我有问题理解如何使用Python电子邮件附件。我已经成功地通过smtplib电子邮件发送了简单的消息。有人能解释一下如何在电子邮件中发送附件吗?我知道网上还有其他的帖子,但作为一个Python初学者,我发现它们很难理解。
当前回答
其他的答案也很好,但我还是想分享一种不同的方法,以防有人正在寻找替代方案。
主要的区别是,使用这种方法,你可以使用HTML/CSS来格式化你的邮件,所以你可以有创意,给你的电子邮件一些样式。虽然没有强制使用HTML,但仍然可以只使用纯文本。
注意,该函数接受将电子邮件发送给多个收件人,也允许附加多个文件。
我只在python2上尝试过,但我认为它在python3上也能正常工作:
import os.path
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.application import MIMEApplication
def send_email(subject, message, from_email, to_email=[], attachment=[]):
"""
:param subject: email subject
:param message: Body content of the email (string), can be HTML/CSS or plain text
:param from_email: Email address from where the email is sent
:param to_email: List of email recipients, example: ["a@a.com", "b@b.com"]
:param attachment: List of attachments, exmaple: ["file1.txt", "file2.txt"]
"""
msg = MIMEMultipart()
msg['Subject'] = subject
msg['From'] = from_email
msg['To'] = ", ".join(to_email)
msg.attach(MIMEText(message, 'html'))
for f in attachment:
with open(f, 'rb') as a_file:
basename = os.path.basename(f)
part = MIMEApplication(a_file.read(), Name=basename)
part['Content-Disposition'] = 'attachment; filename="%s"' % basename
msg.attach(part)
email = smtplib.SMTP('your-smtp-host-name.com')
email.sendmail(from_email, to_email, msg.as_string())
我希望这能有所帮助!: -)
其他回答
其他的答案也很好,但我还是想分享一种不同的方法,以防有人正在寻找替代方案。
主要的区别是,使用这种方法,你可以使用HTML/CSS来格式化你的邮件,所以你可以有创意,给你的电子邮件一些样式。虽然没有强制使用HTML,但仍然可以只使用纯文本。
注意,该函数接受将电子邮件发送给多个收件人,也允许附加多个文件。
我只在python2上尝试过,但我认为它在python3上也能正常工作:
import os.path
import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.application import MIMEApplication
def send_email(subject, message, from_email, to_email=[], attachment=[]):
"""
:param subject: email subject
:param message: Body content of the email (string), can be HTML/CSS or plain text
:param from_email: Email address from where the email is sent
:param to_email: List of email recipients, example: ["a@a.com", "b@b.com"]
:param attachment: List of attachments, exmaple: ["file1.txt", "file2.txt"]
"""
msg = MIMEMultipart()
msg['Subject'] = subject
msg['From'] = from_email
msg['To'] = ", ".join(to_email)
msg.attach(MIMEText(message, 'html'))
for f in attachment:
with open(f, 'rb') as a_file:
basename = os.path.basename(f)
part = MIMEApplication(a_file.read(), Name=basename)
part['Content-Disposition'] = 'attachment; filename="%s"' % basename
msg.attach(part)
email = smtplib.SMTP('your-smtp-host-name.com')
email.sendmail(from_email, to_email, msg.as_string())
我希望这能有所帮助!: -)
from email.mime.multipart import MIMEMultipart
from email.mime.image import MIMEImage
from email.mime.text import MIMEText
import smtplib
msg = MIMEMultipart()
password = "password"
msg['From'] = "from_address"
msg['To'] = "to_address"
msg['Subject'] = "Attached Photo"
msg.attach(MIMEImage(file("abc.jpg").read()))
file = "file path"
fp = open(file, 'rb')
img = MIMEImage(fp.read())
fp.close()
msg.attach(img)
server = smtplib.SMTP('smtp.gmail.com: 587')
server.starttls()
server.login(msg['From'], password)
server.sendmail(msg['From'], msg['To'], msg.as_string())
server.quit()
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText
from email.MIMEImage import MIMEImage
import smtplib
msg = MIMEMultipart()
msg.attach(MIMEText(file("text.txt").read()))
msg.attach(MIMEImage(file("image.png").read()))
# to send
mailer = smtplib.SMTP()
mailer.connect()
mailer.sendmail(from_, to, msg.as_string())
mailer.close()
从这里改编。
下面是Oli为python3编写的修改版本
import smtplib
from pathlib import Path
from email.mime.multipart import MIMEMultipart
from email.mime.base import MIMEBase
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
from email import encoders
def send_mail(send_from, send_to, subject, message, files=[],
server="localhost", port=587, username='', password='',
use_tls=True):
"""Compose and send email with provided info and attachments.
Args:
send_from (str): from name
send_to (list[str]): to name(s)
subject (str): message title
message (str): message body
files (list[str]): list of file paths to be attached to email
server (str): mail server host name
port (int): port number
username (str): server auth username
password (str): server auth password
use_tls (bool): use TLS mode
"""
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = COMMASPACE.join(send_to)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach(MIMEText(message))
for path in files:
part = MIMEBase('application', "octet-stream")
with open(path, 'rb') as file:
part.set_payload(file.read())
encoders.encode_base64(part)
part.add_header('Content-Disposition',
'attachment; filename={}'.format(Path(path).name))
msg.attach(part)
smtp = smtplib.SMTP(server, port)
if use_tls:
smtp.starttls()
smtp.login(username, password)
smtp.sendmail(send_from, send_to, msg.as_string())
smtp.quit()
我知道这是一个老问题,但我认为一定有一种比其他例子更简单的方法来做到这一点,因此我做了一个库,在不污染代码库的情况下干净地解决这个问题。包含附件非常简单:
from redmail import EmailSender
from pathlib import Path
# Configure an email sender
email = EmailSender(
host="<SMTP HOST>", port=0,
user_name="me@example.com", password="<PASSWORD>"
)
# Send an email
email.send(
sender="me@example.com",
receivers=["you@example.com"],
subject="An example email"
attachments={
"myfile.txt": Path("path/to/a_file.txt"),
"myfile.html": "<h1>Content of a HTML attachment</h1>"
}
)
你也可以直接附加字节,Pandas DataFrame(根据键中的文件扩展名转换为格式),Matplotlib图或枕头图像。这个库很可能是你需要一个电子邮件发送者的所有功能(它比附件要多得多)。
如何安装:
pip install redmail
你喜欢怎么用就怎么用。我还写了大量的文档:https://red-mail.readthedocs.io/en/latest/
推荐文章
- Visual Studio Code:如何调试Python脚本的参数
- 使用元组/列表等等。从输入vs直接引用类型如list/tuple/etc
- 结合conda环境。Yml和PIP requirements.txt
- 将命名元组转换为字典
- 如何使x轴和y轴的刻度相等呢?
- Numpy在这里函数多个条件
- 在Python中,使用argparse只允许正整数
- 如何从终端机发送电子邮件?
- 如何排序mongodb与pymongo
- 不可变与可变类型
- 列表是线程安全的吗?
- 操作系统。makdirs在我的路径上不理解“~”
- 如何在Django模板中获得我的网站的域名?
- 在django Forms中定义css类
- 如何在Python中scp ?