预期的输入:

getDatesFromRange( '2010-10-01', '2010-10-05' );

预期的输出:

Array( '2010-10-01', '2010-10-02', '2010-10-03', '2010-10-04', '2010-10-05' )

当前回答

<?
print_r(getDatesFromRange( '2010-10-01', '2010-10-05' ));

function getDatesFromRange($startDate, $endDate)
{
    $return = array($startDate);
    $start = $startDate;
    $i=1;
    if (strtotime($startDate) < strtotime($endDate))
    {
       while (strtotime($start) < strtotime($endDate))
        {
            $start = date('Y-m-d', strtotime($startDate.'+'.$i.' days'));
            $return[] = $start;
            $i++;
        }
    }

    return $return;
}

其他回答

下面是一个函数,它将从两个方向返回日期范围,适用于PHP >=5.2.2:

function createRange($start, $end, $format = 'Y-m-d') {
    $start  = new DateTime($start);
    $end    = new DateTime($end);
    $invert = $start > $end;

    $dates = array();
    $dates[] = $start->format($format);
    while ($start != $end) {
        $start->modify(($invert ? '-' : '+') . '1 day');
        $dates[] = $start->format($format);
    }
    return $dates;
}

使用的例子:

print_r(createRange('2010-10-01', '2010-10-05'));
/*Array
(
    [0] => 2010-10-01
    [1] => 2010-10-02
    [2] => 2010-10-03
    [3] => 2010-10-04
    [4] => 2010-10-05
)*/

print_r(createRange('2010-10-05', '2010-10-01', 'j M Y'));
/*Array
(
    [0] => 5 Oct 2010
    [1] => 4 Oct 2010
    [2] => 3 Oct 2010
    [3] => 2 Oct 2010
    [4] => 1 Oct 2010
)*/

demo

这是另一个解决方案。请核对一下。

$first = '10/30/2017'; //starting date
$last= '10/11/2017';   //ending date
$first_time_arr=explode('/',$first); 
$last_time_arr=explode('/',$last);
//create timestamp of starting date
$start_timestamp=mktime(0,0,0, $first_time_arr[0], $first_time_arr[1],$first_time_arr[2]);
//create timestamp of ending date
$end_timestamp=mktime(0,0,0, $last_time_arr[0], $last_time_arr[1],$last_time_arr[2]);
$date_arr=array();
for($i=$start_timestamp;$i<=$end_timestamp;$i=$i+86400){
    $date_arr[]=date("Y-m-d",$i); //this will save all dates in array
}
// will return dates array
function returnBetweenDates( $startDate, $endDate ){
    $startStamp = strtotime(  $startDate );
    $endStamp   = strtotime(  $endDate );

    if( $endStamp > $startStamp ){
        while( $endStamp >= $startStamp ){

            $dateArr[] = date( 'Y-m-d', $startStamp );

            $startStamp = strtotime( ' +1 day ', $startStamp );

        }
        return $dateArr;    
    }else{
        return $startDate;
    }

}

returnBetweenDates( '2014-09-16', '2014-09-26' );

// print_r( returnBetweenDates( '2014-09-16', '2014-09-26' ) );

它将返回如下所示的数组:

Array
(
    [0] => 2014-09-16
    [1] => 2014-09-17
    [2] => 2014-09-18
    [3] => 2014-09-19
    [4] => 2014-09-20
    [5] => 2014-09-21
    [6] => 2014-09-22
    [7] => 2014-09-23
    [8] => 2014-09-24
    [9] => 2014-09-25
    [10] => 2014-09-26
)
public static function countDays($date1,$date2)
{
    $date1 = strtotime($date1); // or your date as well
    $date2 = strtotime($date2);
    $datediff = $date1 - $date2;
    return floor($datediff/(60*60*24));
}

public static function dateRange($date1,$date2)
{
    $count = static::countDays($date1,$date2) + 1;
    $dates = array();
    for($i=0;$i<$count;$i++)
    {
        $dates[] = date("Y-m-d",strtotime($date2.'+'.$i.' days'));
    }
    return $dates;
}

我认为这是最简短的答案

按照您的喜好编辑代码

for ($x=strtotime('2015-12-01');$x<=strtotime('2015-12-30');$x+=86400)
echo date('Y-m-d',$x);