这是一个扩展的kfis指令，我做了允许不同级别的路径匹配。从本质上讲，我发现需要匹配URL路径到一定深度，因为精确匹配不允许嵌套和默认状态重定向。希望这能有所帮助。

    .directive('selectedLink', ['$location', function(location) {
    return {
        restrict: 'A',
        scope:{
            selectedLink : '='
            },
        link: function(scope, element, attrs, controller) {
            var level = scope.selectedLink;
            var path = attrs.href;
            path = path.substring(1); //hack because path does not return including hashbang
            scope.location = location;
            scope.$watch('location.path()', function(newPath) {
                var i=0;
                p = path.split('/');
                n = newPath.split('/');
                for( i ; i < p.length; i++) { 
                    if( p[i] == 'undefined' || n[i] == 'undefined' || (p[i] != n[i]) ) break;
                    }

                if ( (i-1) >= level) {
                    element.addClass("selected");
                    } 
                else {
                    element.removeClass("selected");
                    }
                });
            }

        };
    }]);

下面是我如何使用这个链接

<nav>
    <a href="#/info/project/list"  selected-link="2">Project</a>
    <a href="#/info/company/list" selected-link="2">Company</a>
    <a href="#/info/person/list"  selected-link="2">Person</a>
</nav>

该指令将匹配在该指令的属性值中指定的深度级别。只是意味着它可以在其他地方多次使用。

对于那些使用ui-router的人，我的答案有点类似于Ender2050，但我更喜欢通过州名测试来做到这一点:

$scope.isActive = function (stateName) {
  var active = (stateName === $state.current.name);
  return active;
};

相应的HTML:

<ul class="nav nav-sidebar">
    <li ng-class="{ active: isActive('app.home') }"><a ui-sref="app.home">Dashboard</a></li>
    <li ng-class="{ active: isActive('app.tiles') }"><a ui-sref="app.tiles">Tiles</a></li>
</ul>

路线:

$routeProvider.when('/Account/', { templateUrl: '/Home/Account', controller: 'HomeController' });

菜单html:

<li id="liInicio" ng-class="{'active':url=='account'}">

控制器:

angular.module('Home').controller('HomeController', function ($scope, $http, $location) {
    $scope.url = $location.url().replace(/\//g, "").toLowerCase();
...

我在这里发现的问题是，菜单项只有在加载整个页面时才处于活动状态。当部分视图被加载时，菜单不会改变。有人知道为什么吗?

使用Angular Version 6和Bootstrap 4.1

我能够做到如下所示。

在下面的例子中，当URL看到'/contact'时，引导活动就会被添加到html标记中。当URL改变时，它就会被删除。

<ul>
<li class="nav-item" routerLink="/contact" routerLinkActive="active">
    <a class="nav-link" href="/contact">Contact</a>
</li>
</ul>

这个指令允许你在链接的时候给元素添加一个CSS类 路由激活。

在Angular网站上阅读更多信息

Here is the solution that I came up with after reading some of the excellent suggestions above. In my particular situation, I was trying to use Bootstrap tabs component as my menu, but didn't want to use the Angular-UI version of this because I want the tabs to act as a menu, where each tab is bookmark-able, rather than the tabs acting as navigation for a single page. (See http://angular-ui.github.io/bootstrap/#/tabs if you're interested in what the Angular-UI version of bootstrap tabs looks like).

I really liked kfis's answer about creating your own directive to handle this, however it seemed cumbersome to have a directive that needed to be placed on every single link. So I've created my own Angular directive which is placed instead once on the ul. Just in case any one else is trying to do the same thing, I thought I'd post it here, though as I said, many of the above solutions work as well. This is a slightly more complex solution as far as the javascript goes, but it creates a reusable component with minimal markup.

下面是指令的javascript和ng:view的路由提供程序:

var app = angular.module('plunker', ['ui.bootstrap']).
  config(['$routeProvider', function($routeProvider) {
    $routeProvider.
        when('/One', {templateUrl: 'one.html'}).
        when('/Two', {templateUrl: 'two.html'}).
        when('/Three', {templateUrl: 'three.html'}).
        otherwise({redirectTo: '/One'});
  }]).
  directive('navTabs', ['$location', function(location) {
    return {
        restrict: 'A',
        link: function(scope, element) {
            var $ul = $(element);
            $ul.addClass("nav nav-tabs");

            var $tabs = $ul.children();
            var tabMap = {};
            $tabs.each(function() {
              var $li = $(this);
              //Substring 1 to remove the # at the beginning (because location.path() below does not return the #)
              tabMap[$li.find('a').attr('href').substring(1)] = $li;
            });

            scope.location = location;
            scope.$watch('location.path()', function(newPath) {
                $tabs.removeClass("active");
                tabMap[newPath].addClass("active");
            });
        }

    };

 }]);

然后在你的html中你只需:

<ul nav-tabs>
  <li><a href="#/One">One</a></li>
  <li><a href="#/Two">Two</a></li>
  <li><a href="#/Three">Three</a></li>
</ul>
<ng:view><!-- Content will appear here --></ng:view>

这里是它的活塞:http://plnkr.co/edit/xwGtGqrT7kWoCKnGDHYN?p=preview。

来自@Renan-tomal-fernandes的回答很好，但需要进行一些改进才能正确工作。 事实上，它总是在触发时检测到到主页(/)的链接，即使你在另一个部分。

我稍微改进了一下，这是代码。 我使用Bootstrap，所以活动部分是在<li>元素，而不是<a>。

控制器

$scope.getClass = function(path) {
    var cur_path = $location.path().substr(0, path.length);
    if (cur_path == path) {
        if($location.path().substr(0).length > 1 && path.length == 1 )
            return "";
        else
            return "active";
    } else {
        return "";
    }
}

模板

<div class="nav-collapse collapse">
  <ul class="nav">
    <li ng-class="getClass('/')"><a href="#/">Home</a></li>
    <li ng-class="getClass('/contents/')"><a href="#/contests/">Contents</a></li>
    <li ng-class="getClass('/data/')"><a href="#/data/">Your data</a></li>
  </ul>
</div>