for item in my_list:
    if item.find("abc") != -1:
        print item

def find_dog(new_ls):
    splt = new_ls.split()
    if 'dog' in splt:
        print("True")
    else:
        print('False')


find_dog("Is there a dog here?")

要检查列表中任何字符串中是否存在“abc”，请执行以下操作：

xs = ['abc-123', 'def-456', 'ghi-789', 'abc-456']

if any("abc" in s for s in xs):
    ...

要获取包含“abc”的所有项目：

matching = [s for s in xs if "abc" in s]

问题：给出abc的信息

a = ['abc-123', 'def-456', 'ghi-789', 'abc-456']


aa = [ string for string in a if  "abc" in string]
print(aa)


Output =>  ['abc-123', 'abc-456']

我需要与以下匹配项对应的列表索引：

lst=['abc-123', 'def-456', 'ghi-789', 'abc-456']

[n for n, x in enumerate(lst) if 'abc' in x]

输出

[0, 3]

只是抛出这个：如果你恰好需要匹配多个字符串，例如abc和def，你可以按如下方式组合两个理解：

matchers = ['abc','def']
matching = [s for s in my_list if any(xs in s for xs in matchers)]

输出：

['abc-123', 'def-456', 'abc-456']