我听说利斯科夫替换原则(LSP)是面向对象设计的基本原则。它是什么?它的一些使用例子是什么?
当前回答
可替代性是面向对象编程中的一个原则,它指出,在计算机程序中,如果S是T的子类型,那么类型T的对象可以被类型S的对象替换
让我们用Java做一个简单的例子:
不好的例子
public class Bird{
public void fly(){}
}
public class Duck extends Bird{}
鸭子能飞,因为它是鸟,但这个呢:
public class Ostrich extends Bird{}
鸵鸟是一种鸟,但它不能飞,鸵鸟类是鸟类的一个子类,但它不应该能够使用fly方法,这意味着我们打破了LSP原则。
很好的例子
public class Bird{}
public class FlyingBirds extends Bird{
public void fly(){}
}
public class Duck extends FlyingBirds{}
public class Ostrich extends Bird{}
其他回答
LSP说“对象应该被它们的子类型替换”。 另一方面,这一原则指向
子类永远不应该破坏父类的类型定义。
通过以下示例,可以更好地理解LSP。
没有太阳能发电:
public interface CustomerLayout{
public void render();
}
public FreeCustomer implements CustomerLayout {
...
@Override
public void render(){
//code
}
}
public PremiumCustomer implements CustomerLayout{
...
@Override
public void render(){
if(!hasSeenAd)
return; //it isn`t rendered in this case
//code
}
}
public void renderView(CustomerLayout layout){
layout.render();
}
LSP修复:
public interface CustomerLayout{
public void render();
}
public FreeCustomer implements CustomerLayout {
...
@Override
public void render(){
//code
}
}
public PremiumCustomer implements CustomerLayout{
...
@Override
public void render(){
if(!hasSeenAd)
showAd();//it has a specific behavior based on its requirement
//code
}
}
public void renderView(CustomerLayout layout){
layout.render();
}
利科夫替换原则指出,如果程序模块使用基类,则基类的引用可以被派生类替换,而不会影响程序模块的功能。
派生类型必须能够完全替代它们的基类型。
示例- java中的协变返回类型。
罗伯特·马丁有一篇关于利斯科夫替换原理的优秀论文。它讨论了可能违反原则的微妙和不那么微妙的方式。
论文的一些相关部分(注意,第二个例子被大量压缩):
A Simple Example of a Violation of LSP One of the most glaring violations of this principle is the use of C++ Run-Time Type Information (RTTI) to select a function based upon the type of an object. i.e.: void DrawShape(const Shape& s) { if (typeid(s) == typeid(Square)) DrawSquare(static_cast<Square&>(s)); else if (typeid(s) == typeid(Circle)) DrawCircle(static_cast<Circle&>(s)); } Clearly the DrawShape function is badly formed. It must know about every possible derivative of the Shape class, and it must be changed whenever new derivatives of Shape are created. Indeed, many view the structure of this function as anathema to Object Oriented Design. Square and Rectangle, a More Subtle Violation. However, there are other, far more subtle, ways of violating the LSP. Consider an application which uses the Rectangle class as described below: class Rectangle { public: void SetWidth(double w) {itsWidth=w;} void SetHeight(double h) {itsHeight=w;} double GetHeight() const {return itsHeight;} double GetWidth() const {return itsWidth;} private: double itsWidth; double itsHeight; }; [...] Imagine that one day the users demand the ability to manipulate squares in addition to rectangles. [...] Clearly, a square is a rectangle for all normal intents and purposes. Since the ISA relationship holds, it is logical to model the Square class as being derived from Rectangle. [...] Square will inherit the SetWidth and SetHeight functions. These functions are utterly inappropriate for a Square, since the width and height of a square are identical. This should be a significant clue that there is a problem with the design. However, there is a way to sidestep the problem. We could override SetWidth and SetHeight [...] But consider the following function: void f(Rectangle& r) { r.SetWidth(32); // calls Rectangle::SetWidth } If we pass a reference to a Square object into this function, the Square object will be corrupted because the height won’t be changed. This is a clear violation of LSP. The function does not work for derivatives of its arguments. [...]
可替代性是面向对象编程中的一个原则,它指出,在计算机程序中,如果S是T的子类型,那么类型T的对象可以被类型S的对象替换
让我们用Java做一个简单的例子:
不好的例子
public class Bird{
public void fly(){}
}
public class Duck extends Bird{}
鸭子能飞,因为它是鸟,但这个呢:
public class Ostrich extends Bird{}
鸵鸟是一种鸟,但它不能飞,鸵鸟类是鸟类的一个子类,但它不应该能够使用fly方法,这意味着我们打破了LSP原则。
很好的例子
public class Bird{}
public class FlyingBirds extends Bird{
public void fly(){}
}
public class Duck extends FlyingBirds{}
public class Ostrich extends Bird{}
LSP关注不变量。
经典示例由以下伪代码声明给出(实现略):
class Rectangle {
int getHeight()
void setHeight(int value) {
postcondition: width didn’t change
}
int getWidth()
void setWidth(int value) {
postcondition: height didn’t change
}
}
class Square extends Rectangle { }
现在我们有一个问题,尽管接口匹配。原因是我们违反了源自正方形和矩形数学定义的不变量。getter和setter的工作方式,矩形应该满足以下不变量:
void invariant(Rectangle r) {
r.setHeight(200)
r.setWidth(100)
assert(r.getHeight() == 200 and r.getWidth() == 100)
}
然而,Square的正确实现必须违反这个不变量(以及显式后置条件),因此它不是Rectangle的有效替代品。