如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
当前回答
快速攻击:
// assuming $var is a multidimensional array
$obj = json_decode (json_encode ($var), FALSE);
不漂亮,但很好用。
其他回答
这个方法对我很管用
function array_to_obj($array, &$obj)
{
foreach ($array as $key => $value)
{
if (is_array($value))
{
$obj->$key = new stdClass();
array_to_obj($value, $obj->$key);
}
else
{
$obj->$key = $value;
}
}
return $obj;
}
function arrayToObject($array)
{
$object= new stdClass();
return array_to_obj($array,$object);
}
用法:
$myobject = arrayToObject($array);
print_r($myobject);
返回:
[127] => stdClass Object
(
[status] => Have you ever created a really great looking website design
)
[128] => stdClass Object
(
[status] => Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution.
)
[129] => stdClass Object
(
[status] => The other day at work, I had some spare time
)
像往常一样,你可以这样循环:
foreach($myobject as $obj)
{
echo $obj->status;
}
多维数组转换为对象。此代码用于转换必应搜索API的尝试和捕获方法。
try {
// Perform the Web request and get the JSON response
$context = stream_context_create($options);
$results = file_get_contents($url . "?cc=" . $country . "&category=" . $type, false, $context);
$results = json_decode($results);
return response()->json($results);
} catch (\Exception $e) {
$results = array('value' => array(
(object) array(
"name" => "Unable to Retrive News",
"url" => "http://www.sample.com/",
"image" => (object) array("thumbnail" => (object) array("contentUrl" => "")),
"publishedAt" => "",
"description" => "")
)
);
$results = (object) $results;
return response()->json($results);
}
世界上最好的方法:)
function arrayToObject($conArray)
{
if(is_array($conArray)){
/*
* Return array converted to object
* Using __FUNCTION__ (Magic constant)
* for recursive call
*/
return (object) array_map(__FUNCTION__, $conArray);
}else{
// Return object
return $conArray;
}
}
如果使用不同的方法,就会出现问题。这是最好的方法。你所见过的。
实际上,如果你想在多维数组中使用这个你就需要使用一些递归。
static public function array_to_object(array $array)
{
foreach($array as $key => $value)
{
if(is_array($value))
{
$array[$key] = self::array_to_object($value);
}
}
return (object)$array;
}
受到所有这些代码的启发,我尝试创建一个增强版本,支持:特定的类名,避免构造函数方法,'beans'模式和严格模式(仅设置现有属性):
class Util {
static function arrayToObject($array, $class = 'stdClass', $strict = false) {
if (!is_array($array)) {
return $array;
}
//create an instance of an class without calling class's constructor
$object = unserialize(
sprintf(
'O:%d:"%s":0:{}', strlen($class), $class
)
);
if (is_array($array) && count($array) > 0) {
foreach ($array as $name => $value) {
$name = strtolower(trim($name));
if (!empty($name)) {
if(method_exists($object, 'set'.$name)){
$object->{'set'.$name}(Util::arrayToObject($value));
}else{
if(($strict)){
if(property_exists($class, $name)){
$object->$name = Util::arrayToObject($value);
}
}else{
$object->$name = Util::arrayToObject($value);
}
}
}
}
return $object;
} else {
return FALSE;
}
}
}