如何检测用户用JavaScript在网页上向某个方向滑动手指?

我想知道是否有一种解决方案可以同时适用于iPhone和Android手机上的网站。


当前回答

我之前使用的方法是,您必须检测mousedown事件,记录其x,y位置(任何相关的位置),然后检测mouseup事件,并减去两个值。

其他回答

我必须为旋转木马编写一个简单的脚本,以检测向左或向右的滑动。

我使用指针事件代替触摸事件。

我希望这对个人有用,我欢迎任何改进我的代码的见解;我觉得很不好意思加入这个线程与显著优秀的JS开发人员。

function getSwipeX({elementId}) {

  this.e               = document.getElementsByClassName(elementId)[0];
  this.initialPosition = 0;
  this.lastPosition    = 0;
  this.threshold       = 200;
  this.diffInPosition  = null;
  this.diffVsThreshold = null;
  this.gestureState    = 0;

  this.getTouchStart = (event) => {
    event.preventDefault();
    if (window.PointerEvent) {
      this.e.setPointerCapture(event.pointerId);
    }
    return this.initalTouchPos = this.getGesturePoint(event);
  }

  this.getTouchMove  = (event) => {
    event.preventDefault();
    return this.lastPosition = this.getGesturePoint(event);
  }

  this.getTouchEnd   = (event) => {
    event.preventDefault();
    if (window.PointerEvent) {
      this.e.releasePointerCapture(event.pointerId);
    }
    this.doSomething();
    this.initialPosition = 0;
  }

  this.getGesturePoint = (event) => {
    this.point = event.pageX
    return this.point;
  }

  this.whatGestureDirection = (event) => {
    this.diffInPosition  = this.initalTouchPos - this.lastPosition;
    this.diffVsThreshold = Math.abs(this.diffInPosition) > this.threshold;
    (Math.sign(this.diffInPosition) > 0) ? this.gestureState = 'L' : (Math.sign(this.diffInPosition) < 0) ? this.gestureState = 'R' : this.gestureState = 'N';
    
    return [this.diffInPosition, this.diffVsThreshold, this.gestureState];
  }

  this.doSomething = (event) => {
    let [gestureDelta,gestureThreshold,gestureDirection] = this.whatGestureDirection();

    // USE THIS TO DEBUG
    console.log(gestureDelta,gestureThreshold,gestureDirection);

    if (gestureThreshold) {
      (gestureDirection == 'L') ? // LEFT ACTION : // RIGHT ACTION
    }
  }

  if (window.PointerEvent) {
    this.e.addEventListener('pointerdown', this.getTouchStart, true);
    this.e.addEventListener('pointermove', this.getTouchMove, true);
    this.e.addEventListener('pointerup', this.getTouchEnd, true);
    this.e.addEventListener('pointercancel', this.getTouchEnd, true);
  }
}

可以使用new调用该函数。

window.addEventListener('load', () => {
  let test = new getSwipeX({
    elementId: 'your_div_here'
  });
})

我之前使用的方法是,您必须检测mousedown事件,记录其x,y位置(任何相关的位置),然后检测mouseup事件,并减去两个值。

touchStart和touchEnd的句柄:

var handleSwipe = function(elem,callbackOnRight, callbackOnLeft, callbackOnDown, 
      callbackOnUp) => {

        elem.ontouchstart = handleTouchStart;
        elem.ontouchend = handleTouchEnd;

        var xDown = null;
        var yDown = null;

        function getTouches(evt) {
            return evt.touches ||             // browser API
                evt.originalEvent.touches; // jQuery
        }

        function handleTouchStart(evt) {
            const firstTouch = getTouches(evt)[0];
            xDown = firstTouch.clientX;
            yDown = firstTouch.clientY;
        };

        function handleTouchEnd(evt) {
            if (!xDown || !yDown) {
                return;
            }

            var xUp = evt.changedTouches[0].clientX;
            var yUp = evt.changedTouches[0].clientY;

            var xDiff = xDown - xUp;
            var yDiff = yDown - yUp;
            var minDif = 30;

            console.log(`xDiff:${xDiff}, yDiff:${yDiff}`);

            if (Math.abs(xDiff) > Math.abs(yDiff)) {
                if (xDiff > minDif) {
                    if (callbackOnLeft)
                        callbackOnLeft();
                } else if (xDiff < -1 * minDif){
                    if (callbackOnRight)
                        callbackOnRight();
                }
            } else {
                if (yDiff > minDif) {
                    if (callbackOnDown)
                        callbackOnDown();
                } else if (yDiff < -1* minDif){
                    if (callbackOnUp)
                        callbackOnUp();
                }
            }
            
            xDown = null;
            yDown = null;
        };
    }

jQuery Mobile还包括滑动支持:http://api.jquerymobile.com/swipe/

例子

$("#divId").on("swipe", function(event) {
    alert("It's a swipe!");
});

在这里的建议之上,我将跟踪手指号码,因为如果你同时用两个手指触摸,它将获得X位置,而不会导致一个奇怪的行为,而且,你可能想要设置一个“距离”最小值,这样用户在通过你的网站或应用程序触摸时就不会错误地触发滑动。

//Swipe 
let touchstartX = 0
let touchendX = 0
let fingerCount = 0
    
const checkDirection = () => {

  const distance = 50 //Minimum distance for the swipe to work

  //left
  if (touchendX < touchstartX && (touchstartX - touchendX) > distance ){

  //Do something cool
   
  } 
  //right
  if (touchendX > touchstartX && (touchendX - touchstartX) > distance){

    //Do something cooler
}

document.addEventListener('touchstart', e => {

    fingerCount = e.touches.length
    touchstartX = e.changedTouches[0].clientX  
     
})

document.addEventListener('touchend', e => {

    touchendX = e.changedTouches[0].clientX
    if(fingerCount === 1){ 
        checkDirection() 
    }

})