我检查了之前展示的例子，它们并不是在所有情况下都有效，因此我自己写了一个脚本。我测试过了，效果很好。

function getAge(birth) {
   var today = new Date();
   var curr_date = today.getDate();
   var curr_month = today.getMonth() + 1;
   var curr_year = today.getFullYear();

   var pieces = birth.split('/');
   var birth_date = pieces[0];
   var birth_month = pieces[1];
   var birth_year = pieces[2];

   if (curr_month == birth_month && curr_date >= birth_date) return parseInt(curr_year-birth_year);
   if (curr_month == birth_month && curr_date < birth_date) return parseInt(curr_year-birth_year-1);
   if (curr_month > birth_month) return parseInt(curr_year-birth_year);
   if (curr_month < birth_month) return parseInt(curr_year-birth_year-1);
}

var age = getAge('18/01/2011');
alert(age);

这是我修改的尝试(用一个字符串传递给函数而不是一个日期对象):

function calculateAge(dobString) {
    var dob = new Date(dobString);
    var currentDate = new Date();
    var currentYear = currentDate.getFullYear();
    var birthdayThisYear = new Date(currentYear, dob.getMonth(), dob.getDate());
    var age = currentYear - dob.getFullYear();

    if(birthdayThisYear > currentDate) {
        age--;
    }

    return age;
}

和用法:

console.log(calculateAge('1980-01-01'));

这个问题已经超过10年了，没有人回答过提示，他们已经有了YYYYMMDD格式的出生日期?

如果你有一个YYYYMMDD格式的过去日期和当前日期，你可以像这样快速计算它们之间的年数:

var pastDate = '20101030';
var currentDate = '20210622';
var years = Math.floor( ( currentDate - pastDate ) * 0.0001 );
// 10 (10.9592)

你可以得到当前日期格式为YYYYMMDD，如下所示:

var now = new Date();

var currentDate = [
    now.getFullYear(),
    ('0' + (now.getMonth() + 1) ).slice(-2),
    ('0' + now.getDate() ).slice(-2),
].join('');

从naveen和原始OP的帖子中采用，我最终得到了一个可重用的方法存根，它接受字符串和/或JS Date对象。

我将其命名为gregorianAge()，因为这个计算准确地给出了我们如何使用公历表示年龄。即，如果月和日在出生年份的月和日之前，则不计算结束年。

/** * Calculates human age in years given a birth day. Optionally ageAtDate * can be provided to calculate age at a specific date * * @param string|Date Object birthDate * @param string|Date Object ageAtDate optional * @returns integer Age between birthday and a given date or today */ function gregorianAge(birthDate, ageAtDate) { // convert birthDate to date object if already not if (Object.prototype.toString.call(birthDate) !== '[object Date]') birthDate = new Date(birthDate); // use today's date if ageAtDate is not provided if (typeof ageAtDate == "undefined") ageAtDate = new Date(); // convert ageAtDate to date object if already not else if (Object.prototype.toString.call(ageAtDate) !== '[object Date]') ageAtDate = new Date(ageAtDate); // if conversion to date object fails return null if (ageAtDate == null || birthDate == null) return null; var _m = ageAtDate.getMonth() - birthDate.getMonth(); // answer: ageAt year minus birth year less one (1) if month and day of // ageAt year is before month and day of birth year return (ageAtDate.getFullYear()) - birthDate.getFullYear() - ((_m < 0 || (_m === 0 && ageAtDate.getDate() < birthDate.getDate())) ? 1 : 0) } // Below is for the attached snippet function showAge() { $('#age').text(gregorianAge($('#dob').val())) } $(function() { $(".datepicker").datepicker(); showAge(); }); <link rel="stylesheet" href="//code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css"> <script src="//code.jquery.com/jquery-1.10.2.js"></script> <script src="//code.jquery.com/ui/1.11.4/jquery-ui.js"></script> DOB: <input name="dob" value="12/31/1970" id="dob" class="datepicker" onChange="showAge()" /> AGE: <span id="age"><span>

我使用这种方法使用逻辑而不是数学。 它既精确又快速。 参数是这个人生日的年、月和日。 它以整数形式返回这个人的年龄。

function calculateAge(year, month, day) {
        var currentDate = new Date();
        var currentYear = currentDate.getFullYear();
        var currentMonth = currentDate.getUTCMonth() + 1;
        var currentDay = currentDate.getUTCDate();
        // You need to treat the cases where the year, month or day hasn't arrived yet.
        var age = currentYear - year;
        if (currentMonth > month) {
            return age;
        } else {
            if (currentDay >= day) {
                return age;
            } else {
                age--;
                return age;
            }
        }
    }

下面是我能想到的最简单、最准确的解决方案:

Date.prototype.getAge = function (date) {
    if (!date) date = new Date();
    return ~~((date.getFullYear() + date.getMonth() / 100
    + date.getDate() / 10000) - (this.getFullYear() + 
    this.getMonth() / 100 + this.getDate() / 10000));
}

下面是一个考虑每年2月29日至2月28日的例子。

Date.prototype.getAge = function (date) {
    if (!date) date = new Date();
    var feb = (date.getMonth() == 1 || this.getMonth() == 1);
    return ~~((date.getFullYear() + date.getMonth() / 100 + 
        (feb && date.getDate() == 29 ? 28 : date.getDate())
        / 10000) - (this.getFullYear() + this.getMonth() / 100 + 
        (feb && this.getDate() == 29 ? 28 : this.getDate()) 
        / 10000));
}

它甚至适用于负年龄!