如何在以下列表中搜索包含字符串“abc”的项目?
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:
if 'abc' in xs:
如何在以下列表中搜索包含字符串“abc”的项目?
xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:
if 'abc' in xs:
当前回答
如果要获取多个子字符串的数据列表
你可以这样改
some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
# select element where "abc" or "ghi" is included
find_1 = "abc"
find_2 = "ghi"
result = [element for element in some_list if find_1 in element or find_2 in element]
# Output ['abc-123', 'ghi-789', 'abc-456']
其他回答
my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
if (item.find('abc')) != -1:
print ('Found at ', item)
any('abc' in item for item in mylist)
问题:给出abc的信息
a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
aa = [ string for string in a if "abc" in string]
print(aa)
Output => ['abc-123', 'abc-456']
我是Python新手。我得到了下面的代码,使其易于理解:
my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for item in my_list:
if 'abc' in item:
print(item)
如果要获取多个子字符串的数据列表
你可以这样改
some_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
# select element where "abc" or "ghi" is included
find_1 = "abc"
find_2 = "ghi"
result = [element for element in some_list if find_1 in element or find_2 in element]
# Output ['abc-123', 'ghi-789', 'abc-456']