Django可以很好地自动序列化从DB返回到JSON格式的ORM模型。

如何序列化SQLAlchemy查询结果为JSON格式?

我试过jsonpickle。编码,但它编码查询对象本身。 我尝试了json.dumps(items),但它返回

TypeError: <Product('3', 'some name', 'some desc')> is not JSON serializable

将SQLAlchemy ORM对象序列化为JSON /XML真的那么难吗?它没有任何默认序列化器吗?现在序列化ORM查询结果是非常常见的任务。

我所需要的只是返回SQLAlchemy查询结果的JSON或XML数据表示。

需要在javascript datagird中使用JSON/XML格式的SQLAlchemy对象查询结果(JQGrid http://www.trirand.com/blog/)


当前回答

这是一个JSONEncoder版本,它保留了模型列的顺序,只保留递归定义的列和关系字段。它还格式化了大多数不可序列化的JSON类型:

import json
from datetime import datetime
from decimal import Decimal

import arrow
from sqlalchemy.ext.declarative import DeclarativeMeta

class SQLAlchemyJSONEncoder(json.JSONEncoder):
    """
    SQLAlchemy ORM JSON Encoder
    If you have a "backref" relationship defined in your SQLAlchemy model,
    this encoder raises a ValueError to stop an infinite loop.
    """

    def default(self, obj):
        if isinstance(obj, datetime):
            return arrow.get(obj).isoformat()
        elif isinstance(obj, Decimal):
            return float(obj)
        elif isinstance(obj, set):
            return sorted(obj)
        elif isinstance(obj.__class__, DeclarativeMeta):
            for attribute, relationship in obj.__mapper__.relationships.items():
                if isinstance(relationship.__getattribute__("backref"), tuple):
                    raise ValueError(
                        f'{obj.__class__} object has a "backref" relationship '
                        "that would cause an infinite loop!"
                    )
            dictionary = {}
            column_names = [column.name for column in obj.__table__.columns]
            for key in column_names:
                value = obj.__getattribute__(key)
                if isinstance(value, datetime):
                    value = arrow.get(value).isoformat()
                elif isinstance(value, Decimal):
                    value = float(value)
                elif isinstance(value, set):
                    value = sorted(value)
                dictionary[key] = value
            for key in [
                attribute
                for attribute in dir(obj)
                if not attribute.startswith("_")
                and attribute != "metadata"
                and attribute not in column_names
            ]:
                value = obj.__getattribute__(key)
                dictionary[key] = value
            return dictionary

        return super().default(obj)

其他回答

你可以把你的对象输出为一个字典:

class User:
   def as_dict(self):
       return {c.name: getattr(self, c.name) for c in self.__table__.columns}

然后使用User.as_dict()序列化对象。

如将sqlalchemy行对象转换为python dict中所述

虽然使用一些原始sql和未定义的对象,使用cursor.description似乎得到了我正在寻找的东西:

with connection.cursor() as cur:
    print(query)
    cur.execute(query)
    for item in cur.fetchall():
        row = {column.name: item[i] for i, column in enumerate(cur.description)}
        print(row)

自定义序列化和反序列化。

"from_json"(类方法)基于json数据构建一个Model对象。

“反序列化”只能在实例上调用,并将json中的所有数据合并到Model实例中。

"serialize" -递归序列化

需要__write_only__属性来定义只写属性(例如“password_hash”)。

class Serializable(object):
    __exclude__ = ('id',)
    __include__ = ()
    __write_only__ = ()

    @classmethod
    def from_json(cls, json, selfObj=None):
        if selfObj is None:
            self = cls()
        else:
            self = selfObj
        exclude = (cls.__exclude__ or ()) + Serializable.__exclude__
        include = cls.__include__ or ()
        if json:
            for prop, value in json.iteritems():
                # ignore all non user data, e.g. only
                if (not (prop in exclude) | (prop in include)) and isinstance(
                        getattr(cls, prop, None), QueryableAttribute):
                    setattr(self, prop, value)
        return self

    def deserialize(self, json):
        if not json:
            return None
        return self.__class__.from_json(json, selfObj=self)

    @classmethod
    def serialize_list(cls, object_list=[]):
        output = []
        for li in object_list:
            if isinstance(li, Serializable):
                output.append(li.serialize())
            else:
                output.append(li)
        return output

    def serialize(self, **kwargs):

