我正在寻找一种方法来检测单击事件是否发生在组件之外,如本文所述。jQueryclosest()用于查看单击事件的目标是否将dom元素作为其父元素之一。如果存在匹配项,则单击事件属于其中一个子项,因此不被视为在组件之外。

因此,在我的组件中,我想将一个单击处理程序附加到窗口。当处理程序启动时,我需要将目标与组件的dom子级进行比较。

click事件包含类似“path”的财产,它似乎保存了事件经过的dom路径。我不知道该比较什么,或者如何最好地遍历它,我想肯定有人已经把它放在了一个聪明的效用函数中。。。不


当前回答

您只需在主体上安装一个双击处理程序,并在此元素上安装另一个。在该元素的处理程序中,只需返回false以防止事件传播。因此,当双击发生时,如果它在元素上,它将被捕获,并且不会传播到主体上的处理程序。否则它会被身体上的处理程序抓住。

更新:如果你真的不想阻止事件传播,你只需要使用closest来检查点击是发生在你的元素还是他的一个孩子身上:

<html>
<head>
<script src="https://code.jquery.com/jquery-2.1.4.min.js"></script>
<script>
$(document).on('click', function(event) {
    if (!$(event.target).closest('#div3').length) {
    alert("outside");
    }
});
</script>
</head>
<body>
    <div style="background-color:blue;width:100px;height:100px;" id="div1"></div>
    <div style="background-color:red;width:100px;height:100px;" id="div2"></div>
    <div style="background-color:green;width:100px;height:100px;" id="div3"></div>
    <div style="background-color:yellow;width:100px;height:100px;" id="div4"></div>
    <div style="background-color:grey;width:100px;height:100px;" id="div5"></div>
</body>
</html>

更新:不带jQuery:

<html>
<head>
<script>
function findClosest (element, fn) {
  if (!element) return undefined;
  return fn(element) ? element : findClosest(element.parentElement, fn);
}
document.addEventListener("click", function(event) {
    var target = findClosest(event.target, function(el) {
        return el.id == 'div3'
    });
    if (!target) {
        alert("outside");
    }
}, false);
</script>
</head>
<body>
    <div style="background-color:blue;width:100px;height:100px;" id="div1"></div>
    <div style="background-color:red;width:100px;height:100px;" id="div2"></div>
    <div style="background-color:green;width:100px;height:100px;" id="div3">
        <div style="background-color:pink;width:50px;height:50px;" id="div6"></div>
    </div>
    <div style="background-color:yellow;width:100px;height:100px;" id="div4"></div>
    <div style="background-color:grey;width:100px;height:100px;" id="div5"></div>
</body>
</html>

其他回答

非侵入性方式无需添加另一个DIV EL。

注意:React可能会说findDomNode已弃用,但到目前为止,我还没有遇到任何问题

@异常:单击要忽略的类

@idException:单击时忽略的id

import React from "react"
import ReactDOM from "react-dom"
type Func1<T1, R> = (a1: T1) => R


export function closest(
    el: Element,
    fn: (el: Element) => boolean
  ): Element | undefined {
    let el_: Element | null = el;
  
    while (el_) {
      if (fn(el_)) {
        return el_;
      }
  
      el_ = el_.parentElement;
    }
  }
let instances: ClickOutside[] = []

type Props = {
  idException?: string,
  exceptions?: (string | Func1<MouseEvent, boolean>)[]
  handleClickOutside: Func1<MouseEvent, void>

}


export default class ClickOutside extends React.Component<Props> {
  static defaultProps = {
    exceptions: []
  };

  componentDidMount() {
    if (instances.length === 0) {
      document.addEventListener("mousedown", this.handleAll, true)
      window.parent.document.addEventListener(
        "mousedown",
        this.handleAll,
        true
      )
    }
    instances.push(this)
  }

  componentWillUnmount() {
    instances.splice(instances.indexOf(this), 1)
    if (instances.length === 0) {
      document.removeEventListener("mousedown", this.handleAll, true)
      window.parent.document.removeEventListener(
        "mousedown",
        this.handleAll,
        true
      )
    }
  }

  handleAll = (e: MouseEvent) => {

    const target: HTMLElement = e.target as HTMLElement
    if (!target) return

    instances.forEach(instance => {
      const { exceptions, handleClickOutside: onClickOutside, idException } = instance.props as Required<Props>
      let exceptionsCount = 0

