在ios7中,sizeWithFont:现在已弃用。我现在如何在UIFont对象传递到替换方法sizeWithAttributes:?


当前回答

我创建了一个类别来处理这个问题,它是:

#import "NSString+StringSizeWithFont.h"

@implementation NSString (StringSizeWithFont)

- (CGSize) sizeWithMyFont:(UIFont *)fontToUse
{
    if ([self respondsToSelector:@selector(sizeWithAttributes:)])
    {
        NSDictionary* attribs = @{NSFontAttributeName:fontToUse};
        return ([self sizeWithAttributes:attribs]);
    }
    return ([self sizeWithFont:fontToUse]);
}

这样你只需要找到/替换sizeWithFont: sizeWithMyFont:你就可以了。

其他回答

改用sizeWithAttributes:,它现在接受一个NSDictionary。传入key UITextAttributeFont和你的字体对象,如下所示:

CGRect rawRect = {};
rawRect.size = [string sizeWithAttributes: @{
    NSFontAttributeName: [UIFont systemFontOfSize:17.0f],
}];

// Values are fractional -- you should take the ceil to get equivalent values
CGSize adjustedSize = CGRectIntegral(rawRect).size;

正如你在苹果开发者网站上看到的sizeWithFont,它已被弃用,所以我们需要使用sizeWithAttributes。

#define SYSTEM_VERSION_LESS_THAN(v) ([[[UIDevice currentDevice] systemVersion] compare:v options:NSNumericSearch] == NSOrderedAscending)

NSString *text = @"Hello iOS 7.0";
if (SYSTEM_VERSION_LESS_THAN(@"7.0")) {
    // code here for iOS 5.0,6.0 and so on
    CGSize fontSize = [text sizeWithFont:[UIFont fontWithName:@"Helvetica" 
                                                         size:12]];
} else {
    // code here for iOS 7.0
   CGSize fontSize = [text sizeWithAttributes: 
                            @{NSFontAttributeName: 
                              [UIFont fontWithName:@"Helvetica" size:12]}];
}

基于@bitsand,这是一个新方法,我刚刚添加到我的NSString+Extras类别:

- (CGRect) boundingRectWithFont:(UIFont *) font constrainedToSize:(CGSize) constraintSize lineBreakMode:(NSLineBreakMode) lineBreakMode;
{
    // set paragraph style
    NSMutableParagraphStyle *style = [[NSParagraphStyle defaultParagraphStyle] mutableCopy];
    [style setLineBreakMode:lineBreakMode];

    // make dictionary of attributes with paragraph style
    NSDictionary *sizeAttributes = @{NSFontAttributeName:font, NSParagraphStyleAttributeName: style};

    CGRect frame = [self boundingRectWithSize:constraintSize options:NSStringDrawingUsesLineFragmentOrigin attributes:sizeAttributes context:nil];

    /*
    // OLD
    CGSize stringSize = [self sizeWithFont:font
                              constrainedToSize:constraintSize
                                  lineBreakMode:lineBreakMode];
    // OLD
    */

    return frame;
}

我只是使用结果帧的大小。

替代解决方案,

CGSize expectedLabelSize;
if ([subTitle respondsToSelector:@selector(sizeWithAttributes:)])
{
    expectedLabelSize = [subTitle sizeWithAttributes:@{NSFontAttributeName:subTitleLabel.font}];
}else{
    expectedLabelSize = [subTitle sizeWithFont:subTitleLabel.font constrainedToSize:subTitleLabel.frame.size lineBreakMode:NSLineBreakByWordWrapping];
}

在iOS7中,我需要逻辑来为tableview返回正确的高度:highightforrowatindexpath方法,但sizeWithAttributes总是返回相同的高度,而不管字符串长度,因为它不知道它将被放在一个固定宽度的表格单元格。我发现这对我来说很有用,并计算出正确的高度,考虑到表格单元格的宽度!这是基于上面T先生的回答。

NSString *text = @"The text that I want to wrap in a table cell."

CGFloat width = tableView.frame.size.width - 15 - 30 - 15;  //tableView width - left border width - accessory indicator - right border width
UIFont *font = [UIFont systemFontOfSize:17];
NSAttributedString *attributedText = [[NSAttributedString alloc] initWithString:text attributes:@{NSFontAttributeName: font}];
CGRect rect = [attributedText boundingRectWithSize:(CGSize){width, CGFLOAT_MAX}
                                           options:NSStringDrawingUsesLineFragmentOrigin
                                           context:nil];
CGSize size = rect.size;
size.height = ceilf(size.height);
size.width  = ceilf(size.width);
return size.height + 15;  //Add a little more padding for big thumbs and the detailText label