我可以使用以下jQuery代码使用ajax请求的POST方法执行文件上载吗？
$.ajax({
type: "POST",
timeout: 50000,
url: url,
data: dataString,
success: function (data) {
alert('success');
return false;
}
});
如果可能，我需要填写数据部分吗？这是正确的方式吗？我只将文件POST到服务器端。
我一直在搜索，但我发现的是一个插件，而在我的计划中，我不想使用它。至少目前是这样。
当前回答
以下是我如何做到这一点：
HTML
<input type="file" id="file">
<button id='process-file-button'>Process</button>
JS
$('#process-file-button').on('click', function (e) {
let files = new FormData(), // you can consider this as 'data bag'
url = 'yourUrl';
files.append('fileName', $('#file')[0].files[0]); // append selected file to the bag named 'file'
$.ajax({
type: 'post',
url: url,
processData: false,
contentType: false,
data: files,
success: function (response) {
console.log(response);
},
error: function (err) {
console.log(err);
}
});
});
PHP
if (isset($_FILES) && !empty($_FILES)) {
$file = $_FILES['fileName'];
$name = $file['name'];
$path = $file['tmp_name'];
// process your file
}
其他回答
<html>
<head>
<title>Ajax file upload</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
$(document).ready(function (e) {
$("#uploadimage").on('submit', (function(e) {
e.preventDefault();
$.ajax({
url: "upload.php", // Url to which the request is send
type: "POST", // Type of request to be send, called as method
data: new FormData(this), // Data sent to server, a set of key/value pairs (i.e. form fields and values)
contentType: false, // The content type used when sending data to the server.
cache: false, // To unable request pages to be cached
processData:false, // To send DOMDocument or non processed data file it is set to false
success: function(data) // A function to be called if request succeeds
{
alert(data);
}
});
}));
</script>
</head>
<body>
<div class="main">
<h1>Ajax Image Upload</h1><br/>
<hr>
<form id="uploadimage" action="" method="post" enctype="multipart/form-data">
<div id="image_preview"><img id="previewing" src="noimage.png" /></div>
<hr id="line">
<div id="selectImage">
<label>Select Your Image</label><br/>
<input type="file" name="file" id="file" required />
<input type="submit" value="Upload" class="submit" />
</div>
</form>
</div>
</body>
</html>
2019年更新：
html
<form class="fr" method='POST' enctype="multipart/form-data"> {% csrf_token %}
<textarea name='text'>
<input name='example_image'>
<button type="submit">
</form>
js
$(document).on('submit', '.fr', function(){
$.ajax({
type: 'post',
url: url, <--- you insert proper URL path to call your views.py function here.
enctype: 'multipart/form-data',
processData: false,
contentType: false,
data: new FormData(this) ,
success: function(data) {
console.log(data);
}
});
return false;
});
视图.py
form = ThisForm(request.POST, request.FILES)
if form.is_valid():
text = form.cleaned_data.get("text")
example_image = request.FILES['example_image']
使用FormData。它工作得很好：-）。。。
var jform = new FormData();
jform.append('user',$('#user').val());
jform.append('image',$('#image').get(0).files[0]); // Here's the important bit
$.ajax({
url: '/your-form-processing-page-url-here',
type: 'POST',
data: jform,
dataType: 'json',
mimeType: 'multipart/form-data', // this too
contentType: false,
cache: false,
processData: false,
success: function(data, status, jqXHR){
alert('Hooray! All is well.');
console.log(data);
console.log(status);
console.log(jqXHR);
},
error: function(jqXHR,status,error){
// Hopefully we should never reach here
console.log(jqXHR);
console.log(status);
console.log(error);
}
});
要获取所有表单输入，包括type=“file”，需要使用FormData对象。提交表单后，您将能够在调试器->网络->标头中看到formData内容。
var url = "YOUR_URL";
var form = $('#YOUR_FORM_ID')[0];
var formData = new FormData(form);
$.ajax(url, {
method: 'post',
processData: false,
contentType: false,
data: formData
}).done(function(data){
if (data.success){
alert("Files uploaded");
} else {
alert("Error while uploading the files");
}
}).fail(function(data){
console.log(data);
alert("Error while uploading the files");
});
我用简单的代码处理了这些问题。您可以从这里下载工作演示
就你的情况而言，这些都是可能的。我将逐步介绍如何使用AJAX jquery将文件上传到服务器。
首先让我们创建一个HTML文件，添加如下表单文件元素，如下所示。
<form action="" id="formContent" method="post" enctype="multipart/form-data" >
<input type="file" name="file" required id="upload">
<button class="submitI" >Upload Image</button>
</form>
其次，创建一个jquery.js文件，并添加以下代码来处理向服务器提交的文件
$("#formContent").submit(function(e){
e.preventDefault();
var formdata = new FormData(this);
$.ajax({
url: "ajax_upload_image.php",
type: "POST",
data: formdata,
mimeTypes:"multipart/form-data",
contentType: false,
cache: false,
processData: false,
success: function(){
alert("file successfully submitted");
},error: function(){
alert("okey");
}
});
});
});
你完成了。查看更多信息
