在Go中,我只想要一个随机字符串(大写或小写),没有数字。最快最简单的方法是什么?


当前回答

如果您愿意向允许的字符池中添加一些字符,您可以使代码与任何通过io.Reader提供随机字节的东西一起工作。这里我们使用的是crypto/rand。

// len(encodeURL) == 64. This allows (x <= 265) x % 64 to have an even
// distribution.
const encodeURL = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_"

// A helper function create and fill a slice of length n with characters from
// a-zA-Z0-9_-. It panics if there are any problems getting random bytes.
func RandAsciiBytes(n int) []byte {
    output := make([]byte, n)

    // We will take n bytes, one byte for each character of output.
    randomness := make([]byte, n)

    // read all random
    _, err := rand.Read(randomness)
    if err != nil {
        panic(err)
    }

    // fill output
    for pos := range output {
        // get random item
        random := uint8(randomness[pos])

        // random % 64
        randomPos := random % uint8(len(encodeURL))

        // put into output
        output[pos] = encodeURL[randomPos]
    }

    return output
}

其他回答

package main

import (
    "encoding/base64"
    "fmt"
    "math/rand"
    "time"
)

// customEncodeURL is like `bas64.encodeURL` 
// except its made up entirely of uppercase characters:
const customEncodeURL = "ABCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKL"

// Random generates a random string.
// It is not cryptographically secure.
func Random(n int) string {
    b := make([]byte, n)
    rand.Seed(time.Now().UnixNano())
    _, _ = rand.Read(b) // docs say that it always returns a nil error.

    customEncoding := base64.NewEncoding(customEncodeURL).WithPadding(base64.NoPadding)
    return customEncoding.EncodeToString(b)
}

func main() {
    fmt.Println(Random(16))
}

如果您愿意向允许的字符池中添加一些字符,您可以使代码与任何通过io.Reader提供随机字节的东西一起工作。这里我们使用的是crypto/rand。

// len(encodeURL) == 64. This allows (x <= 265) x % 64 to have an even
// distribution.
const encodeURL = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_"

// A helper function create and fill a slice of length n with characters from
// a-zA-Z0-9_-. It panics if there are any problems getting random bytes.
func RandAsciiBytes(n int) []byte {
    output := make([]byte, n)

    // We will take n bytes, one byte for each character of output.
    randomness := make([]byte, n)

    // read all random
    _, err := rand.Read(randomness)
    if err != nil {
        panic(err)
    }

    // fill output
    for pos := range output {
        // get random item
        random := uint8(randomness[pos])

        // random % 64
        randomPos := random % uint8(len(encodeURL))

        // put into output
        output[pos] = encodeURL[randomPos]
    }

    return output
}
func Rand(n int) (str string) {
    b := make([]byte, n)
    rand.Read(b)
    str = fmt.Sprintf("%x", b)
    return
}

这是我的方式)使用数学兰特或加密兰特如你所愿。

func randStr(len int) string {
    buff := make([]byte, len)
    rand.Read(buff)
    str := base64.StdEncoding.EncodeToString(buff)
    // Base 64 can be longer than len
    return str[:len]
}
const (
    chars       = "0123456789_abcdefghijkl-mnopqrstuvwxyz" //ABCDEFGHIJKLMNOPQRSTUVWXYZ
    charsLen    = len(chars)
    mask        = 1<<6 - 1
)

var rng = rand.NewSource(time.Now().UnixNano())

// RandStr 返回指定长度的随机字符串
func RandStr(ln int) string {
    /* chars 38个字符
     * rng.Int63() 每次产出64bit的随机数,每次我们使用6bit(2^6=64) 可以使用10次
     */
    buf := make([]byte, ln)
    for idx, cache, remain := ln-1, rng.Int63(), 10; idx >= 0; {
        if remain == 0 {
            cache, remain = rng.Int63(), 10
        }
        buf[idx] = chars[int(cache&mask)%charsLen]
        cache >>= 6
        remain--
        idx--
    }
    return *(*string)(unsafe.Pointer(&buf))
}

基准RandStr16-8 20000000 68.1 ns/op 16 B/op 1 分配/操作