我试图在脚本中从谷歌驱动器下载一个文件,我这样做有点麻烦。我要下载的文件在这里。
我在网上搜了很多,终于下载了其中一个。我得到了文件的uid,较小的文件(1.6MB)下载正常,但较大的文件(3.7GB)总是重定向到一个页面,询问我是否想在不进行病毒扫描的情况下继续下载。谁能帮我跳过那个屏幕?
下面是我如何让第一个文件工作-
curl -L "https://docs.google.com/uc?export=download&id=0Bz-w5tutuZIYeDU0VDRFWG9IVUE" > phlat-1.0.tar.gz
当我对另一个文件进行同样操作时,
curl -L "https://docs.google.com/uc?export=download&id=0Bz-w5tutuZIYY3h5YlMzTjhnbGM" > index4phlat.tar.gz
我得到以下输出-
我注意到在链接的第三行到最后一行,有一个&confirm=JwkK,这是一个随机的4个字符的字符串,但建议有一种方法添加到我的URL确认。我访问的一个链接建议&confirm=no_antivirus,但这不起作用。
我希望这里有人能帮忙!
下面是我写的一个小bash脚本,它今天完成了这项工作。它适用于大文件,也可以恢复部分获取的文件。它有两个参数,第一个是file_id,第二个是输出文件的名称。与之前的答案相比,主要的改进是它可以在大文件上工作,只需要常用的工具:bash, curl, tr, grep, du, cut和mv。
#!/usr/bin/env bash
fileid="$1"
destination="$2"
# try to download the file
curl -c /tmp/cookie -L -o /tmp/probe.bin "https://drive.google.com/uc?export=download&id=${fileid}"
probeSize=`du -b /tmp/probe.bin | cut -f1`
# did we get a virus message?
# this will be the first line we get when trying to retrive a large file
bigFileSig='<!DOCTYPE html><html><head><title>Google Drive - Virus scan warning</title><meta http-equiv="content-type" content="text/html; charset=utf-8"/>'
sigSize=${#bigFileSig}
if (( probeSize <= sigSize )); then
virusMessage=false
else
firstBytes=$(head -c $sigSize /tmp/probe.bin)
if [ "$firstBytes" = "$bigFileSig" ]; then
virusMessage=true
else
virusMessage=false
fi
fi
if [ "$virusMessage" = true ] ; then
confirm=$(tr ';' '\n' </tmp/probe.bin | grep confirm)
confirm=${confirm:8:4}
curl -C - -b /tmp/cookie -L -o "$destination" "https://drive.google.com/uc?export=download&id=${fileid}&confirm=${confirm}"
else
mv /tmp/probe.bin "$destination"
fi
我写了一个从谷歌驱动器下载文件的Python代码片段,给出了一个可共享的链接。截至2017年8月,它是有效的。
剪切不使用gdrive,也没有谷歌驱动器API。它使用请求模块。
当从谷歌驱动器下载大文件时,单个GET请求是不够的。需要第二个URL,这个URL有一个额外的URL参数confirm,它的值应该等于某个cookie的值。
import requests
def download_file_from_google_drive(id, destination):
def get_confirm_token(response):
for key, value in response.cookies.items():
if key.startswith('download_warning'):
return value
return None
def save_response_content(response, destination):
CHUNK_SIZE = 32768
with open(destination, "wb") as f:
for chunk in response.iter_content(CHUNK_SIZE):
if chunk: # filter out keep-alive new chunks
f.write(chunk)
URL = "https://docs.google.com/uc?export=download"
session = requests.Session()
response = session.get(URL, params = { 'id' : id }, stream = True)
token = get_confirm_token(response)
if token:
params = { 'id' : id, 'confirm' : token }
response = session.get(URL, params = params, stream = True)
save_response_content(response, destination)
if __name__ == "__main__":
import sys
if len(sys.argv) is not 3:
print("Usage: python google_drive.py drive_file_id destination_file_path")
else:
# TAKE ID FROM SHAREABLE LINK
file_id = sys.argv[1]
# DESTINATION FILE ON YOUR DISK
destination = sys.argv[2]
download_file_from_google_drive(file_id, destination)
我无法让Nanoix的perl脚本工作,或者我看到的其他curl示例,所以我开始自己用python研究api。这适用于小文件,但大文件阻塞了可用的ram,所以我找到了一些其他不错的分块代码,使用api的部分下载功能。要点:
