如果给出格式为YYYYMMDD的出生日期，如何以年计算年龄?是否可以使用Date()函数?
我正在寻找一个比我现在使用的更好的解决方案:
Var dob = '19800810'; var年=数字(dob.)substr (0, 4)); var月=数字(dob.)Substr (4, 2)) - 1; var day =数字(dob.)2) substr(6日); var today = new Date(); var age = today.getFullYear() -年份; if (today.getMonth() < month || (today.getMonth() == month && today.getDate() < day)) { 年龄——; ｝ 警报(年龄);
当前回答
看这个例子，你从这里得到完整的年、月、日信息
function getAge(dateString) {
var today = new Date();
var birthDate = new Date(dateString);
var age = today.getFullYear() - birthDate.getFullYear();
var m = today.getMonth() - birthDate.getMonth();
var da = today.getDate() - birthDate.getDate();
if (m < 0 || (m === 0 && today.getDate() < birthDate.getDate())) {
age--;
}
if(m<0){
m +=12;
}
if(da<0){
da +=30;
}
return age+" years "+ Math.abs(m) + "months"+ Math.abs(da) + " days";
}
alert('age: ' + getAge("1987/08/31"));
[http://jsfiddle.net/tapos00/2g70ue5y/][1]
其他回答
$("#birthday").change(function (){
var val=this.value;
var current_year=new Date().getFullYear();
if(val!=null){
var Split = val.split("-");
var birth_year=parseInt(Split[2]);
if(parseInt(current_year)-parseInt(birth_year)<parseInt(18)){
$("#maritial_status").attr('disabled', 'disabled');
var val2= document.getElementById("maritial_status");
val2.value = "Not Married";
$("#anniversary").attr('disabled', 'disabled');
var val1= document.getElementById("anniversary");
val1.value = "NA";
}else{
$("#maritial_status").attr('disabled', false);
$("#anniversary").attr('disabled', false);
}
}
});
你可以在你的表格中使用这个年龄限制
function dobvalidator(birthDateString){
strs = birthDateString.split("-");
var dd = strs[0];
var mm = strs[1];
var yy = strs[2];
var d = new Date();
var ds = d.getDate();
var ms = d.getMonth();
var ys = d.getFullYear();
var accepted_age = 18;
var days = ((accepted_age * 12) * 30) + (ms * 30) + ds;
var age = (((ys - yy) * 12) * 30) + ((12 - mm) * 30) + parseInt(30 - dd);
if((days - age) <= '0'){
console.log((days - age));
alert('You are at-least ' + accepted_age);
}else{
console.log((days - age));
alert('You are not at-least ' + accepted_age);
}
}
我对之前的答案做了一些更新。
var calculateAge = function(dob) {
var days = function(date) {
return 31*date.getMonth() + date.getDate();
},
d = new Date(dob*1000),
now = new Date();
return now.getFullYear() - d.getFullYear() - ( measureDays(now) < measureDays(d));
}
我希望这对你有所帮助
试试这个。
function getAge(dateString) {
var today = new Date();
var birthDate = new Date(dateString);
var age = today.getFullYear() - birthDate.getFullYear();
var m = today.getMonth() - birthDate.getMonth();
if (m < 0 || (m === 0 && today.getDate() < birthDate.getDate())) {
age--;
}
return age;
}
我相信你的代码中唯一看起来粗糙的是substr部分。
小提琴:http://jsfiddle.net/codeandcloud/n33RJ/
我认为可以简单地像这样:
function age(dateString){
let birth = new Date(dateString);
let now = new Date();
let beforeBirth = ((() => {birth.setDate(now.getDate());birth.setMonth(now.getMonth()); return birth.getTime()})() < birth.getTime()) ? 0 : 1;
return now.getFullYear() - birth.getFullYear() - beforeBirth;
}
age('09/20/1981');
//35
也适用于时间戳
age(403501000000)
//34