        # init write only props
        if len(getattr(self.__class__, '__write_only__', ())) == 0:
            self.__class__.__write_only__ = ()
        dictionary = {}
        expand = kwargs.get('expand', ()) or ()
        prop = 'props'
        if expand:
            # expand all the fields
            for key in expand:
                getattr(self, key)
        iterable = self.__dict__.items()
        is_custom_property_set = False
        # include only properties passed as parameter
        if (prop in kwargs) and (kwargs.get(prop, None) is not None):
            is_custom_property_set = True
            iterable = kwargs.get(prop, None)
        # loop trough all accessible properties
        for key in iterable:
            accessor = key
            if isinstance(key, tuple):
                accessor = key[0]
            if not (accessor in self.__class__.__write_only__) and not accessor.startswith('_'):
                # force select from db to be able get relationships
                if is_custom_property_set:
                    getattr(self, accessor, None)
                if isinstance(self.__dict__.get(accessor), list):
                    dictionary[accessor] = self.__class__.serialize_list(object_list=self.__dict__.get(accessor))
                # check if those properties are read only
                elif isinstance(self.__dict__.get(accessor), Serializable):
                    dictionary[accessor] = self.__dict__.get(accessor).serialize()
                else:
                    dictionary[accessor] = self.__dict__.get(accessor)
        return dictionary

扁平化实现

你可以使用这样的代码:

from sqlalchemy.ext.declarative import DeclarativeMeta

class AlchemyEncoder(json.JSONEncoder):

    def default(self, obj):
        if isinstance(obj.__class__, DeclarativeMeta):
            # an SQLAlchemy class
            fields = {}
            for field in [x for x in dir(obj) if not x.startswith('_') and x != 'metadata']:
                data = obj.__getattribute__(field)
                try:
                    json.dumps(data) # this will fail on non-encodable values, like other classes
                    fields[field] = data
                except TypeError:
                    fields[field] = None
            # a json-encodable dict
            return fields

        return json.JSONEncoder.default(self, obj)

然后转换为JSON使用:

c = YourAlchemyClass()
print json.dumps(c, cls=AlchemyEncoder)

它将忽略不可编码的字段(将它们设置为“None”)。

它不会自动展开关系(因为这可能导致自引用,并永远循环)。

递归的非循环实现

然而,如果你宁愿永远循环,你可以使用:

from sqlalchemy.ext.declarative import DeclarativeMeta

def new_alchemy_encoder():
    _visited_objs = []

    class AlchemyEncoder(json.JSONEncoder):
        def default(self, obj):
            if isinstance(obj.__class__, DeclarativeMeta):
                # don't re-visit self
                if obj in _visited_objs:
                    return None
                _visited_objs.append(obj)

                # an SQLAlchemy class
                fields = {}
                for field in [x for x in dir(obj) if not x.startswith('_') and x != 'metadata']:
                    fields[field] = obj.__getattribute__(field)
                # a json-encodable dict
                return fields

            return json.JSONEncoder.default(self, obj)

    return AlchemyEncoder

然后对对象进行编码,使用:

print json.dumps(e, cls=new_alchemy_encoder(), check_circular=False)

这将编码所有的子代、子代、子代……基本上可以编码你的整个数据库。当它到达之前编码过的东西时,它会将其编码为“None”。

递归的、可能是循环的、有选择的实现

另一种选择,可能更好,是能够指定你想要展开的字段:

def new_alchemy_encoder(revisit_self = False, fields_to_expand = []):
    _visited_objs = []

    class AlchemyEncoder(json.JSONEncoder):
        def default(self, obj):
            if isinstance(obj.__class__, DeclarativeMeta):
                # don't re-visit self
                if revisit_self:
                    if obj in _visited_objs:
                        return None
                    _visited_objs.append(obj)

                # go through each field in this SQLalchemy class
                fields = {}
                for field in [x for x in dir(obj) if not x.startswith('_') and x != 'metadata']:
                    val = obj.__getattribute__(field)

                    # is this field another SQLalchemy object, or a list of SQLalchemy objects?
                    if isinstance(val.__class__, DeclarativeMeta) or (isinstance(val, list) and len(val) > 0 and isinstance(val[0].__class__, DeclarativeMeta)):
                        # unless we're expanding this field, stop here
                        if field not in fields_to_expand:
                            # not expanding this field: set it to None and continue
                            fields[field] = None
                            continue

                    fields[field] = val
                # a json-encodable dict
                return fields

            return json.JSONEncoder.default(self, obj)

    return AlchemyEncoder

你现在可以调用它:

print json.dumps(e, cls=new_alchemy_encoder(False, ['parents']), check_circular=False)

例如,仅展开名为“parents”的SQLAlchemy字段。

更详细的解释。 在你的模型中,添加:

def as_dict(self):
       return {c.name: str(getattr(self, c.name)) for c in self.__table__.columns}

str()是针对python3的,所以如果使用python2则使用unicode()。它应该有助于反序列化日期。如果不处理这些,你可以删除它。

现在可以像这样查询数据库

some_result = User.query.filter_by(id=current_user.id).first().as_dict()

需要First()来避免奇怪的错误。As_dict()现在将反序列化结果。反序列化之后,就可以将其转换为json了

jsonify(some_result)