找到你的微调器名称和id，然后实现这个方法。

spinnername.setOnItemSelectedListener(new OnItemSelectedListener() {

    @Override
    public void onItemSelected(AdapterView<?> parentView, View selectedItemView, int position, long id) {
        // your code here
    }

    @Override
    public void onNothingSelected(AdapterView<?> parentView) {
        // your code here
    }
});

我认为最好的方法是让flagitemselected = 0;在onCreate()。在itemselected event上增加标志，即flagitemselected++;然后检查

if(flagitemselected!=1)
{
// do your work here
}

我想这会有帮助。

默认情况下，您将获得旋转器数组的第一项

value = spinner.getSelectedItem().toString();

无论何时你在旋转器中选择值，它都会给你选择的值

如果你想要选定项目的位置，然后这样做

pos = spinner.getSelectedItemPosition();

以上两个答案均为不应用监听器的情况

找到你的微调器名称和id，然后实现这个方法。

spinnername.setOnItemSelectedListener(new OnItemSelectedListener() {

    @Override
    public void onItemSelected(AdapterView<?> parentView, View selectedItemView, int position, long id) {
        // your code here
    }

    @Override
    public void onNothingSelected(AdapterView<?> parentView) {
        // your code here
    }
});

spinner1.setOnItemSelectedListener(
    new AdapterView.OnItemSelectedListener() {
        //add some code here
    }
);

https://stackoverflow.com/q/1714426/811625

你可以通过一个简单的检查来避免OnItemSelectedListener()被调用:将当前的选择索引存储在一个整数变量中，并在做任何事情之前在onItemSelected(..)中进行检查。

E.g:

Spinner spnLocale;

spnLocale = (Spinner)findViewById(R.id.spnLocale);

int iCurrentSelection = spnLocale.getSelectedItemPosition();

spnLocale.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
    public void onItemSelected(AdapterView<?> adapterView, View view, int i, long l) { 
    if (iCurrentSelection != i){
            // Your code here
    }
    iCurrentSelection = i;
    } 

    public void onNothingSelected(AdapterView<?> adapterView) {
        return;
    } 
}); 

当然，iCurrentSelection应该在对象范围内，这样才能工作!