我如何在每一条匹配的线周围显示前面和后面的5条线?


当前回答

使用grep

$ grep --help | grep -i context
Context control:
  -B, --before-context=NUM  print NUM lines of leading context
  -A, --after-context=NUM   print NUM lines of trailing context
  -C, --context=NUM         print NUM lines of output context
  -NUM                      same as --context=NUM

其他回答

我通常使用

grep searchstring file -C n # n for number of lines of context up and down

许多像grep这样的工具也有很棒的man文件。我发现自己经常参考grep的手册页,因为你可以用它做很多事情。

man grep

许多GNU工具也有一个信息页,除了手册页之外,它可能还有更多有用的信息。

info grep
$ grep thestring thefile -5

-5会让你在匹配项上下各5行,“thestring”相当于-C 5或-A 5-B 5。

里普雷普

如果您关心性能,请使用与grep语法相似的ripgrep,例如。

rg -C5 "pattern" .

-C、 --context NUM—在每次匹配前后显示NUM行。

还有一些参数,如-A/-after上下文和-B/-before上下文。

该工具构建在Rust的正则表达式引擎之上,这使得它对大数据非常有效。

grep astring myfile -A 5 -B 5

这将grep“myfile”表示“跨步”,并在每次比赛前后显示5行

让我们用一个例子来理解。我们可以使用带有选项的grep:

-A 5  # this will give you 5 lines after searched string.
-B 5  # this will give you 5 lines before searched string.
-C 5  # this will give you 5 lines before & after searched string

实例File.txt包含6行,以下是操作。

[abc@xyz]~/% cat file.txt # print all file data
this is first line
this is 2nd line
this is 3rd line
this is 4th line
this is 5th line
this is 6th line

[abc@xyz]~% grep "3rd" file.txt # we are searching for keyword '3rd' in the file
this is 3rd line

[abc@xyz]~% grep -A 2 "3rd" file.txt # print 2 lines after finding the searched string
this is 3rd line
this is 4th line
this is 5th line

[abc@xyz]~% grep -B 2 "3rd" file.txt # Print 2 lines before the search string.
this is first line
this is 2nd line
this is 3rd line

[abc@xyz]~% grep -C 2 "3rd" file.txt # print 2 line before and 2 line after the searched string 
this is first line
this is 2nd line
this is 3rd line
this is 4th line
this is 5th line

记住选项的技巧:选项:

-一个 -> 之后的平均值-B级 -> B表示之前。-c类 -> 介于两者之间