      if (exceptions.length > 0) {
        const { functionExceptions, stringExceptions } = exceptions.reduce(
          (acc, exception) => {
            switch (typeof exception) {
              case "function":
                acc.functionExceptions.push(exception)
                break
              case "string":
                acc.stringExceptions.push(exception)
                break
            }

            return acc
          },
          { functionExceptions: [] as Func1<MouseEvent, boolean>[], stringExceptions: [] as string[] }
        )
        if (functionExceptions.length > 0) {
          exceptionsCount += functionExceptions.filter(
            exception => exception(e) === true
          ).length
        }

        if (exceptionsCount === 0 && stringExceptions.length > 0) {

          const el = closest(target, (e) => stringExceptions.some(ex => e.classList.contains(ex)))
          if (el) {
            exceptionsCount++
          }
        }
      }

      if (idException) {
        const target = e.target as HTMLDivElement
        if (document.getElementById(idException)!.contains(target)) {
          exceptionsCount++
        }
      }

      if (exceptionsCount === 0) {
        // eslint-disable-next-line react/no-find-dom-node
        const node = ReactDOM.findDOMNode(instance)

        if (node && !node.contains(target)) {
          onClickOutside(e)
        }
      }
    })
  };

  render() {
    return React.Children.only(this.props.children)
  }
}

用法

<ClickOutside {...{ handleClickOutside: () => { alert('Clicked Outside') } }}>
    <div >
        <div>Breathe</div>
    </div>
</ClickOutside>

import { useClickAway } from "react-use";

useClickAway(ref, () => console.log('OUTSIDE CLICKED'));

我使用了这个模块(我与作者没有关联)

npm install react-onclickout --save

const ClickOutHandler=require('act-on-clickout');ExampleComponent类扩展React.Component{单击退出(e){if(hasClass(e.target,'忽略我'))返回;alert('用户在组件外部单击!');}render(){返回(<ClickOutHandler onClickOut={this.onClickOut}><div>点击我的外部</分区></ClickOutHandler>);}}

它做得很好。

带钩的字体

注意:我使用的是React 16.3版,带有React.createRef。对于其他版本,使用ref回调。

下拉组件:

interface DropdownProps {
 ...
};

export const Dropdown: React.FC<DropdownProps> () {
  const ref: React.RefObject<HTMLDivElement> = React.createRef();
  
  const handleClickOutside = (event: MouseEvent) => {
    if (ref && ref !== null) {
      const cur = ref.current;
      if (cur && !cur.contains(event.target as Node)) {
        // close all dropdowns
      }
    }
  }

  useEffect(() => {
    // Bind the event listener
    document.addEventListener("mousedown", handleClickOutside);
    return () => {
      // Unbind the event listener on clean up
      document.removeEventListener("mousedown", handleClickOutside);
    };
  });

  return (
    <div ref={ref}>
        ...
    </div>
  );
}

在我的DROPDOWN案例中,Ben Bud的解决方案工作得很好,但我有一个单独的切换按钮和一个onClick处理程序。因此,外部单击逻辑与单击切换按钮冲突。下面是我如何通过传递按钮的ref来解决这个问题:

import React, { useRef, useEffect, useState } from "react";

/**
 * Hook that triggers onClose when clicked outside of ref and buttonRef elements
 */
function useOutsideClicker(ref, buttonRef, onOutsideClick) {
  useEffect(() => {

    function handleClickOutside(event) {
      /* clicked on the element itself */
      if (ref.current && !ref.current.contains(event.target)) {
        return;
      }

      /* clicked on the toggle button */
      if (buttonRef.current && !buttonRef.current.contains(event.target)) {
        return;
      }

      /* If it's something else, trigger onClose */
      onOutsideClick();
    }

    // Bind the event listener
    document.addEventListener("mousedown", handleClickOutside);
    return () => {
      // Unbind the event listener on clean up
      document.removeEventListener("mousedown", handleClickOutside);
    };
  }, [ref]);
}

/**
 * Component that alerts if you click outside of it
 */
export default function DropdownMenu(props) {
  const wrapperRef = useRef(null);
  const buttonRef = useRef(null);
  const [dropdownVisible, setDropdownVisible] = useState(false);

  useOutsideClicker(wrapperRef, buttonRef, closeDropdown);

  const toggleDropdown = () => setDropdownVisible(visible => !visible);

  const closeDropdown = () => setDropdownVisible(false);

  return (
    <div>
      <button onClick={toggleDropdown} ref={buttonRef}>Dropdown Toggler</button>
      {dropdownVisible && <div ref={wrapperRef}>{props.children}</div>}
    </div>
  );
}