我得到$row['message']从一个MySQL数据库，我需要删除所有的空白，如\n \t等。
$row['message'] = "This is a Text \n and so on \t Text text.";
应格式化为:
$row['message'] = 'This is a Text and so on Text text.';
我试着:
$ro = preg_replace('/\s\s+/', ' ',$row['message']);
echo $ro;
但它不删除\n或\t，只删除单个空格。有人能告诉我怎么做吗?
当前回答
preg_replace('/[\s]+/mu', ' ', $var);
\s已经包含制表符和新行，所以上面的正则表达式似乎足够了。
其他回答
$str='This is a Text \n and so on Text text.';
print preg_replace("/[[:blank:]]+/"," ",$str);
简化为一个函数:
function removeWhiteSpace($text)
{
$text = preg_replace('/[\t\n\r\0\x0B]/', '', $text);
$text = preg_replace('/([\s])\1+/', ' ', $text);
$text = trim($text);
return $text;
}
基于丹尼尔·奥尼尔的答案。
我使用以下代码和模式:
preg_replace('/\\s+/', ' ',$data)
$data = 'This is a Text
and so on Text text on multiple lines and with whitespaces';
$data= preg_replace('/\\s+/', ' ',$data);
echo $data;
您可以在http://writecodeonline.com/php/上进行测试
没有preg_replace ()
$str = "This is a Text \n and so on \t Text text.";
$str = str_replace(["\r", "\n", "\t"], " ", $str);
while (strpos($str, " ") !== false)
{
$str = str_replace(" ", " ", $str);
}
echo $str;
<?php
$str = "This is a string with
spaces, tabs and newlines present";
$stripped = preg_replace(array('/\s{2,}/', '/[\t\n]/'), ' ', $str);
echo $str;
echo "\n---\n";
echo "$stripped";
?>
这个输出
This is a string with
spaces, tabs and newlines present
---
This is a string with spaces, tabs and newlines present
