我不时地读到Fortran在繁重的计算中比C更快。这是真的吗?我必须承认我几乎不懂Fortran,但是到目前为止我看到的Fortran代码并没有显示出该语言具有C语言所不具备的特性。
如果是真的,请告诉我原因。请不要告诉我什么语言或库适合处理数字,我不打算写一个应用程序或库来做这个,我只是好奇。
我不时地读到Fortran在繁重的计算中比C更快。这是真的吗?我必须承认我几乎不懂Fortran,但是到目前为止我看到的Fortran代码并没有显示出该语言具有C语言所不具备的特性。
如果是真的,请告诉我原因。请不要告诉我什么语言或库适合处理数字,我不打算写一个应用程序或库来做这个,我只是好奇。
当前回答
Fortran可以非常方便地处理数组,特别是多维数组。在Fortran中对多维数组元素进行切片比在C/ c++中容易得多。c++现在有库可以做这项工作,比如Boost或Eigen,但它们毕竟是外部库。在Fortran中,这些函数是固有的。
对于开发来说,Fortran是更快还是更方便主要取决于您需要完成的工作。作为地球物理的科学计算人员,我用Fortran(我指的是现代Fortran, >=F90)进行了大部分计算。
其他回答
Fortran有更好的I/O例程,例如隐含的do工具提供了C标准库无法比拟的灵活性。
Fortran编译器直接处理更复杂的 涉及到语法,而且这样的语法不能轻易简化 参数传递形式,C不能有效地实现它。
Fortran和C之间的速度差异更多的是编译器优化和特定编译器使用的底层数学库的函数。Fortran没有什么固有的特性可以使它比C更快。
不管怎样,一个优秀的程序员可以用任何语言编写Fortran。
The faster code is not really up to the language, is the compiler so you can see the ms-vb "compiler" that generates bloated, slower and redundant object code that is tied together inside an ".exe", but powerBasic generates too way better code. Object code made by a C and C++ compilers is generated in some phases (at least 2) but by design most Fortran compilers have at least 5 phases including high-level optimizations so by design Fortran will always have the capability to generate highly optimized code. So at the end is the compiler not the language you should ask for, the best compiler i know is the Intel Fortran Compiler because you can get it on LINUX and Windows and you can use VS as the IDE, if you're looking for a cheap tigh compiler you can always relay on OpenWatcom.
更多信息: http://ed-thelen.org/1401Project/1401-IBM-Systems-Journal-FORTRAN.html
This is more than somewhat subjective, because it gets into the quality of compilers and such more than anything else. However, to more directly answer your question, speaking from a language/compiler standpoint there is nothing about Fortran over C that is going to make it inherently faster or better than C. If you are doing heavy math operations, it will come down to the quality of the compiler, the skill of the programmer in each language and the intrinsic math support libraries that support those operations to ultimately determine which is going to be faster for a given implementation.
编辑:@Nils等人提出了一个很好的观点,即C语言中指针使用的差异,以及可能存在的别名,这可能会使C语言中最简单的实现变慢。然而,在C99中有一些方法可以解决这个问题,比如通过编译器优化标志和/或C语言的实际编写方式。这在@Nils的回答和随后的评论中有很好的介绍。
这两种语言具有相似的特性集。性能上的差异来自Fortran不允许混淆的事实,除非使用了EQUIVALENCE语句。任何有别名的代码都不是有效的Fortran,但是它是由程序员而不是编译器来检测这些错误的。因此,Fortran编译器忽略了可能的内存指针别名,并允许它们生成更有效的代码。看一下C语言中的这个小例子:
void transform (float *output, float const * input, float const * matrix, int *n)
{
int i;
for (i=0; i<*n; i++)
{
float x = input[i*2+0];
float y = input[i*2+1];
output[i*2+0] = matrix[0] * x + matrix[1] * y;
output[i*2+1] = matrix[2] * x + matrix[3] * y;
}
}
这个函数在优化后会比Fortran函数运行得慢。为什么如此?如果你在输出数组中写入值,你可能会改变矩阵的值。毕竟,指针可以重叠并指向相同的内存块(包括int指针!)C编译器被迫从内存中重新加载所有计算的四个矩阵值。
在Fortran中,编译器只加载一次矩阵值,并将它们存储在寄存器中。它可以这样做是因为Fortran编译器假定指针/数组在内存中不重叠。
Fortunately, the restrict keyword and strict-aliasing have been introduced to the C99 standard to address this problem. It's well supported in most C++ compilers these days as well. The keyword allows you to give the compiler a hint that the programmer promises that a pointer does not alias with any other pointer. The strict-aliasing means that the programmer promises that pointers of different type will never overlap, for example a double* will not overlap with an int* (with the specific exception that char* and void* can overlap with anything).
If you use them you will get the same speed from C and Fortran. However, the ability to use the restrict keyword only with performance critical functions means that C (and C++) programs are much safer and easier to write. For example, consider the invalid Fortran code: CALL TRANSFORM(A(1, 30), A(2, 31), A(3, 32), 30), which most Fortran compilers will happily compile without any warning but introduces a bug that only shows up on some compilers, on some hardware and with some optimization options.