我知道如何创建一个有String参数并返回int的方法的引用,它是:

Function<String, Integer>

然而,如果函数抛出异常,比如它被定义为:

Integer myMethod(String s) throws IOException

我该如何定义这个引用呢?


当前回答

我是一个小库的作者,它具有一些通用的魔法,可以在任何地方抛出任何Java异常,而不需要捕获它们,也不需要将它们包装到RuntimeException中。

用法: unchecked(() -> methodThrowingCheckedException())

public class UncheckedExceptions {

    /**
     * throws {@code exception} as unchecked exception, without wrapping exception.
     *
     * @return will never return anything, return type is set to {@code exception} only to be able to write <code>throw unchecked(exception)</code>
     * @throws T {@code exception} as unchecked exception
     */
    @SuppressWarnings("unchecked")
    public static <T extends Throwable> T unchecked(Exception exception) throws T {
        throw (T) exception;
    }


    @FunctionalInterface
    public interface UncheckedFunction<R> {
        R call() throws Exception;
    }

    /**
     * Executes given function,
     * catches and rethrows checked exceptions as unchecked exceptions, without wrapping exception.
     *
     * @return result of function
     * @see #unchecked(Exception)
     */
    public static <R> R unchecked(UncheckedFunction<R> function) {
        try {
            return function.call();
        } catch (Exception e) {
            throw unchecked(e);
        }
    }


    @FunctionalInterface
    public interface UncheckedMethod {
        void call() throws Exception;
    }

    /**
     * Executes given method,
     * catches and rethrows checked exceptions as unchecked exceptions, without wrapping exception.
     *
     * @see #unchecked(Exception)
     */
    public static void unchecked(UncheckedMethod method) {
        try {
            method.call();
        } catch (Exception e) {
            throw unchecked(e);
        }
    }
}

来源:https://github.com/qoomon/unchecked-exceptions-java

其他回答

这并不是Java 8所特有的。你正在尝试编译一些等价的东西:

interface I {
    void m();
}
class C implements I {
    public void m() throws Exception {} //can't compile
}

您需要执行以下操作之一。

If it's your code, then define your own functional interface that declares the checked exception: @FunctionalInterface public interface CheckedFunction<T, R> { R apply(T t) throws IOException; } and use it: void foo (CheckedFunction f) { ... } Otherwise, wrap Integer myMethod(String s) in a method that doesn't declare a checked exception: public Integer myWrappedMethod(String s) { try { return myMethod(s); } catch(IOException e) { throw new UncheckedIOException(e); } } and then: Function<String, Integer> f = (String t) -> myWrappedMethod(t); or: Function<String, Integer> f = (String t) -> { try { return myMethod(t); } catch(IOException e) { throw new UncheckedIOException(e); } };

默认情况下,Java 8函数不允许抛出异常,正如在多个回答中所建议的那样,有许多方法来实现它,其中一种方法是:

@FunctionalInterface
public interface FunctionWithException<T, R, E extends Exception> {
    R apply(T t) throws E;
}

定义为:

private FunctionWithException<String, Integer, IOException> myMethod = (str) -> {
    if ("abc".equals(str)) {
        throw new IOException();
    }
  return 1;
};

并在调用者方法中添加抛出或尝试/捕获相同的异常。

Sneaky throw成语允许绕过Lambda表达式的CheckedException。将CheckedException包装在RuntimeException中不利于严格的错误处理。

它可以用作Java集合中使用的Consumer函数。

下面是jib答案的一个简单改进版本。

import static Throwing.rethrow;

@Test
public void testRethrow() {
    thrown.expect(IOException.class);
    thrown.expectMessage("i=3");

    Arrays.asList(1, 2, 3).forEach(rethrow(e -> {
        int i = e.intValue();
        if (i == 3) {
            throw new IOException("i=" + i);
        }
    }));
}

这只是在重新抛出中包装lambda。它使CheckedException重新抛出在lambda中抛出的任何异常。

public final class Throwing {
    private Throwing() {}

    @Nonnull
    public static <T> Consumer<T> rethrow(@Nonnull final ThrowingConsumer<T> consumer) {
        return consumer;
    }

    /**
     * The compiler sees the signature with the throws T inferred to a RuntimeException type, so it
     * allows the unchecked exception to propagate.
     * 
     * http://www.baeldung.com/java-sneaky-throws
     */
    @SuppressWarnings("unchecked")
    @Nonnull
    public static <E extends Throwable> void sneakyThrow(@Nonnull Throwable ex) throws E {
        throw (E) ex;
    }

}

在这里找到完整的代码和单元测试。

实际上,您可以使用一个处理异常的新接口来扩展Consumer(和Function等)——使用Java 8的默认方法!

考虑这个接口(扩展Consumer):

@FunctionalInterface
public interface ThrowingConsumer<T> extends Consumer<T> {

    @Override
    default void accept(final T elem) {
        try {
            acceptThrows(elem);
        } catch (final Exception e) {
            // Implement your own exception handling logic here..
            // For example:
            System.out.println("handling an exception...");
            // Or ...
            throw new RuntimeException(e);
        }
    }

    void acceptThrows(T elem) throws Exception;

}

然后,例如,如果你有一个列表:

final List<String> list = Arrays.asList("A", "B", "C");

如果你想消费它(例如。使用forEach)和一些抛出异常的代码,你通常会设置一个try/catch块:

final Consumer<String> consumer = aps -> {
    try {
        // maybe some other code here...
        throw new Exception("asdas");
    } catch (final Exception ex) {
        System.out.println("handling an exception...");
    }
};
list.forEach(consumer);

但是有了这个新接口,你可以用lambda表达式实例化它,编译器不会报错:

final ThrowingConsumer<String> throwingConsumer = aps -> {
    // maybe some other code here...
    throw new Exception("asdas");
};
list.forEach(throwingConsumer);

或者甚至只是转换它更简洁!:

list.forEach((ThrowingConsumer<String>) aps -> {
    // maybe some other code here...
    throw new Exception("asda");
});

更新

看起来榴莲有一个非常好的实用程序库,叫做Errors,可以用来解决这个问题,具有更大的灵活性。例如,在上面的实现中,我显式地定义了错误处理策略(System.out…或者抛出RuntimeException),而Durian的Errors允许您通过一套大型实用程序方法动态应用策略。感谢分享,@NedTwigg!

示例用法:

list.forEach(Errors.rethrow().wrap(c -> somethingThatThrows(c)));