我只是不得不为自己写这个函数-接受的答案是相当好的，但IMO可以使用一些清理。这需要一个unix时间戳的dob，因为这是我的要求，但可以迅速适应使用字符串:

var getAge = function(dob) {
    var measureDays = function(dateObj) {
            return 31*dateObj.getMonth()+dateObj.getDate();
        },
        d = new Date(dob*1000),
        now = new Date();

    return now.getFullYear() - d.getFullYear() - (measureDays(now) < measureDays(d));
}

注意，我在measureDays函数中使用了31的固定值。所有计算所关心的是“年中的一天”是时间戳的单调递增度量。

如果使用javascript时间戳或字符串，显然需要删除1000的因子。

function change(){
    setTimeout(function(){
        var dateObj  =      new Date();
                    var month    =      dateObj.getUTCMonth() + 1; //months from 1-12
                    var day      =      dateObj.getUTCDate();
                    var year     =      dateObj.getUTCFullYear();  
                    var newdate  =      year + "/" + month + "/" + day;
                    var entered_birthdate        =   document.getElementById('birth_dates').value;
                    var birthdate                =   new Date(entered_birthdate);
                    var birth_year               =   birthdate.getUTCFullYear();
                    var birth_month              =   birthdate.getUTCMonth() + 1;
                    var birth_date               =   birthdate.getUTCDate();
                    var age_year                =    (year-birth_year);
                    var age_month               =    (month-birth_month);
                    var age_date                =    ((day-birth_date) < 0)?(31+(day-birth_date)):(day-birth_date);
                    var test                    =    (birth_year>year)?true:((age_year===0)?((month<birth_month)?true:((month===birth_month)?(day < birth_date):false)):false) ;
                   if (test === true || (document.getElementById("birth_dates").value=== "")){
                        document.getElementById("ages").innerHTML = "";
                    }                    else{
                        var age                     =    (age_year > 1)?age_year:(   ((age_year=== 1 )&&(age_month >= 0))?age_year:((age_month < 0)?(age_month+12):((age_month > 1)?age_month:      (  ((age_month===1) && (day>birth_date) ) ? age_month:age_date)          )    )); 
                        var ages                    =    ((age===age_date)&&(age!==age_month)&&(age!==age_year))?(age_date+"days"):((((age===age_month+12)||(age===age_month)&&(age!==age_year))?(age+"months"):age_year+"years"));
                        document.getElementById("ages").innerHTML = ages;
                  }
                }, 30);

};

这是我修改的尝试(用一个字符串传递给函数而不是一个日期对象):

function calculateAge(dobString) {
    var dob = new Date(dobString);
    var currentDate = new Date();
    var currentYear = currentDate.getFullYear();
    var birthdayThisYear = new Date(currentYear, dob.getMonth(), dob.getDate());
    var age = currentYear - dob.getFullYear();

    if(birthdayThisYear > currentDate) {
        age--;
    }

    return age;
}

和用法:

console.log(calculateAge('1980-01-01'));

我在这里测试的所有答案(大约一半)都认为2000-02-29到2001-02-28是0年，而从2000-02-29到2001-03-01最有可能是1年，即1年零1天。这里有一个getYearDiff函数来修复这个问题。它只适用于d0 < d1:

function getYearDiff(d0, d1) {

    d1 = d1 || new Date();

    var m = d0.getMonth();
    var years = d1.getFullYear() - d0.getFullYear();

    d0.setFullYear(d0.getFullYear() + years);

    if (d0.getMonth() != m) d0.setDate(0);

    return d0 > d1? --years : years;
}

使用momentjs "fromNow"方法， 这允许您使用格式化的日期，例如:03/15/1968

var dob = document.getElementByID（“dob”）; var age = moment（dob.value）.fromNow（true）.replace（“ years”， “”）;

//fromNow(true) =>后缀“ago”不显示 //但是我们还是要去掉“years”;

作为原型版本

String.prototype.getAge = function() {
return moment(this.valueOf()).fromNow(true).replace(" years", "");

}

function age()
{
    var birthdate = $j('#birthDate').val(); // in   "mm/dd/yyyy" format
    var senddate = $j('#expireDate').val(); // in   "mm/dd/yyyy" format
    var x = birthdate.split("/");    
    var y = senddate.split("/");
    var bdays = x[1];
    var bmonths = x[0];
    var byear = x[2];
    //alert(bdays);
    var sdays = y[1];
    var smonths = y[0];
    var syear = y[2];
    //alert(sdays);

    if(sdays < bdays)
    {
        sdays = parseInt(sdays) + 30;
        smonths = parseInt(smonths) - 1;
        //alert(sdays);
        var fdays = sdays - bdays;
        //alert(fdays);
    }
    else{
        var fdays = sdays - bdays;
    }

    if(smonths < bmonths)
    {
        smonths = parseInt(smonths) + 12;
        syear = syear - 1;
        var fmonths = smonths - bmonths;
    }
    else
    {
        var fmonths = smonths - bmonths;
    }

    var fyear = syear - byear;
    document.getElementById('patientAge').value = fyear+' years '+fmonths+' months '+fdays+' days';
}