对于java.util.Date
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd/MM/yyyy")
private Date dateOfBirth;
然后在JSON请求中发送
{ {"dateOfBirth":"01/01/2000"} }
它的工作原理。
我应该如何为Java 8的LocalDate字段这样做??
我试着
@JsonDeserialize(using = LocalDateDeserializer.class)
@JsonSerialize(using = LocalDateSerializer.class)
private LocalDate dateOfBirth;
但是没有成功。
谁能告诉我正确的方法是什么?
下面是依赖关系
<dependency>
<groupId>org.jboss.resteasy</groupId>
<artifactId>jaxrs-api</artifactId>
<version>3.0.9.Final</version>
</dependency>
<dependency>
<groupId>com.fasterxml.jackson.jaxrs</groupId>
<artifactId>jackson-jaxrs-json-provider</artifactId>
<version>2.4.2</version>
</dependency>
<dependency>
<groupId>com.wordnik</groupId>
<artifactId>swagger-annotations</artifactId>
<version>1.3.10</version>
</dependency>
因为LocalDateSerializer默认将其转换为“[年,月,日]”(json数组)而不是“年-月-日”(json字符串),并且因为我不想需要任何特殊的ObjectMapper设置(如果禁用SerializationFeature,您可以使LocalDateSerializer生成字符串)。WRITE_DATES_AS_TIMESTAMPS,但这需要额外的设置到您的ObjectMapper),我使用以下:
进口:
import com.fasterxml.jackson.databind.ser.std.ToStringSerializer;
import com.fasterxml.jackson.datatype.jsr310.deser.LocalDateDeserializer;
代码:
// generates "yyyy-MM-dd" output
@JsonSerialize(using = ToStringSerializer.class)
// handles "yyyy-MM-dd" input just fine (note: "yyyy-M-d" format will not work)
@JsonDeserialize(using = LocalDateDeserializer.class)
private LocalDate localDate;
现在我可以使用new ObjectMapper()来读写我的对象,而不需要任何特殊的设置。
最简单的解决方案(也支持反序列化和序列化)是
import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.databind.annotation.JsonDeserialize;
import com.fasterxml.jackson.databind.annotation.JsonSerialize;
import com.fasterxml.jackson.datatype.jsr310.deser.LocalDateDeserializer;
import com.fasterxml.jackson.datatype.jsr310.ser.LocalDateSerializer;
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd/MM/yyyy")
@JsonDeserialize(using = LocalDateDeserializer.class)
@JsonSerialize(using = LocalDateSerializer.class)
private LocalDate dateOfBirth;
在项目中使用以下依赖项时。
Maven
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>2.9.7</version>
</dependency>
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
<version>2.9.7</version>
</dependency>
Gradle
compile "com.fasterxml.jackson.core:jackson-databind:2.9.7"
compile "com.fasterxml.jackson.datatype:jackson-datatype-jsr310:2.9.7"
不需要额外的ContextResolver、Serializer或Deserializer实现。
https://stackoverflow.com/a/53251526/1282532是序列化/反序列化属性的最简单方法。对于这种方法,我有两个顾虑——在某种程度上违反了DRY原则,以及pojo和mapper之间的高耦合。
public class Trade {
@JsonFormat(pattern = "yyyyMMdd")
@JsonDeserialize(using = LocalDateDeserializer.class)
@JsonSerialize(using = LocalDateSerializer.class)
private LocalDate tradeDate;
@JsonFormat(pattern = "yyyyMMdd")
@JsonDeserialize(using = LocalDateDeserializer.class)
@JsonSerialize(using = LocalDateSerializer.class)
private LocalDate maturityDate;
@JsonFormat(pattern = "yyyyMMdd")
@JsonDeserialize(using = LocalDateDeserializer.class)
@JsonSerialize(using = LocalDateSerializer.class)
private LocalDate entryDate;
}
如果你有多个LocalDate字段的POJO,最好配置映射器而不是POJO。如果您使用的是ISO-8601值("2019-01-31"),可以简单到https://stackoverflow.com/a/35062824/1282532
如果你需要处理自定义格式,代码将是这样的:
ObjectMapper mapper = new ObjectMapper();
JavaTimeModule javaTimeModule = new JavaTimeModule();
javaTimeModule.addDeserializer(LocalDate.class, new LocalDateDeserializer(DateTimeFormatter.ofPattern("yyyyMMdd")));
javaTimeModule.addSerializer(LocalDate.class, new LocalDateSerializer(DateTimeFormatter.ofPattern("yyyyMMdd")));
mapper.registerModule(javaTimeModule);
逻辑只编写一次,它可以用于多个POJO
如果你的请求包含一个这样的对象:
{
"year": 1900,
"month": 1,
"day": 20
}
然后你可以使用:
data class DateObject(
val day: Int,
val month: Int,
val year: Int
)
class LocalDateConverter : StdConverter<DateObject, LocalDate>() {
override fun convert(value: DateObject): LocalDate {
return value.run { LocalDate.of(year, month, day) }
}
}
以上字段:
@JsonDeserialize(converter = LocalDateConverter::class)
val dateOfBirth: LocalDate
代码是在Kotlin中,但这当然也适用于Java。