我记录了15种用Java读取文件的方法，然后测试了它们在不同文件大小下的速度——从1kb到1gb，下面是最常用的三种方法:

java.nio.file.Files.readAllBytes() Tested to work in Java 7, 8, and 9. import java.io.File; import java.io.IOException; import java.nio.file.Files; public class ReadFile_Files_ReadAllBytes { public static void main(String [] pArgs) throws IOException { String fileName = "c:\\temp\\sample-10KB.txt"; File file = new File(fileName); byte [] fileBytes = Files.readAllBytes(file.toPath()); char singleChar; for(byte b : fileBytes) { singleChar = (char) b; System.out.print(singleChar); } } } java.io.BufferedReader.readLine() Tested to work in Java 7, 8, 9. import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; public class ReadFile_BufferedReader_ReadLine { public static void main(String [] args) throws IOException { String fileName = "c:\\temp\\sample-10KB.txt"; FileReader fileReader = new FileReader(fileName); try (BufferedReader bufferedReader = new BufferedReader(fileReader)) { String line; while((line = bufferedReader.readLine()) != null) { System.out.println(line); } } } } java.nio.file.Files.lines() This was tested to work in Java 8 and 9 but won't work in Java 7 because of the lambda expression requirement. import java.io.File; import java.io.IOException; import java.nio.file.Files; import java.util.stream.Stream; public class ReadFile_Files_Lines { public static void main(String[] pArgs) throws IOException { String fileName = "c:\\temp\\sample-10KB.txt"; File file = new File(fileName); try (Stream linesStream = Files.lines(file.toPath())) { linesStream.forEach(line -> { System.out.println(line); }); } } }

org.apache.commons.io.FileUtils中的方法也可能非常方便，例如:

/**
 * Reads the contents of a file line by line to a List
 * of Strings using the default encoding for the VM.
 */
static List readLines(File file)

try {
  File f = new File("filename.txt");
  Scanner r = new Scanner(f);  
  while (r.hasNextLine()) {
    String data = r.nextLine();
    JOptionPane.showMessageDialog(data);
  }
  r.close();
} catch (FileNotFoundException ex) {
  JOptionPane.showMessageDialog("Error occurred");
  ex.printStackTrace();
}

我编写的这段代码对于非常大的文件要快得多:

public String readDoc(File f) {
    String text = "";
    int read, N = 1024 * 1024;
    char[] buffer = new char[N];

    try {
        FileReader fr = new FileReader(f);
        BufferedReader br = new BufferedReader(fr);

        while(true) {
            read = br.read(buffer, 0, N);
            text += new String(buffer, 0, read);

            if(read < N) {
                break;
            }
        }
    } catch(Exception ex) {
        ex.printStackTrace();
    }

    return text;
}

import java.util.stream.Stream;
import java.nio.file.*;
import java.io.*;

class ReadFile {

 public static void main(String[] args) {

    String filename = "Test.txt";

    try(Stream<String> stream = Files.lines(Paths.get(filename))) {

          stream.forEach(System.out:: println);

    } catch (IOException e) {

        e.printStackTrace();
    }

 }

 }

只需使用java 8流。

最简单的方法是使用Java中的Scanner类和FileReader对象。简单的例子:

Scanner in = new Scanner(new FileReader("filename.txt"));

扫描器有几个方法读取字符串，数字，等…您可以在Java文档页面上查找有关这方面的更多信息。

例如，将整个内容读入String:

StringBuilder sb = new StringBuilder();
while(in.hasNext()) {
    sb.append(in.next());
}
in.close();
outString = sb.toString();

另外，如果你需要一个特定的编码，你可以使用这个来代替FileReader:

new InputStreamReader(new FileInputStream(fileUtf8), StandardCharsets.UTF_8)