我从对REST服务器的AJAX调用中接收到一个JSON对象。这个对象的属性名与我的TypeScript类相匹配(这是这个问题的后续)。
初始化它的最佳方法是什么?我不认为这将工作,因为类(& JSON对象)的成员是对象的列表和成员是类,而这些类的成员是列表和/或类。
但我更喜欢一种方法,查找成员名和分配他们,创建列表和实例化类的需要,所以我不必为每个类中的每个成员写显式代码(有很多!)
我从对REST服务器的AJAX调用中接收到一个JSON对象。这个对象的属性名与我的TypeScript类相匹配(这是这个问题的后续)。
初始化它的最佳方法是什么?我不认为这将工作,因为类(& JSON对象)的成员是对象的列表和成员是类,而这些类的成员是列表和/或类。
但我更喜欢一种方法,查找成员名和分配他们,创建列表和实例化类的需要,所以我不必为每个类中的每个成员写显式代码(有很多!)
当前回答
对于简单的对象,我喜欢这个方法:
class Person {
constructor(
public id: String,
public name: String,
public title: String) {};
static deserialize(input:any): Person {
return new Person(input.id, input.name, input.title);
}
}
var person = Person.deserialize({id: 'P123', name: 'Bob', title: 'Mr'});
利用在构造函数中定义属性的能力可以使其简洁。
这将为您提供一个类型化对象(与所有使用object的答案相比)。赋值或一些变量,给你一个对象),不需要外部库或装饰器。
其他回答
我的方法略有不同。我没有将属性复制到新的实例中,我只是改变了现有pojo的原型(在旧的浏览器上可能不太好用)。每个类负责提供一个setprototype方法来设置任何子对象的原型,这些子对象反过来提供它们自己的setprototype方法。
(我也使用_Type属性来获取未知对象的类名,但在这里可以忽略)
class ParentClass
{
public ID?: Guid;
public Child?: ChildClass;
public ListOfChildren?: ChildClass[];
/**
* Set the prototypes of all objects in the graph.
* Used for recursive prototype assignment on a graph via ObjectUtils.SetPrototypeOf.
* @param pojo Plain object received from API/JSON to be given the class prototype.
*/
private static SetPrototypes(pojo: ParentClass): void
{
ObjectUtils.SetPrototypeOf(pojo.Child, ChildClass);
ObjectUtils.SetPrototypeOfAll(pojo.ListOfChildren, ChildClass);
}
}
class ChildClass
{
public ID?: Guid;
public GrandChild?: GrandChildClass;
/**
* Set the prototypes of all objects in the graph.
* Used for recursive prototype assignment on a graph via ObjectUtils.SetPrototypeOf.
* @param pojo Plain object received from API/JSON to be given the class prototype.
*/
private static SetPrototypes(pojo: ChildClass): void
{
ObjectUtils.SetPrototypeOf(pojo.GrandChild, GrandChildClass);
}
}
下面是ObjectUtils.ts:
/**
* ClassType lets us specify arguments as class variables.
* (where ClassType == window[ClassName])
*/
type ClassType = { new(...args: any[]): any; };
/**
* The name of a class as opposed to the class itself.
* (where ClassType == window[ClassName])
*/
type ClassName = string & {};
abstract class ObjectUtils
{
/**
* Set the prototype of an object to the specified class.
*
* Does nothing if source or type are null.
* Throws an exception if type is not a known class type.
*
* If type has the SetPrototypes method then that is called on the source
* to perform recursive prototype assignment on an object graph.
*
* SetPrototypes is declared private on types because it should only be called
* by this method. It does not (and must not) set the prototype of the object
* itself - only the protoypes of child properties, otherwise it would cause a
* loop. Thus a public method would be misleading and not useful on its own.
*
* https://stackoverflow.com/questions/9959727/proto-vs-prototype-in-javascript
*/
public static SetPrototypeOf(source: any, type: ClassType | ClassName): any
{
let classType = (typeof type === "string") ? window[type] : type;
if (!source || !classType)
{
return source;
}
// Guard/contract utility
ExGuard.IsValid(classType.prototype, "type", <any>type);
if ((<any>Object).setPrototypeOf)
{
(<any>Object).setPrototypeOf(source, classType.prototype);
}
else if (source.__proto__)
{
source.__proto__ = classType.prototype.__proto__;
}
if (typeof classType["SetPrototypes"] === "function")
{
classType["SetPrototypes"](source);
}
return source;
}
/**
* Set the prototype of a list of objects to the specified class.
*
* Throws an exception if type is not a known class type.
*/
public static SetPrototypeOfAll(source: any[], type: ClassType): void
{
if (!source)
{
return;
}
for (var i = 0; i < source.length; i++)
{
this.SetPrototypeOf(source[i], type);
}
}
}
用法:
let pojo = SomePlainOldJavascriptObjectReceivedViaAjax;
let parentObject = ObjectUtils.SetPrototypeOf(pojo, ParentClass);
// parentObject is now a proper ParentClass instance
**model.ts**
export class Item {
private key: JSON;
constructor(jsonItem: any) {
this.key = jsonItem;
}
}
**service.ts**
import { Item } from '../model/items';
export class ItemService {
items: Item;
constructor() {
this.items = new Item({
'logo': 'Logo',
'home': 'Home',
'about': 'About',
'contact': 'Contact',
});
}
getItems(): Item {
return this.items;
}
}
这是我的方法(非常简单):
const jsonObj: { [key: string]: any } = JSON.parse(jsonStr);
for (const key in jsonObj) {
if (!jsonObj.hasOwnProperty(key)) {
continue;
}
console.log(key); // Key
console.log(jsonObj[key]); // Value
// Your logic...
}
你可以像下面这样做
export interface Instance {
id?:string;
name?:string;
type:string;
}
and
var instance: Instance = <Instance>({
id: null,
name: '',
type: ''
});
我发现最适合这个目的的是类转换器
这就是它的用法:
一些类:
export class Foo {
name: string;
@Type(() => Bar)
bar: Bar;
public someFunction = (test: string): boolean => {
...
}
}
// the docs say "import [this shim] in a global place, like app.ts"
import 'reflect-metadata';
// import this function where you need to use it
import { plainToClass } from 'class-transformer';
export class SomeService {
anyFunction() {
u = plainToClass(Foo, JSONobj);
}
}
如果使用@Type装饰器,也会创建嵌套属性。