); //now out put is 0,1,2,4,4,5,6 but 4 reapete
/*
if we need remove duplicate element method use are
1.Using set
2.using .filter
3.using .reduce
*/
带过滤器的最简单解决方案:
var array1 = ["Vijendra","Singh"];
var array2 = ["Singh", "Shakya"];
var mergedArrayWithoutDuplicates = array1.concat(
array2.filter(seccondArrayItem => !array1.includes(seccondArrayItem))
);
在当今时代,使用现有的图书馆提供更简单、更优雅的内容:
import {pipe, concat, distinct} from 'iter-ops';
// our inputs:
const array1 = ['Vijendra', 'Singh'];
const array2 = ['Singh', 'Shakya'];
const i = pipe(
array1,
concat(array2), // adding array
distinct() // making it unique
);
console.log([...i]); //=> ['Vijendra', 'Singh', 'Shakya']
这两者都是高性能的,因为我们只迭代一次,而且代码非常容易阅读。
注:我是iter ops的作者。
使用Lodash
我发现@GijsjanB的答案很有用,但我的数组包含具有许多属性的对象,因此我不得不使用其中一个属性来消除它们的重复。
这是我使用lodash的解决方案
userList1 = [{ id: 1 }, { id: 2 }, { id: 3 }]
userList2 = [{ id: 3 }, { id: 4 }, { id: 5 }]
// id 3 is repeated in both arrays
users = _.unionWith(userList1, userList2, function(a, b){ return a.id == b.id });
// users = [{ id: 1 }, { id: 2 }, { id: 3 }, { id: 4 }, { id: 5 }]
作为第三个参数传递的函数有两个参数(两个元素),如果它们相等,则必须返回true。
我有一个类似的请求,但它具有数组中元素的Id。
这里是我进行重复数据消除的方法。
它简单,易于维护,使用方便。
// Vijendra's Id = Id_0
// Singh's Id = Id_1
// Shakya's Id = Id_2
let item0 = { 'Id': 'Id_0', 'value': 'Vijendra' };
let item1 = { 'Id': 'Id_1', 'value': 'Singh' };
let item2 = { 'Id': 'Id_2', 'value': 'Shakya' };
let array = [];
array = [ item0, item1, item1, item2 ];
let obj = {};
array.forEach(item => {
obj[item.Id] = item;
});
let deduplicatedArray = [];
let deduplicatedArrayOnlyValues = [];
for(let [index, item] of Object.values(obj).entries()){
deduplicatedArray = [ ...deduplicatedArray, item ];
deduplicatedArrayOnlyValues = [ ...deduplicatedArrayOnlyValues , item.value ];
};
console.log( JSON.stringify(array) );
console.log( JSON.stringify(deduplicatedArray) );
console.log( JSON.stringify(deduplicatedArrayOnlyValues ) );
控制台日志
[{"recordId":"Id_0","value":"Vijendra"},{"recordId":"Id_1","value":"Singh"},{"recordId":"Id_1","value":"Singh"},{"recordId":"Id_2","value":"Shakya"}]
[{"recordId":"Id_0","value":"Vijendra"},{"recordId":"Id_1","value":"Singh"},{"recordId":"Id_2","value":"Shakya"}]
["Vijendra","Singh","Shakya"]