在Go中,我只想要一个随机字符串(大写或小写),没有数字。最快最简单的方法是什么?


当前回答

简单的解决方案,最少重复的结果:

import (
    "fmt"
    "math/rand"
    "time"
)

func randomString(length int) string {
    rand.Seed(time.Now().UnixNano())
    b := make([]byte, length+2)
    rand.Read(b)
    return fmt.Sprintf("%x", b)[2 : length+2]
}

在操场上看看

其他回答

另一个版本,灵感来自于生成密码在JavaScript加密:

package main

import (
    "crypto/rand"
    "fmt"
)

var chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890-"

func shortID(length int) string {
    ll := len(chars)
    b := make([]byte, length)
    rand.Read(b) // generates len(b) random bytes
    for i := 0; i < length; i++ {
        b[i] = chars[int(b[i])%ll]
    }
    return string(b)
}

func main() {
    fmt.Println(shortID(18))
    fmt.Println(shortID(18))
    fmt.Println(shortID(18))
}

这是我的方式)使用数学兰特或加密兰特如你所愿。

func randStr(len int) string {
    buff := make([]byte, len)
    rand.Read(buff)
    str := base64.StdEncoding.EncodeToString(buff)
    // Base 64 can be longer than len
    return str[:len]
}
package main

import (
    "encoding/base64"
    "fmt"
    "math/rand"
    "time"
)

// customEncodeURL is like `bas64.encodeURL` 
// except its made up entirely of uppercase characters:
const customEncodeURL = "ABCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKL"

// Random generates a random string.
// It is not cryptographically secure.
func Random(n int) string {
    b := make([]byte, n)
    rand.Seed(time.Now().UnixNano())
    _, _ = rand.Read(b) // docs say that it always returns a nil error.

    customEncoding := base64.NewEncoding(customEncodeURL).WithPadding(base64.NoPadding)
    return customEncoding.EncodeToString(b)
}

func main() {
    fmt.Println(Random(16))
}

如果需要选择是否大写,我通常会这样做

func randomString(length int, upperCase bool) string {
    rand.Seed(time.Now().UnixNano())

    var alphabet string

    if upperCase {
        alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    } else {
        alphabet = "abcdefghijklmnopqrstuvwxyz"
    }

    var sb strings.Builder

    l := len(alphabet)

    for i := 0; i < length; i++ {
        c := alphabet[rand.Intn(l)]
        sb.WriteByte(c)
    }

    return sb.String()
}

如果不需要大写字母,就像这样

func randomString(length int) string {
        rand.Seed(time.Now().UnixNano())

        var alphabet string = "abcdefghijklmnopqrstuvwxyz"
        var sb strings.Builder

        l := len(alphabet)

        for i := 0; i < length; i++ {
                c := alphabet[rand.Intn(l)]
                sb.WriteByte(c)
        }

        return sb.String()
}

你可以为它编写代码。如果您希望使用UTF-8编码时所有字母都是单个字节,则此代码可以稍微简单一些。

package main

import (
    "fmt"
    "time"
    "math/rand"
)

var letters = []rune("abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ")

func randSeq(n int) string {
    b := make([]rune, n)
    for i := range b {
        b[i] = letters[rand.Intn(len(letters))]
    }
    return string(b)
}

func main() {
    rand.Seed(time.Now().UnixNano())

    fmt.Println(randSeq(10))
}