Django可以很好地自动序列化从DB返回到JSON格式的ORM模型。

如何序列化SQLAlchemy查询结果为JSON格式?

我试过jsonpickle。编码,但它编码查询对象本身。 我尝试了json.dumps(items),但它返回

TypeError: <Product('3', 'some name', 'some desc')> is not JSON serializable

将SQLAlchemy ORM对象序列化为JSON /XML真的那么难吗?它没有任何默认序列化器吗?现在序列化ORM查询结果是非常常见的任务。

我所需要的只是返回SQLAlchemy查询结果的JSON或XML数据表示。

需要在javascript datagird中使用JSON/XML格式的SQLAlchemy对象查询结果(JQGrid http://www.trirand.com/blog/)


当前回答

Python 3.7+和Flask 1.1+可以使用内置的数据类包

from dataclasses import dataclass
from datetime import datetime
from flask import Flask, jsonify
from flask_sqlalchemy import SQLAlchemy


app = Flask(__name__)
db = SQLAlchemy(app)


@dataclass
class User(db.Model):
  id: int
  email: str

  id = db.Column(db.Integer, primary_key=True, auto_increment=True)
  email = db.Column(db.String(200), unique=True)


@app.route('/users/')
def users():
  users = User.query.all()
  return jsonify(users)  


if __name__ == "__main__":
  users = User(email="user1@gmail.com"), User(email="user2@gmail.com")
  db.create_all()
  db.session.add_all(users)
  db.session.commit()
  app.run()

/users/路由现在将返回一个用户列表。

[
  {"email": "user1@gmail.com", "id": 1},
  {"email": "user2@gmail.com", "id": 2}
]

自动序列化相关模型

@dataclass
class Account(db.Model):
  id: int
  users: User

  id = db.Column(db.Integer)
  users = db.relationship(User)  # User model would need a db.ForeignKey field

jsonify(account)的响应是这样的。

{  
   "id":1,
   "users":[  
      {  
         "email":"user1@gmail.com",
         "id":1
      },
      {  
         "email":"user2@gmail.com",
         "id":2
      }
   ]
}

覆盖默认的JSON编码器

from flask.json import JSONEncoder


class CustomJSONEncoder(JSONEncoder):
  "Add support for serializing timedeltas"

  def default(o):
    if type(o) == datetime.timedelta:
      return str(o)
    if type(o) == datetime.datetime:
      return o.isoformat()
    return super().default(o)

app.json_encoder = CustomJSONEncoder      

其他回答

安装simplejson by PIP安装simplejson并创建一个类

class Serialise(object):

    def _asdict(self):
        """
        Serialization logic for converting entities using flask's jsonify

        :return: An ordered dictionary
        :rtype: :class:`collections.OrderedDict`
        """

        result = OrderedDict()
        # Get the columns
        for key in self.__mapper__.c.keys():
            if isinstance(getattr(self, key), datetime):
                result["x"] = getattr(self, key).timestamp() * 1000
                result["timestamp"] = result["x"]
            else:
                result[key] = getattr(self, key)

        return result

并将这个类继承到每个orm类,这样这个_asdict函数就会注册到每个orm类,然后。 并在任何地方使用jsonify

Python 3.7+和Flask 1.1+可以使用内置的数据类包

from dataclasses import dataclass
from datetime import datetime
from flask import Flask, jsonify
from flask_sqlalchemy import SQLAlchemy


app = Flask(__name__)
db = SQLAlchemy(app)


@dataclass
class User(db.Model):
  id: int
  email: str

  id = db.Column(db.Integer, primary_key=True, auto_increment=True)
  email = db.Column(db.String(200), unique=True)


@app.route('/users/')
def users():
  users = User.query.all()
  return jsonify(users)  


if __name__ == "__main__":
  users = User(email="user1@gmail.com"), User(email="user2@gmail.com")
  db.create_all()
  db.session.add_all(users)
  db.session.commit()
  app.run()

/users/路由现在将返回一个用户列表。

[
  {"email": "user1@gmail.com", "id": 1},
  {"email": "user2@gmail.com", "id": 2}
]

自动序列化相关模型

@dataclass
class Account(db.Model):
  id: int
  users: User

  id = db.Column(db.Integer)
  users = db.relationship(User)  # User model would need a db.ForeignKey field

jsonify(account)的响应是这样的。

{  
   "id":1,
   "users":[  
      {  
         "email":"user1@gmail.com",
         "id":1
      },
      {  
         "email":"user2@gmail.com",
         "id":2
      }
   ]
}

覆盖默认的JSON编码器

from flask.json import JSONEncoder


class CustomJSONEncoder(JSONEncoder):
  "Add support for serializing timedeltas"

  def default(o):
    if type(o) == datetime.timedelta:
      return str(o)
    if type(o) == datetime.datetime:
      return o.isoformat()
    return super().default(o)

app.json_encoder = CustomJSONEncoder      

我对使用(太多?)字典的看法:

def serialize(_query):
    #d = dictionary written to per row
    #D = dictionary d is written to each time, then reset
    #Master = dictionary of dictionaries; the id Key (int, unique from database) 
    from D is used as the Key for the dictionary D entry in Master
    Master = {}
    D = {}
    x = 0
    for u in _query:
        d = u.__dict__
        D = {}
        for n in d.keys():
           if n != '_sa_instance_state':
                    D[n] = d[n]
        x = d['id']
        Master[x] = D
    return Master

使用flask(包括jsonify)和flask_sqlalchemy将输出打印为JSON。

使用jsonify(serialize())调用该函数。

与我迄今为止尝试过的所有SQLAlchemy查询一起工作(运行SQLite3)

你可以像这样将RowProxy转换为dict:

 d = dict(row.items())

然后将其序列化为JSON(必须为datetime值等指定编码器) 如果您只想要一条记录(而不是相关记录的完整层次结构),这并不难。

json.dumps([(dict(row.items())) for row in rs])

如果你正在使用Flask并且只想快速查询:

def get_cats():
    sql = text("select * from cat")
    sql_params = {}
    result = db.session.execute(sql, sql_params)
    row_list = result.fetchall()
    data = [dict(r) for r in row_list]

    response = jsonify({
        'data': [{
            'categorias': data
        }]
    })
    
    return response