如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
当前回答
如果你需要将一个数组强制转换为一个特定的类(在我的例子中,我需要对象类型为Google_Service_AndroidPublisher_Resource_Inappproducts),你可以像这样从stdClass中将类名str_replace为预期的类:
function castArrayToClass(array $array, string $className)
{
//first cast the array to stdClass
$subject = serialize((object)$array);
//then change the class name
$converted = str_replace(
'O:8:"stdClass"',
'O:'.strlen($className).':"'.$className.'"',
$subject
);
unset($subject);
return unserialize($converted);
}
其他回答
我使用的一个(它是类成员):
const MAX_LEVEL = 5; // change it as needed
public function arrayToObject($a, $level=0)
{
if(!is_array($a)) {
throw new InvalidArgumentException(sprintf('Type %s cannot be cast, array expected', gettype($a)));
}
if($level > self::MAX_LEVEL) {
throw new OverflowException(sprintf('%s stack overflow: %d exceeds max recursion level', __METHOD__, $level));
}
$o = new stdClass();
foreach($a as $key => $value) {
if(is_array($value)) { // convert value recursively
$value = $this->arrayToObject($value, $level+1);
}
$o->{$key} = $value;
}
return $o;
}
你可以使用反射:
<?php
$array = ['name'=>'maria','age'=>33];
class Person {
public $name;
public $age;
public function __construct(string $name, string $age){
$this->name = $name;
$this->age = $age;
}
}
function arrayToObject(array $array, string $class_name){
$r = new ReflectionClass($class_name);
$object = $r->newInstanceWithoutConstructor();
$list = $r->getProperties();
foreach($list as $prop){
$prop->setAccessible(true);
if(isset($array[$prop->name]))
$prop->setValue($object, $array[$prop->name]);
}
return $object;
}
$pessoa1 = arrayToObject($array, 'Person');
var_dump($pessoa1);
可以使用(object)函数将数组转换为对象。
$arr= [128=> ['status'=>
'Figure A. Facebook \'s horizontal scrollbars showing up on a 1024x768 screen resolution.'],
129=>['status'=>'The other day at work, I had some spare time']];
$ArrToObject=(object)$arr;
var_dump($ArrToObject);
结果将是一个包含数组的对象:
对象(stdClass)#1048(2){[128]=>数组(1){ ["地位"]= > 字符串(87)“图a: Facebook的水平滚动条显示在1024x768分辨率的屏幕上。”} [129]=>数组(1){ ["地位"]= > 字符串(44)“前几天上班,我有一些空闲时间”}}
容易:
$object = json_decode(json_encode($array));
例子:
$array = array(
'key' => array(
'k' => 'value',
),
'group' => array('a', 'b', 'c')
);
$object = json_decode(json_encode($array));
那么,以下是正确的:
$object->key->k === 'value';
$object->group === array('a', 'b', 'c')
显然,这只是对其他人答案的推断,但这里有一个递归函数,可以将任何多维数组转换为对象:
function convert_array_to_object($array){
$obj= new stdClass();
foreach ($array as $k=> $v) {
if (is_array($v)){
$v = convert_array_to_object($v);
}
$obj->{strtolower($k)} = $v;
}
return $obj;
}
记住,如果数组有数字键,它们仍然可以通过{}在结果对象中引用(例如:$obj->prop->{4}->prop)