如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
如何将这样的数组转换为对象?
[128] => Array
(
[status] => "Figure A.
Facebook's horizontal scrollbars showing up on a 1024x768 screen resolution."
)
[129] => Array
(
[status] => "The other day at work, I had some spare time"
)
当前回答
通过使用(array)和(object)作为前缀,可以简单地将对象数组转换为标准数组,反之亦然
<?php
//defining an array
$a = array('a'=>'1','b'=>'2','c'=>'3','d'=>'4');
//defining an object array
$obj = new stdClass();
$obj->a = '1';
$obj->b = '2';
$obj->c = '3';
$obj->d = '4';
print_r($a);echo '<br>';
print_r($obj);echo '<br>';
//converting object array to array
$b = (array) $obj;
print_r($b);echo '<br>';
//converting array to object
$c = (object) $a;
print_r($c);echo '<br>';
?>
其他回答
这里有三种方法:
Fake a real object: class convert { public $varible; public function __construct($array) { $this = $array; } public static function toObject($array) { $array = new convert($array); return $array; } } Convert the array into an object by casting it to an object: $array = array( // ... ); $object = (object) $array; Manually convert the array into an object: $object = object; foreach ($arr as $key => $value) { $object->{$key} = $value; }
CakePHP有一个递归的Set::map类,基本上是将数组映射到对象。为了使对象看起来像你想要的样子,你可能需要改变数组的样子。
http://api.cakephp.org/view_source/set/#line-158
最坏的情况下,您可能会从这个函数中得到一些想法。
你也可以通过在变量的左边添加(object)来创建一个新对象。
<?php
$a = Array
( 'status' => " text" );
var_dump($a);
$b = (object)$a;
var_dump($b);
var_dump($b->status);
http://codepad.org/9YmD1KsU
多维数组转换为对象。此代码用于转换必应搜索API的尝试和捕获方法。
try {
// Perform the Web request and get the JSON response
$context = stream_context_create($options);
$results = file_get_contents($url . "?cc=" . $country . "&category=" . $type, false, $context);
$results = json_decode($results);
return response()->json($results);
} catch (\Exception $e) {
$results = array('value' => array(
(object) array(
"name" => "Unable to Retrive News",
"url" => "http://www.sample.com/",
"image" => (object) array("thumbnail" => (object) array("contentUrl" => "")),
"publishedAt" => "",
"description" => "")
)
);
$results = (object) $results;
return response()->json($results);
}
我用了很简单的方法,
$list_years = array();
$object = new stdClass();
$object->year_id = 1 ;
$object->year_name = 2001 ;
$list_years[] = $object;