我经常需要根据值对字典(由键和值组成)进行排序。例如,我有一个单词和相应频率的散列,我想按频率排序。

有一个SortedList,它适用于单个值(比如频率),我想把它映射回单词。

SortedDictionary按键排序,而不是按值。有些人求助于自定义课程,但有没有更干净的方法呢?


当前回答

分类打印:

var items = from pair in players_Dic
                orderby pair.Value descending
                select pair;

// Display results.
foreach (KeyValuePair<string, int> pair in items)
{
    Debug.Log(pair.Key + " - " + pair.Value);
}

将降序改为升序以改变排序顺序

其他回答

使用LINQ:

Dictionary<string, int> myDict = new Dictionary<string, int>();
myDict.Add("one", 1);
myDict.Add("four", 4);
myDict.Add("two", 2);
myDict.Add("three", 3);

var sortedDict = from entry in myDict orderby entry.Value ascending select entry;

这也为你提供了很大的灵活性,你可以选择前10%,20 - 10%等等。或者,如果您正在使用词频索引进行提前输入,您还可以包括StartsWith子句。

获得一个排序字典最简单的方法是使用内置的SortedDictionary类:

//Sorts sections according to the key value stored on "sections" unsorted dictionary, which is passed as a constructor argument
System.Collections.Generic.SortedDictionary<int, string> sortedSections = null;
if (sections != null)
{
    sortedSections = new SortedDictionary<int, string>(sections);
}

sortedSections将包含section的排序版本

你可以用:

Dictionary<string, string> dic= new Dictionary<string, string>();
var ordered = dic.OrderBy(x => x.Value);
return ordered.ToDictionary(t => t.Key, t => t.Value);

所需的命名空间:使用System.Linq;

Dictionary<string, int> counts = new Dictionary<string, int>();
counts.Add("one", 1);
counts.Add("four", 4);
counts.Add("two", 2);
counts.Add("three", 3);

按描述排序:

foreach (KeyValuePair<string, int> kvp in counts.OrderByDescending(key => key.Value))
{
// some processing logic for each item if you want.
}

按Asc排序:

foreach (KeyValuePair<string, int> kvp in counts.OrderBy(key => key.Value))
{
// some processing logic for each item if you want.
}

使用VB对SortedDictionary列表进行排序以绑定到ListView控件。NET:

Dim MyDictionary As SortedDictionary(Of String, MyDictionaryEntry)

MyDictionaryListView.ItemsSource = MyDictionary.Values.OrderByDescending(Function(entry) entry.MyValue)

Public Class MyDictionaryEntry ' Need Property for GridViewColumn DisplayMemberBinding
    Public Property MyString As String
    Public Property MyValue As Integer
End Class

XAML:

<ListView Name="MyDictionaryListView">
    <ListView.View>
        <GridView>
            <GridViewColumn DisplayMemberBinding="{Binding Path=MyString}" Header="MyStringColumnName"></GridViewColumn>
            <GridViewColumn DisplayMemberBinding="{Binding Path=MyValue}" Header="MyValueColumnName"></GridViewColumn>
         </GridView>
    </ListView.View>
</ListView>