https://gist.github.com/csik/c4c90987224150e4a0b2
注意从API接口下载client_secret json文件到本地目录的部分。
源
$ cat gdrive_dl.py
from pydrive.auth import GoogleAuth
from pydrive.drive import GoogleDrive
"""API calls to download a very large google drive file. The drive API only allows downloading to ram
(unlike, say, the Requests library's streaming option) so the files has to be partially downloaded
and chunked. Authentication requires a google api key, and a local download of client_secrets.json
Thanks to Radek for the key functions: http://stackoverflow.com/questions/27617258/memoryerror-how-to-download-large-file-via-google-drive-sdk-using-python
"""
def partial(total_byte_len, part_size_limit):
s = []
for p in range(0, total_byte_len, part_size_limit):
last = min(total_byte_len - 1, p + part_size_limit - 1)
s.append([p, last])
return s
def GD_download_file(service, file_id):
drive_file = service.files().get(fileId=file_id).execute()
download_url = drive_file.get('downloadUrl')
total_size = int(drive_file.get('fileSize'))
s = partial(total_size, 100000000) # I'm downloading BIG files, so 100M chunk size is fine for me
title = drive_file.get('title')
originalFilename = drive_file.get('originalFilename')
filename = './' + originalFilename
if download_url:
with open(filename, 'wb') as file:
print "Bytes downloaded: "
for bytes in s:
headers = {"Range" : 'bytes=%s-%s' % (bytes[0], bytes[1])}
resp, content = service._http.request(download_url, headers=headers)
if resp.status == 206 :
file.write(content)
file.flush()
else:
print 'An error occurred: %s' % resp
return None
print str(bytes[1])+"..."
return title, filename
else:
return None
gauth = GoogleAuth()
gauth.CommandLineAuth() #requires cut and paste from a browser
FILE_ID = 'SOMEID' #FileID is the simple file hash, like 0B1NzlxZ5RpdKS0NOS0x0Ym9kR0U
drive = GoogleDrive(gauth)
service = gauth.service
#file = drive.CreateFile({'id':FILE_ID}) # Use this to get file metadata
GD_download_file(service, FILE_ID)
我一直在使用@Amit Chahar的curl片段,他在这个帖子中给出了一个很好的答案。我发现它很有用
将其放在bash函数中,而不是单独的.sh文件中
function curl_gdrive {
GDRIVE_FILE_ID=$1
DEST_PATH=$2
curl -c ./cookie -s -L "https://drive.google.com/uc?export=download&id=${GDRIVE_FILE_ID}" > /dev/null
curl -Lb ./cookie "https://drive.google.com/uc?export=download&confirm=`awk '/download/ {print $NF}' ./cookie`&id=${GDRIVE_FILE_ID}" -o ${DEST_PATH}
rm -f cookie
}
可以包含在例如a ~/。Bashrc(当然,如果不是自动源),并以以下方式使用
$ curl_gdrive 153bpzybhfqDspyO_gdbcG5CMlI19ASba imagenet.tar
UPDATE 2022-03-01 - wget版本,当病毒扫描被触发时也可以工作
function wget_gdrive {
GDRIVE_FILE_ID=$1
DEST_PATH=$2
wget --save-cookies cookies.txt 'https://docs.google.com/uc?export=download&id='$GDRIVE_FILE_ID -O- | sed -rn 's/.*confirm=([0-9A-Za-z_]+).*/\1/p' > confirm.txt
wget --load-cookies cookies.txt -O $DEST_PATH 'https://docs.google.com/uc?export=download&id='$GDRIVE_FILE_ID'&confirm='$(<confirm.txt)
rm -fr cookies.txt confirm.txt
}
示例用法:
$ wget_gdrive 1gzp8zIDo888AwMXRTZ4uzKCMiwKynHYP foo.out