我想从纬度和经度在安卓得到以下值
街道地址 城市/州 邮政编码 完整的地址
如何做到这一点?
我想从纬度和经度在安卓得到以下值
街道地址 城市/州 邮政编码 完整的地址
如何做到这一点?
当前回答
城市和国家不总是在地址1号线和2号线…
例子在这里
So,
Geocoder geocoder = new Geocoder(context, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(latitude,longitude, 1);
String address = addresses.get(0).getAddressLine(0);
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String zip = addresses.get(0).getPostalCode();
String country = addresses.get(0).getCountryName();
其他回答
只要用这个方法,把你的背,长。
public static void getAddress(Context context, double LATITUDE, double LONGITUDE{
//Set Address
try {
Geocoder geocoder = new Geocoder(context, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
if (addresses != null && addresses.size() > 0) {
String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL
Log.d(TAG, "getAddress: address" + address);
Log.d(TAG, "getAddress: city" + city);
Log.d(TAG, "getAddress: state" + state);
Log.d(TAG, "getAddress: postalCode" + postalCode);
Log.d(TAG, "getAddress: knownName" + knownName);
}
} catch (IOException e) {
e.printStackTrace();
}
return;
}
在onCreate () . .
LocationManager locationManager = (LocationManager) getSystemService(LOCATION_SERVICE);
locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 30000, 0, this);
Criteria criteria = new Criteria();
String bestProvider = locationManager.getBestProvider(criteria, true);
Location location = locationManager.getLastKnownLocation(bestProvider);
if (location == null) {
Toast.makeText(getApplicationContext(), "GPS signal not found",
3000).show();
}
if (location != null) {
Log.e("location", "location--" + location);
Log.e("latitude at beginning",
"@@@@@@@@@@@@@@@" + location.getLatitude());
onLocationChanged(location);
}
在onLocationChanged()中编写代码
@Override
public void onLocationChanged(Location location) {
Geocoder geocoder;
List<Address> addresses;
geocoder = new Geocoder(this, Locale.getDefault());
latitude = location.getLatitude();
longitude = location.getLongitude();
Log.e("latitude", "latitude--" + latitude);
try {
Log.e("latitude", "inside latitude--" + latitude);
addresses = geocoder.getFromLocation(latitude, longitude, 1);
if (addresses != null && addresses.size() > 0) {
String address = addresses.get(0).getAddressLine(0);
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName();
locationTxt.setText(address + " " + city + " " + country);
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
从latlong (Geo-coordinates)获取Address还有最后一个技巧。你可以简单地通过经度和纬度点击谷歌地图web服务。它只是一个GET-Method web服务。
它将返回JSON响应,可以很容易地解析以获得地址。它的URL是:
http://maps.googleapis.com/maps/api/geocode/json?latlng=32,75&sensor=true
你可以用lat,long代替32,75。
尝试使用geocoder使用下面的代码:
Geocoder gcd = new Geocoder(MainActivity.this, Locale.getDefault());
List<Address> geoAddresses = geoAddresses = gcd.getFromLocation(location.getLatitude(), location.getLongitude(), 1);
if (geoAddresses.size() > 0) {
String mUserLocation = "";
for (int i = 0; i < 4; i++) { //Since it return only four value we declare this as static.
mUserLocation = mUserLocation + geoAddresses.get(0).getAddressLine(i).replace(",", "") + ", ";
}
}
试试这段代码(正在工作)
public void GetLocation() throws IOException {
LocationManager locationManager = (LocationManager) context.getSystemService(LOCATION_SERVICE);
if (ActivityCompat.checkSelfPermission(context, Manifest.permission.ACCESS_COARSE_LOCATION) != PackageManager.PERMISSION_GRANTED
|| (ActivityCompat.checkSelfPermission(context, Manifest.permission.ACCESS_FINE_LOCATION) != PackageManager.PERMISSION_GRANTED)) {
ActivityCompat.requestPermissions(getActivity(), new String[]{Manifest.permission.ACCESS_FINE_LOCATION, Manifest.permission.ACCESS_COARSE_LOCATION
}, 200);
return;
} else {
locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 30000, 0, new LocationListener() {
@Override
public void onLocationChanged(Location location) {
Log.d(TAG, "onLocationChanged: " + location.getLongitude() + " , " + location.getLatitude());
}
@Override
public void onStatusChanged(String s, int i, Bundle bundle) {
Log.d(TAG, "onStatusChanged: " + s);
}
@Override
public void onProviderEnabled(String s) {
}
@Override
public void onProviderDisabled(String s) {
}
});
Criteria criteria = new Criteria();
String bestProvider = locationManager.getBestProvider(criteria, true);
Location location = locationManager.getLastKnownLocation(bestProvider);
if (location == null) {
Toast.makeText(context, "GPS signal not found",
Toast.LENGTH_LONG).show();
}
if (location != null) {
Log.e("location", "location--" + location);
Log.e("latitude at beginning",
"@@@@@@@@@@@@@@@" + location.getLatitude());
// onLocationChanged(location);
}
Geocoder geocoder;
List<Address> addresses;
geocoder = new Geocoder(context, Locale.getDefault());
addresses = geocoder.getFromLocation(location.getLatitude(), location.getLongitude(), 1); // Here 1 represent max location result to returned, by documents it recommended 1 to 5
String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName();
Log.d(TAG, "GetLocation: address " + address + " city " + city + " state " + state + " country " + country + " postalCode " + postalCode + " knownName " + knownName);
}
}