我试图将我的新模式转发到我的数据库服务器上,但我不知道为什么我会得到这个错误。

我试图在这里寻找答案,但我所找到的一切都表明,要么将数据库引擎设置为InnoDB,要么确保我试图用作外键的键是它们自己表中的主键。如果我没记错的话,这两件事我都做过。我还能做什么?

Executing SQL script in server

ERROR: Error 1215: Cannot add foreign key constraint

-- -----------------------------------------------------
-- Table `Alternative_Pathways`.`Clients_has_Staff`
-- -----------------------------------------------------
CREATE  TABLE IF NOT EXISTS `Alternative_Pathways`.`Clients_has_Staff` (
  `Clients_Case_Number` INT NOT NULL ,
  `Staff_Emp_ID` INT NOT NULL ,
  PRIMARY KEY (`Clients_Case_Number`, `Staff_Emp_ID`) ,
  INDEX `fk_Clients_has_Staff_Staff1_idx` (`Staff_Emp_ID` ASC) ,
  INDEX `fk_Clients_has_Staff_Clients_idx` (`Clients_Case_Number` ASC) ,
  CONSTRAINT `fk_Clients_has_Staff_Clients`
    FOREIGN KEY (`Clients_Case_Number` )
    REFERENCES `Alternative_Pathways`.`Clients` (`Case_Number` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION,
  CONSTRAINT `fk_Clients_has_Staff_Staff1`
    FOREIGN KEY (`Staff_Emp_ID` )
    REFERENCES `Alternative_Pathways`.`Staff` (`Emp_ID` )
    ON DELETE NO ACTION
    ON UPDATE NO ACTION)
ENGINE = InnoDB

SQL脚本执行完成:语句:7成功,1失败

下面是父表的SQL。

CREATE  TABLE IF NOT EXISTS `Alternative_Pathways`.`Clients` (
  `Case_Number` INT NOT NULL ,
  `First_Name` CHAR(10) NULL ,
  `Middle_Name` CHAR(10) NULL ,
  `Last_Name` CHAR(10) NULL ,
  `Address` CHAR(50) NULL ,
  `Phone_Number` INT(10) NULL ,
  PRIMARY KEY (`Case_Number`) )
ENGINE = InnoDB

CREATE  TABLE IF NOT EXISTS `Alternative_Pathways`.`Staff` (
  `Emp_ID` INT NOT NULL ,
  `First_Name` CHAR(10) NULL ,
  `Middle_Name` CHAR(10) NULL ,
  `Last_Name` CHAR(10) NULL ,
  PRIMARY KEY (`Emp_ID`) )
ENGINE = InnoDB

当前回答

在我的情况下,我不得不禁用外键检查,因为源表不存在。

设置FOREIGN_KEY_CHECKS = 0;

其他回答

In my case, I had deleted a table using SET FOREIGN_KEY_CHECKS=0, then SET FOREIGN_KEY_CHECKS=1 after. When I went to reload the table, I got error 1215. The problem was there was another table in the database that had a foreign key to the table I had deleted and was reloading. Part of the reloading process involved changing a data type for one of the fields, which made the foreign key from the other table invalid, thus triggering error 1215. I resolved the problem by dropping and then reloading the other table with the new data type for the involved field.

我经历这个错误的原因完全不同。我使用MySQL Workbench 6.3创建我的数据模型(很棒的工具)。我注意到,当外键约束定义中定义的列顺序不符合表列顺序时,也会生成此错误。

我花了大约4个小时的时间尝试了所有其他方法,就是没能确认。

现在一切正常,我可以继续编码了。:-)

喔,我刚明白!这是许多已经发布的答案(InnoDB, unsigned等)的混合。

但我在这里没有看到的一点是:如果外键指向主键,请确保源列具有有意义的值。例如,如果主键是一个mediumint(8),请确保源列也包含一个mediumint(8)。这是我的问题之一。

你可能会得到外键约束错误的原因:

You are not using InnoDB as the engine on all tables. You are trying to reference a nonexistent key on the target table. Make sure it is a key on the other table (it can be a primary or unique key, or just a key) The types of the columns are not the same (an exception is the column on the referencing table can be nullable even if it is not nullable in the referenced table). If the primary key or foreign key is a varchar, make sure the collation is the same for both. One of the reasons may also be that the column you are using for ON DELETE SET NULL is not defined to be null. So make sure that the column is set default null.

检查这些。

检查表格的排列顺序。使用SHOW TABLE STATUS,可以检查表的信息,包括排序规则。

两个表必须具有相同的排序规则。

这种事发生在我身上。