我的iOS应用程序为UINavigationBar使用了自定义高度,这在新的iPhone X上导致了一些问题。

是否有人已经知道如何通过编程(在Objective-C中)可靠地检测应用程序是否在iPhone X上运行?

编辑:

当然,检查屏幕的大小是可能的,但是,我想知道是否有一些“内置”的方法,如TARGET_OS_IPHONE来检测iOS…

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
    CGSize screenSize = [[UIScreen mainScreen] bounds].size;
    if (screenSize.height == 812)
        NSLog(@"iPhone X");
}

编辑2:

我不认为,我的问题是一个重复的关联问题。当然,有一些方法可以“测量”当前设备的不同属性,并使用结果来决定使用哪种设备。然而,这并不是我在第一篇编辑中试图强调的问题的实际意义。

真正的问题是:“是否有可能直接检测当前设备是否是iPhone X(例如通过某些SDK功能),还是我必须使用间接测量?”

根据目前给出的答案,我假设答案是“不,没有直接的方法。测量是要走的路。”


当前回答

我试图使工作之前的答复,他们都没有为我工作。所以我为SwiftUI找到了一个解决方案。创建名为UIDevice+Notch.swift的文件

其内容:

extension UIDevice {
    var hasNotch: Bool {
        let bottom = UIApplication.shared.keyWindow?.safeAreaInsets.bottom ?? 0
        return bottom > 0
    }
}

用法:

if UIDevice.current.hasNotch {
    //... consider notch 
} else {
    //... don't have to consider notch 
}

其他回答

随着iOS 12的发布,像iPhone X这样的设备可能会被归入这一类别。

`

extension UIDevice {
    var isPortrait: Bool {

       return UIDeviceOrientationIsPortrait(orientation) ||
      UIInterfaceOrientationIsPortrait(UIApplication.shared.statusBarOrientation)

  }

   var isDeviceWith_XShape : Bool {

    if self.userInterfaceIdiom == .phone {

        if isPortrait
        {
            switch UIScreen.main.nativeBounds.height {

            case 2436,2688,1792:
                print("iPhone X, Xs, Xr, Xs Max")
                return true
            default:
                print("Any other device")
                return false
            }
        }
        else
        {
            switch UIScreen.main.nativeBounds.width {

            case 2436,2688,1792:
                print("iPhone X, Xs, Xr, Xs Max")
                return true
            default:
                print("Any other device")
                return false
            }
        }


    }
    else
    {
        return false
    }

}`

我试图使工作之前的答复,他们都没有为我工作。所以我为SwiftUI找到了一个解决方案。创建名为UIDevice+Notch.swift的文件

其内容:

extension UIDevice {
    var hasNotch: Bool {
        let bottom = UIApplication.shared.keyWindow?.safeAreaInsets.bottom ?? 0
        return bottom > 0
    }
}

用法:

if UIDevice.current.hasNotch {
    //... consider notch 
} else {
    //... don't have to consider notch 
}

仅在竖屏中,我使用视图框架的宽度和高度来检查:

override func viewDidLoad() {
    super.viewDidLoad()

    // iPhone Xr: -414 x 896
    // iPhone Xs Max: -414 x 896
    // iPhone X, Xs: -375 x 812

    if view.frame.width == 414 && view.frame.height == 896 || view.frame.width == 375 && view.frame.height == 812  {

        print("iPhone X")
    } else {

        print("not iPhone X")
    }

}

竖屏尺寸列在这里

更新

这个答案已经过时了,现在iPhone阵容中有更多的X系列,你要么必须在if-else中列出所有这些尺寸,要么检查设备是否有缺口会更容易。大约1.5年前,我从某个地方得到了这个答案/代码。如果我能链接到代码,我会的。

// 1. add an extension to UIDevice with this computed property
extension UIDevice {
    
    var hasTopNotch: Bool {
        if #available(iOS 11.0, tvOS 11.0, *) {
            return UIApplication.shared.delegate?.window??.safeAreaInsets.top ?? 0 > 20
        }
        return false
    }
} 

// 2. to use in any class
override func viewDidLoad() {
    super.viewDidLoad()

    if UIDevice.current.hasTopNotch {

        print("X series")

    } else {

        print("regular phone")
    }
}

我正在使用Peter Kreinz的代码(因为它是干净的,做了我需要的),但后来我意识到它只在设备是纵向的时候工作(因为顶部填充将在顶部,显然) 所以我创建了一个扩展来处理所有的方向与它各自的填充,而不依赖于屏幕大小:

extension UIDevice {

    var isIphoneX: Bool {
        if #available(iOS 11.0, *), isIphone {
            if isLandscape {
                if let leftPadding = UIApplication.shared.keyWindow?.safeAreaInsets.left, leftPadding > 0 {
                    return true
                }
                if let rightPadding = UIApplication.shared.keyWindow?.safeAreaInsets.right, rightPadding > 0 {
                    return true
                }
            } else {
                if let topPadding = UIApplication.shared.keyWindow?.safeAreaInsets.top, topPadding > 0 {
                    return true
                }
                if let bottomPadding = UIApplication.shared.keyWindow?.safeAreaInsets.bottom, bottomPadding > 0 {
                    return true
                }
            }
        }
        return false
    }

    var isLandscape: Bool {
        return UIDeviceOrientationIsLandscape(orientation) || UIInterfaceOrientationIsLandscape(UIApplication.shared.statusBarOrientation)
    }

    var isPortrait: Bool {
        return UIDeviceOrientationIsPortrait(orientation) || UIInterfaceOrientationIsPortrait(UIApplication.shared.statusBarOrientation)
    }

    var isIphone: Bool {
        return self.userInterfaceIdiom == .phone
    }

    var isIpad: Bool {
        return self.userInterfaceIdiom == .pad
    }
}

在你的电话网站上

let res = UIDevice.current.isIphoneX
struct ScreenSize {
    static let width = UIScreen.main.bounds.size.width
    static let height = UIScreen.main.bounds.size.height
    static let maxLength = max(ScreenSize.width, ScreenSize.height)
    static let minLength = min(ScreenSize.width, ScreenSize.height)
    static let frame = CGRect(x: 0, y: 0, width: ScreenSize.width, height: ScreenSize.height)
}

struct DeviceType {
    static let iPhone4orLess = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.maxLength < 568.0
    static let iPhone5orSE = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.maxLength == 568.0
    static let iPhone678 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.maxLength == 667.0
    static let iPhone678p = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.maxLength == 736.0
    static let iPhoneX = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.maxLength == 812.0

    static let IS_IPAD              = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.maxLength == 1024.0
    static let IS_IPAD_PRO          = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.maxLength == 1366.0
}