你能帮我用SQL语句在多个字段上找到重复吗?
例如,在伪代码中:
select count(field1,field2,field3)
from table
where the combination of field1, field2, field3 occurs multiple times
从上面的语句中,如果有多次出现,我想选择除第一个之外的每一个记录。
你能帮我用SQL语句在多个字段上找到重复吗?
例如,在伪代码中:
select count(field1,field2,field3)
from table
where the combination of field1, field2, field3 occurs multiple times
从上面的语句中,如果有多次出现,我想选择除第一个之外的每一个记录。
当前回答
试试这个查询,每个SELECT语句都有一个单独的计数:
select field1, count(field1) as field1Count, field2,count(field2) as field2Counts, field3, count(field3) as field3Counts
from table_name
group by field1, field2, field3
having count(*) > 1
其他回答
你也可以尝试这个查询来计数一个不同的()列,并根据你想要的列进行排序:
select field1, field2, field3, count(distinct (field2))
from table_name
group by field1, field2, field3
having count(field2) > 1
order by field2;
要查看重复值:
with MYCTE as (
select row_number() over ( partition by name order by name) rown, *
from tmptest
)
select * from MYCTE where rown <=1
尝试此查询以查找多个字段上的重复记录
SELECT a.column1, a.column2
FROM dbo.a a
JOIN (SELECT column1,
column2, count(*) as countC
FROM dbo.a
GROUP BY column4, column5
HAVING count(*) > 1 ) b
ON a.column1 = b.column1
AND a.column2 = b.column2
试试这个查询,每个SELECT语句都有一个单独的计数:
select field1, count(field1) as field1Count, field2,count(field2) as field2Counts, field3, count(field3) as field3Counts
from table_name
group by field1, field2, field3
having count(*) > 1
你提到了“第一个”,所以我假设你对你的数据有某种排序。让我们假设您的数据是按某个字段ID排序的。
这个SQL将为您提供除了第一个以外的重复条目。它基本上选择存在(a)字段相同且(b) ID较低的另一行的所有行。性能不会很好,但可能会解决您的问题。
SELECT A.ID, A.field1, A.field2, A.field3
FROM myTable A
WHERE EXISTS (SELECT B.ID
FROM myTable B
WHERE B.field1 = A.field1
AND B.field2 = A.field2
AND B.field3 = A.field3
AND B.ID < A.ID)