function filterObject(obj) {
    for (var propName in obj) {
        if (!(obj[propName] || obj[propName] === false)) {
            delete obj[propName];
        }
    }

    return obj;
}

这个函数也从对象中删除NaN值，很容易理解

函数式和不可变的方法，不需要.filter，也不需要创建超出需要的对象

Object.keys(obj).reduce((acc, key) => (obj[key] === undefined ? acc : {...acc, [key]: obj[key]}), {})

您可以使用JSON的组合。stringify，它的替换参数，以及JSON。解析将其转换回对象。使用此方法还意味着替换嵌套对象中的所有嵌套键。

实例对象

var exampleObject = {
  string: 'value',
  emptyString: '',
  integer: 0,
  nullValue: null,
  array: [1, 2, 3],
  object: {
    string: 'value',
    emptyString: '',
    integer: 0,
    nullValue: null,
    array: [1, 2, 3]
  },
  arrayOfObjects: [
    {
      string: 'value',
      emptyString: '',
      integer: 0,
      nullValue: null,
      array: [1, 2, 3]
    },
    {
      string: 'value',
      emptyString: '',
      integer: 0,
      nullValue: null,
      array: [1, 2, 3]
    }
  ]
};

替代者函数

function replaceUndefinedOrNull(key, value) {
  if (value === null || value === undefined) {
    return undefined;
  }

  return value;
}

清洁物体

exampleObject = JSON.stringify(exampleObject, replaceUndefinedOrNull);
exampleObject = JSON.parse(exampleObject);

CodePen例子

ES6 arrow function and ternary operator:
Object.entries(obj).reduce((acc, entry) => {
   const [key, value] = entry
  if (value !== undefined) acc[key] = value;
  return acc;
}, {})


    const obj = {test:undefined, test1:1 ,test12:0, test123:false};
    const newObj = Object.entries(obj).reduce((acc, entry) => {
       const [key, value] = entry
      if (value !== undefined) acc[key] = value;
      return acc;
    }, {})
    console.log(newObj)

TypeScript的泛型函数

function cleanProps(object:Record<string, string>):Record<string, string> {
  let cleanObj = {};

  Object.keys(object).forEach((key) => {
    const property = object[key];
    cleanObj = property ? { ...cleanObj, [key]: property } : cleanObj;
  });

  return cleanObj;
}

export default cleanProps;

现在假设你有一个像下面这样的对象

interface Filters{
 searchString: string;
 location: string;
 sector: string
}

const filters:Filters = {
  searchString: 'cute cats',
  location: '',
  sector: 'education',
};

您可以按照如下方式使用该函数

const result = cleanProps(filters as Record<keyof Filters, string>);
console.log(result); // outputs: { searchString: 'cute cats', sector: 'education' }

您可能正在寻找delete关键字。

var obj = { };
obj.theProperty = 1;
delete obj.theProperty;