是否有可能实现一个HashMap有一个键和两个值。就像HashMap?

请帮助我,也通过告诉(如果没有办法)任何其他方法来实现三个值的存储与一个作为关键?


当前回答

我更喜欢下面的方法来存储任意数量的变量,而不必创建一个单独的类。

final public static Map<String, Map<String, Float>> myMap    = new HashMap<String, Map<String, Float>>();

其他回答

我已经习惯了在Objective c中使用数据字典来实现这一目标,而在Java for Android中却很难获得类似的结果。我最终创建了一个自定义类,然后只做了一个自定义类的hashmap。

public class Test1 {
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.addview);

//create the datastring
    HashMap<Integer, myClass> hm = new HashMap<Integer, myClass>();
    hm.put(1, new myClass("Car", "Small", 3000));
    hm.put(2, new myClass("Truck", "Large", 4000));
    hm.put(3, new myClass("Motorcycle", "Small", 1000));

//pull the datastring back for a specific item.
//also can edit the data using the set methods.  this just shows getting it for display.
    myClass test1 = hm.get(1);
    String testitem = test1.getItem();
    int testprice = test1.getPrice();
    Log.i("Class Info Example",testitem+Integer.toString(testprice));
}
}

//custom class.  You could make it public to use on several activities, or just include in the activity if using only here
class myClass{
    private String item;
    private String type;
    private int price;

    public myClass(String itm, String ty, int pr){
        this.item = itm;
        this.price = pr;
        this.type = ty;
    }

    public String getItem() {
        return item;
    }

    public void setItem(String item) {
        this.item = item;
    }

    public String getType() {
        return item;
    }

    public void setType(String type) {
        this.type = type;
    }

    public int getPrice() {
        return price;
    }

    public void setPrice(int price) {
        this.price = price;
    }

}

是的,这通常被称为multimap。

参见:http://google-collections.googlecode.com/svn/trunk/javadoc/index.html?com/google/common/collect/Multimap.html

你可以隐式地做。

// Create the map. There is no restriction to the size that the array String can have
HashMap<Integer, String[]> map = new HashMap<Integer, String[]>();

//initialize a key chosing the array of String you want for your values
map.put(1, new String[] { "name1", "name2" });

//edit value of a key
map.get(1)[0] = "othername";

这是非常简单和有效的。 如果你想要不同类的值,你可以这样做:

HashMap<Integer, Object[]> map = new HashMap<Integer, Object[]>();
 import java.io.*;
 import java.util.*;

 import com.google.common.collect.*;

 class finTech{
public static void main(String args[]){
       Multimap<String, String> multimap = ArrayListMultimap.create();
       multimap.put("1","11");
       multimap.put("1","14");
       multimap.put("1","12");
       multimap.put("1","13");
       multimap.put("11","111");
       multimap.put("12","121");
        System.out.println(multimap);
        System.out.println(multimap.get("11"));
   }                                                                                            
 }                                                                    

输出:

     {"1"=["11","12","13","14"],"11"=["111"],"12"=["121"]}

      ["111"]

这是用于实用功能的Google-Guava库。这就是需要的解决方案。

不,不只是作为HashMap。你基本上需要一个HashMap,从一个键到一个值的集合。

如果你喜欢使用外部库,Guava在Multimap中就有这个概念,比如ArrayListMultimap, HashMultimap, LinkedHashMultimap等。

Multimap<String, Integer> nameToNumbers = HashMultimap.create();

System.out.println(nameToNumbers.put("Ann", 5)); // true
System.out.println(nameToNumbers.put("Ann", 5)); // false
nameToNumbers.put("Ann", 6);
nameToNumbers.put("Sam", 7);

System.out.println(nameToNumbers.size()); // 3
System.out.println(nameToNumbers.keySet().size()); // 2