如何将这样的数组转换为对象?

[128] => Array
    (
        [status] => "Figure A.
 Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
    )

[129] => Array
    (
        [status] => "The other day at work, I had some spare time"
    )

当前回答

如果你需要将一个数组强制转换为一个特定的类(在我的例子中,我需要对象类型为Google_Service_AndroidPublisher_Resource_Inappproducts),你可以像这样从stdClass中将类名str_replace为预期的类:

function castArrayToClass(array $array, string $className)
{
    //first cast the array to stdClass
    $subject = serialize((object)$array);
    //then change the class name
    $converted = str_replace(
        'O:8:"stdClass"',
        'O:'.strlen($className).':"'.$className.'"',
        $subject
    );
    unset($subject);

    return unserialize($converted);
}

其他回答

一个衬套

$object= json_decode(json_encode($result_array, JSON_FORCE_OBJECT));

使用我创建的这个函数:

function buildObject($class,$data){
    $object = new $class;
    foreach($data as $key=>$value){
        if(property_exists($class,$key)){
            $object->{'set'.ucfirst($key)}($value);
        }
    }
    return $object;
}

用法:

$myObject = buildObject('MyClassName',$myArray);

它的方法很简单,这将为递归数组创建一个对象:

$object = json_decode(json_encode((object) $yourArray), FALSE);

这个方法对我很管用

  function array_to_obj($array, &$obj)
  {
    foreach ($array as $key => $value)
    {
      if (is_array($value))
      {
      $obj->$key = new stdClass();
      array_to_obj($value, $obj->$key);
      }
      else
      {
        $obj->$key = $value;
      }
    }
  return $obj;
  }

function arrayToObject($array)
{
 $object= new stdClass();
 return array_to_obj($array,$object);
}

用法:

$myobject = arrayToObject($array);
print_r($myobject);

返回:

    [127] => stdClass Object
        (
            [status] => Have you ever created a really great looking website design
        )

    [128] => stdClass Object
        (
            [status] => Figure A.
 Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution.
        )

    [129] => stdClass Object
        (
            [status] => The other day at work, I had some spare time
        )

像往常一样,你可以这样循环:

foreach($myobject as $obj)
{
  echo $obj->status;
}

简单的方法是

$object = (object)$array;

但这不是你想要的。如果你想要对象,你想要实现一些东西,但这在这个问题中是缺失的。仅仅为了使用对象而使用对象是没有意义的。