如何在以下列表中搜索包含字符串“abc”的项目?

xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

以下检查“abc”是否在列表中,但未检测到“abc-123”和“abc-456”:

if 'abc' in xs:

当前回答

my_list = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

for item in my_list:
    if (item.find('abc')) != -1:
        print ('Found at ', item)

其他回答

我需要与以下匹配项对应的列表索引:

lst=['abc-123', 'def-456', 'ghi-789', 'abc-456']

[n for n, x in enumerate(lst) if 'abc' in x]

输出

[0, 3]

问题:给出abc的信息

a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']


aa = [ string for string in a if  "abc" in string]
print(aa)


Output =>  ['abc-123', 'abc-456']

使用Pythons字符串类的__contains__()方法。:

a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']
for i in a:
    if i.__contains__("abc") :
        print(i, " is containing")

要检查列表中任何字符串中是否存在“abc”,请执行以下操作:

xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

if any("abc" in s for s in xs):
    ...

要获取包含“abc”的所有项目:

matching = [s for s in xs if "abc" in s]
x = 'aaa'
L = ['aaa-12', 'bbbaaa', 'cccaa']
res = [y for y in L if x in y]