我需要以毫秒为单位获取执行时间。

我最初问这个问题是在2008年。当时接受的答案是使用newDate().getTime()。然而,我们现在都可以同意使用标准performance.now()API更合适。因此,我将接受的答案改为这个答案。


当前回答

使用performance.now():

var startTime = performance.now()

doSomething()   // <---- measured code goes between startTime and endTime
    
var endTime = performance.now()

console.log(`Call to doSomething took ${endTime - startTime} milliseconds`)

在Node.js中,需要导入性能类

进口性能

const { performance } = require('perf_hooks');

使用console.time:(生活水平)

console.time('doSomething')
    
doSomething()   // <---- The function you're measuring time for 
    
console.timeEnd('doSomething')

注意:传递给time()和timeEnd()方法的字符串必须匹配(计时器才能按预期完成)。

console.time()文档:MDN文档Node.js文档

其他回答

支持标记的基本TypeScript示例。调用start(“something”)将启动计时器,而stop(“somehing”)将结束计时器,并返回包含已用时间的格式化字符串。

查看车队示例

/**
 * Mark entries
 */
export const marks: { [id: string]: number } = {};

/**
 * Start timing 
 */
export const start = (id: string) => {
  return Object.assign(marks, {[id]: Date.now() })[id]
}

/**
 * Clear all 
 */
export const clear = () => {
  for (const id in marks) delete marks[id]; 
};

/**
 * Stop timing and return formatted elapsed time
 */
export const stop = (id: string) => {
  const ms = Date.now() - marks[id];
  delete marks[id];
  return ms > 1000 
    ? `${(ms / 1000).toFixed(0)}s ${+ms.toFixed(0).slice(1)}ms` 
    : `${ms.toFixed(0)}ms`;
};

示例代码是导出每个函数。您可以将其放置到项目中,并从默认的import调用相应的方法,例如:

import * as time from './timer.js'

time.start('foo')

// do something

console.log('elapsed time: ' + time.stop('bar'))

在函数之前使用console.time(“此处的某个标签”),在函数之后使用console.timeEnd(“此处某个标签)。它将为您提供函数的运行时间。

具有性能

NodeJs:需要导入性能类

var time0 = performance.now(); // Store the time at this point into time0

yourFunction();   // The function you're measuring time for 

var time1 = performance.now(); // Store the time at this point into time1

console.log("youFunction took " + (time1 - time0) + " milliseconds to execute");

使用console.time

console.time('someFunction');

someFunction(); // Whatever is timed goes between the two "console.time"

console.timeEnd('someFunction');

在我的例子中,我更喜欢使用@grammar suger并用babel编译它。这种方法的问题是函数必须位于对象内部。

JS代码示例

function timer() {
    return (target, propertyKey, descriptor) => {
        const start = Date.now();
        let oldFunc = descriptor.value;

        descriptor.value = async function (){
            var result = await oldFunc.apply(this, arguments);
            console.log(Date.now() - start);
            return result;
        }
    }
}

// Util function 
function delay(timeout) {
    return new Promise((resolve) => setTimeout(() => {
        resolve();
    }, timeout));
}

class Test {
    @timer()
    async test(timout) {
        await delay(timout)
        console.log("delay 1");
        await delay(timout)
        console.log("delay 2");
    }
}

const t = new Test();
t.test(1000)
t.test(100)

babelrc(用于babel 6)

 {
    "plugins": [
        "transform-decorators-legacy"
    ]
 }

它可能会帮助你。

var t0=date.now();做某事();var t1=date.now();console.log(“调用doSomething花费了大约”+(t1-t0)/1000+“秒”)