它是可能的，在PHP中，在不使用递归或引用的情况下扁平化(bi/multi)维数组?
我只对值感兴趣，所以键可以忽略，我认为在array_map()和array_values()的行。
当前回答
如果你想保留中间键:
function flattenArray(array &$result, $value, string $key = "")
{
if (!is_array($value)) {
$result[$key] = $value;
return $result;
}
foreach ($value as $subKey => $subArray) {
$newKey = $key !== "" ? $key . "_" . $subKey : $subKey;
flattenArray($result, $subArray, $newKey);
}
return $result;
}
$nestedArray = [
"name" => "John",
"pets" => [
["id" => 1, "name" => "snooop"],
["id" => 2, "name" => "medor"],
],
"job" => ["title" => "developper"],
];
$intermediateResult = [];
$flattened = flattenArray($intermediateResult, $nestedArray);
var_dump($flattened);
这将输出:
array(6) {
["name"]=>
string(4) "John"
["pets_0_id"]=>
int(1)
["pets_0_name"]=>
string(6) "snooop"
["pets_1_id"]=>
int(2)
["pets_1_name"]=>
string(5) "medor"
["job_title"]=>
string(10) "developper"
}
看到https://ideone.com/KXLtzZ stdout
其他回答
诀窍是通过引用传递源数组和目标数组。
function flatten_array(&$arr, &$dst) {
if(!isset($dst) || !is_array($dst)) {
$dst = array();
}
if(!is_array($arr)) {
$dst[] = $arr;
} else {
foreach($arr as &$subject) {
flatten_array($subject, $dst);
}
}
}
$recursive = array('1', array('2','3',array('4',array('5','6')),'7',array(array(array('8'),'9'),'10')));
echo "Recursive: \r\n";
print_r($recursive);
$flat = null;
flatten_array($recursive, $flat);
echo "Flat: \r\n";
print_r($flat);
// If you change line 3 to $dst[] = &$arr; , you won't waste memory,
// since all you're doing is copying references, and imploding the array
// into a string will be both memory efficient and fast:)
echo "String:\r\n";
echo implode(',',$flat);
您可以使用标准PHP库(SPL)来“隐藏”递归。
$a = array(1,2,array(3,4, array(5,6,7), 8), 9);
$it = new RecursiveIteratorIterator(new RecursiveArrayIterator($a));
foreach($it as $v) {
echo $v, " ";
}
打印
1 2 3 4 5 6 7 8 9
从PHP 5.3开始，最短的解决方案似乎是array_walk_recursive()与新的闭包语法:
function flatten(array $array) {
$return = array();
array_walk_recursive($array, function($a) use (&$return) { $return[] = $a; });
return $return;
}
简单明了的回答。
function flatten_array(array $array)
{
return iterator_to_array(
new \RecursiveIteratorIterator(new \RecursiveArrayIterator($array)));
}
用法:
$array = [
'name' => 'Allen Linatoc',
'profile' => [
'age' => 21,
'favourite_games' => [ 'Call of Duty', 'Titanfall', 'Far Cry' ]
]
];
print_r( flatten_array($array) );
输出(在PsySH):
Array
(
[name] => Allen Linatoc
[age] => 21
[0] => Call of Duty
[1] => Titanfall
[2] => Far Cry
)
现在就看你怎么处理钥匙了。干杯
编辑(2017-03-01)
引用Nigel Alderton的担忧/问题:
澄清一下，这保留了键(甚至是数字键)，因此具有相同键的值将丢失。例如数组美元= [a, [' b ', ' c ']]成为数组([0]= > b, c[1] = >)。“a”丢失了，因为“b”也有一个键值为0
引用Svish的回答:
只需将false作为第二个参数($use_keys)添加到iterator_to_array调用中
如果你想保留中间键:
function flattenArray(array &$result, $value, string $key = "")
{
if (!is_array($value)) {
$result[$key] = $value;
return $result;
}
foreach ($value as $subKey => $subArray) {
$newKey = $key !== "" ? $key . "_" . $subKey : $subKey;
flattenArray($result, $subArray, $newKey);
}
return $result;
}
$nestedArray = [
"name" => "John",
"pets" => [
["id" => 1, "name" => "snooop"],
["id" => 2, "name" => "medor"],
],
"job" => ["title" => "developper"],
];
$intermediateResult = [];
$flattened = flattenArray($intermediateResult, $nestedArray);
var_dump($flattened);
这将输出:
array(6) {
["name"]=>
string(4) "John"
["pets_0_id"]=>
int(1)
["pets_0_name"]=>
string(6) "snooop"
["pets_1_id"]=>
int(2)
["pets_1_name"]=>
string(5) "medor"
["job_title"]=>
string(10) "developper"
}
看到https://ideone.com/KXLtzZ stdout
