将这个ModelCollection.cs添加到您的模型中

using System;
using System.Collections.Generic;

namespace ModelContainer
{
  public class ModelCollection
  {
   private Dictionary<Type, object> models = new Dictionary<Type, object>();

   public void AddModel<T>(T t)
   {
      models.Add(t.GetType(), t);
   }

   public T GetModel<T>()
   {
     return (T)models[typeof(T)];
   }
 }
}

控制器:

public class SampleController : Controller
{
  public ActionResult Index()
  {
    var model1 = new Model1();
    var model2 = new Model2();
    var model3 = new Model3();

    // Do something

    var modelCollection = new ModelCollection();
    modelCollection.AddModel(model1);
    modelCollection.AddModel(model2);
    modelCollection.AddModel(model3);
    return View(modelCollection);
  }
}

视图:

enter code here
@using Models
@model ModelCollection

@{
  ViewBag.Title = "Model1: " + ((Model.GetModel<Model1>()).Name);
}

<h2>Model2: @((Model.GetModel<Model2>()).Number</h2>

@((Model.GetModel<Model3>()).SomeProperty

有很多方法……

with your BigViewModel you do: @model BigViewModel @using(Html.BeginForm()) { @Html.EditorFor(o => o.LoginViewModel.Email) ... } you can create 2 additional views Login.cshtml @model ViewModel.LoginViewModel @using (Html.BeginForm("Login", "Auth", FormMethod.Post)) { @Html.TextBoxFor(model => model.Email) @Html.PasswordFor(model => model.Password) } and register.cshtml same thing after creation you have to render them in the main view and pass them the viewmodel/viewdata so it could be like this: @{Html.RenderPartial("login", ViewBag.Login);} @{Html.RenderPartial("register", ViewBag.Register);} or @{Html.RenderPartial("login", Model.LoginViewModel)} @{Html.RenderPartial("register", Model.RegisterViewModel)} using ajax parts of your web-site become more independent iframes, but probably this is not the case

使用包含多个视图模型的视图模型:

   namespace MyProject.Web.ViewModels
   {
      public class UserViewModel
      {
          public UserDto User { get; set; }
          public ProductDto Product { get; set; }
          public AddressDto Address { get; set; }
      }
   }

你认为:

  @model MyProject.Web.ViewModels.UserViewModel

  @Html.LabelFor(model => model.User.UserName)
  @Html.LabelFor(model => model.Product.ProductName)
  @Html.LabelFor(model => model.Address.StreetName)

你总是可以在ViewBag或View Data中传递第二个对象。

我建议使用Html。RenderAction和PartialViewResults来完成这个;它将允许您显示相同的数据，但每个部分视图仍然有一个单一的视图模型，并消除了对BigViewModel的需要

你的视图包含如下内容:

@Html.RenderAction("Login")
@Html.RenderAction("Register")

其中Login和Register都是你控制器中的动作，定义如下:

public PartialViewResult Login( )
{
    return PartialView( "Login", new LoginViewModel() );
}

public PartialViewResult Register( )
{
    return PartialView( "Register", new RegisterViewModel() );
}

Login & Register将是位于当前View文件夹或共享文件夹中的用户控件，并像这样:

/views/Shared/Login.cshtml： （或 /views/MyView/Login.cshtml）

@model LoginViewModel
@using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
    @Html.TextBoxFor(model => model.Email)
    @Html.PasswordFor(model => model.Password)
}

/views/Shared/Register.cshtml： （或 /views/MyView/Register.cshtml）

@model ViewModel.RegisterViewModel
@using (Html.BeginForm("Login", "Auth", FormMethod.Post))
{
    @Html.TextBoxFor(model => model.Name)
    @Html.TextBoxFor(model => model.Email)
    @Html.PasswordFor(model => model.Password)
}

你有一个单独的控制器动作，每个动作都有视图和视图文件每个动作都完全不同，不依赖于其他任何东西。

这是一个使用IEnumerable的简化示例。

我在视图上使用了两个模型:一个是带有搜索条件的表单(SearchParams模型)，另一个是用于显示结果的网格，我还纠结于如何在同一个视图上添加IEnumerable模型和另一个模型。这是我想到的，希望能帮助到一些人:

@using DelegatePortal.ViewModels;

@model SearchViewModel

@using (Html.BeginForm("Search", "Delegate", FormMethod.Post))
{

                Employee First Name
                @Html.EditorFor(model => model.SearchParams.FirstName,
new { htmlAttributes = new { @class = "form-control form-control-sm " } })

                <input type="submit" id="getResults" value="SEARCH" class="btn btn-primary btn-lg btn-block" />

}
<br />
    @(Html
        .Grid(Model.Delegates)
        .Build(columns =>
        {
            columns.Add(model => model.Id).Titled("Id").Css("collapse");
            columns.Add(model => model.LastName).Titled("Last Name");
            columns.Add(model => model.FirstName).Titled("First Name");
        })

.．. ）

SearchViewModel.cs:

namespace DelegatePortal.ViewModels
{
    public class SearchViewModel
    {
        public IEnumerable<DelegatePortal.Models.DelegateView> Delegates { get; set; }

        public SearchParamsViewModel SearchParams { get; set; }
....

DelegateController.cs:

// GET: /Delegate/Search
    public ActionResult Search(String firstName)
    {
        SearchViewModel model = new SearchViewModel();
        model.Delegates = db.Set<DelegateView>();
        return View(model);
    }

    // POST: /Delegate/Search
    [HttpPost]
    public ActionResult Search(SearchParamsViewModel searchParams)
    {
        String firstName = searchParams.FirstName;
        SearchViewModel model = new SearchViewModel();

        if (firstName != null)
            model.Delegates = db.Set<DelegateView>().Where(x => x.FirstName == firstName);

        return View(model);
    }

SearchParamsViewModel.cs:

namespace DelegatePortal.ViewModels
{
    public class SearchParamsViewModel
    {
        public string FirstName { get; set; }
    }
}