我有2-3个不同的列名,我想在整个数据库中查找,并列出所有具有这些列的表。有没有简单的脚本?


当前回答

获取数据库YourDatabase中所有列为columnna或ColumnB的表:

SELECT DISTINCT TABLE_NAME 
    FROM INFORMATION_SCHEMA.COLUMNS
    WHERE COLUMN_NAME IN ('columnA','ColumnB')
        AND TABLE_SCHEMA='YourDatabase';

其他回答

SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME LIKE '%city_id%' AND TABLE_SCHEMA='database'

对于那些与此相反的搜索,即寻找不包含特定列名的表,这里是查询…

SELECT DISTINCT TABLE_NAME FROM information_schema.columns WHERE 
TABLE_SCHEMA = 'your_db_name' AND TABLE_NAME NOT IN (SELECT DISTINCT 
TABLE_NAME FROM information_schema.columns WHERE column_name = 
'column_name' AND TABLE_SCHEMA = 'your_db_name');

当我们开始缓慢地实现InnoDB特殊的ai_col列的使用,并需要找出200个表中哪些表还没有升级时,这真的很方便。

如果你想“只获取所有的表”,那么使用这个查询:

SELECT TABLE_NAME
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME like '%'
and TABLE_SCHEMA = 'tresbu_lk'

如果你想“获取所有带列的表”,那么使用这个查询:

SELECT DISTINCT TABLE_NAME, COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE column_name LIKE '%'
AND TABLE_SCHEMA='tresbu_lk'

获取数据库YourDatabase中所有列为columnna或ColumnB的表:

SELECT DISTINCT TABLE_NAME 
    FROM INFORMATION_SCHEMA.COLUMNS
    WHERE COLUMN_NAME IN ('columnA','ColumnB')
        AND TABLE_SCHEMA='YourDatabase';

使用这一行查询。将desired_column_name替换为列名。

SELECT TABLE_NAME FROM information_schema.columns WHERE column_name = 'desired_column_name';