例如，在输入框中给定两个日期:
<input id="first" value="1/1/2000"/>
<input id="second" value="1/1/2001"/>
<script>
alert(datediff("day", first, second)); // what goes here?
</script>
如何在JavaScript中获得两个日期之间的天数?
当前回答
简单、容易、复杂。此函数将每1秒调用一次以更新时间。
const year = (new Date().getFullYear());
const bdayDate = new Date("04,11,2019").getTime(); //mmddyyyy
// countdown
let timer = setInterval(function () {
// get today's date
const today = new Date().getTime();
// get the difference
const diff = bdayDate - today;
// math
let days = Math.floor(diff / (1000 * 60 * 60 * 24));
let hours = Math.floor((diff % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
let minutes = Math.floor((diff % (1000 * 60 * 60)) / (1000 * 60));
let seconds = Math.floor((diff % (1000 * 60)) / 1000);
}, 1000);
其他回答
我只有两个以毫秒为单位的时间戳，所以我必须用moment.js做一些额外的步骤来获得天数。
const getDaysDiff = (fromTimestamp, toTimestamp) => {
// set timezone offset with utcOffset if needed
let fromDate = moment(fromTimestamp).utcOffset(8);
let toDate = moment(toTimestamp).utcOffset(8);
// get the start moment of the day
fromDate.set({'hour':0, 'minute': 0, 'second': 0, 'millisecond': 0});
toDate.set({'hour':0, 'minute': 0, 'second': 0, 'millisecond': 0});
let diffDays = toDate.diff(fromDate, 'days');
return diffDays;
}
getDaysDiff(1528889400000, 1528944180000)// 1
1970-01-01之前和2038-01-19之后的贡献
function DateDiff(aDate1, aDate2) {
let dDay = 0;
this.isBissexto = (aYear) => {
return (aYear % 4 == 0 && aYear % 100 != 0) || (aYear % 400 == 0);
};
this.getDayOfYear = (aDate) => {
let count = 0;
for (let m = 0; m < aDate.getUTCMonth(); m++) {
count += m == 1 ? this.isBissexto(aDate.getUTCFullYear()) ? 29 : 28 : /(3|5|8|10)/.test(m) ? 30 : 31;
}
count += aDate.getUTCDate();
return count;
};
this.toDays = () => {
return dDay;
};
(() => {
let startDate = aDate1.getTime() <= aDate2.getTime() ? new Date(aDate1.toISOString()) : new Date(aDate2.toISOString());
let endDate = aDate1.getTime() <= aDate2.getTime() ? new Date(aDate2.toISOString()) : new Date(aDate1.toISOString());
while (startDate.getUTCFullYear() != endDate.getUTCFullYear()) {
dDay += (this.isBissexto(startDate.getFullYear())? 366 : 365) - this.getDayOfYear(startDate) + 1;
startDate = new Date(startDate.getUTCFullYear()+1, 0, 1);
}
dDay += this.getDayOfYear(endDate) - this.getDayOfYear(startDate);
})();
}
简单、容易、复杂。此函数将每1秒调用一次以更新时间。
const year = (new Date().getFullYear());
const bdayDate = new Date("04,11,2019").getTime(); //mmddyyyy
// countdown
let timer = setInterval(function () {
// get today's date
const today = new Date().getTime();
// get the difference
const diff = bdayDate - today;
// math
let days = Math.floor(diff / (1000 * 60 * 60 * 24));
let hours = Math.floor((diff % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
let minutes = Math.floor((diff % (1000 * 60 * 60)) / (1000 * 60));
let seconds = Math.floor((diff % (1000 * 60)) / 1000);
}, 1000);
// JavaScript / NodeJs answer
let startDate = new Date("2022-09-19");
let endDate = new Date("2022-09-26");
let difference = startDate.getTime() - endDate.getTime();
console.log(difference);
let TotalDiffDays = Math.ceil(difference / (1000 * 3600 * 24));
console.log(TotalDiffDays + " days :) ");
如果你想有一个DateArray日期试试这个:
<script>
function getDates(startDate, stopDate) {
var dateArray = new Array();
var currentDate = moment(startDate);
dateArray.push( moment(currentDate).format('L'));
var stopDate = moment(stopDate);
while (dateArray[dateArray.length -1] != stopDate._i) {
dateArray.push( moment(currentDate).format('L'));
currentDate = moment(currentDate).add(1, 'days');
}
return dateArray;
}
</script>
调试片段
