这个版本可以做深层、浅层或特定数量的层:

/**
 * @param  array|object $array  array of mixed values to flatten
 * @param  int|boolean  $level  0:deep, 1:shallow, 2:2 levels, 3...
 * @return array
 */
function flatten($array, $level = 0) {
    $level = (int) $level;
    $result = array();
    foreach ($array as $i => $v) {
        if (0 <= $level && is_array($v)) {
            $v = flatten($v, $level > 1 ? $level - 1 : 0 - $level);
            $result = array_merge($result, $v);
        } elseif (is_int($i)) {
            $result[] = $v;
        } else {
            $result[$i] = $v; 
        }
    }
    return $result;
}

这个解是非递归的。注意，元素的顺序会有些混合。

function flatten($array) {
    $return = array();
    while(count($array)) {
        $value = array_shift($array);
        if(is_array($value))
            foreach($value as $sub)
                $array[] = $sub;
        else
            $return[] = $value;
    }
    return $return;
}

试试下面这个简单的函数:

function _flatten_array($arr) {
  while ($arr) {
    list($key, $value) = each($arr); 
    is_array($value) ? $arr = $value : $out[$key] = $value;
    unset($arr[$key]);
  }
  return (array)$out;
}

所以从这里:

array (
  'und' => 
  array (
    'profiles' => 
    array (
      0 => 
      array (
        'commerce_customer_address' => 
        array (
          'und' => 
          array (
            0 => 
            array (
              'first_name' => 'First name',
              'last_name' => 'Last name',
              'thoroughfare' => 'Address 1',
              'premise' => 'Address 2',
              'locality' => 'Town/City',
              'administrative_area' => 'County',
              'postal_code' => 'Postcode',
            ),
          ),
        ),
      ),
    ),
  ),
)

你会得到:

array (
  'first_name' => 'First name',
  'last_name' => 'Last name',
  'thoroughfare' => 'Address 1',
  'premise' => 'Address 2',
  'locality' => 'Town/City',
  'administrative_area' => 'County',
  'postal_code' => 'Postcode',
)

如果你想保住你的钥匙，那就是解决办法。

function flatten(array $array) {
    $return = array();
    array_walk_recursive($array, function($value, $key) use (&$return) { $return[$key] = $value; });
    return $return;
}

不幸的是，它只输出最后的嵌套数组，没有中间键。对于下面的例子:

$array = array(
    'sweet' => array(
        'a' => 'apple',
        'b' => 'banana'),
    'sour' => 'lemon'); 
print_r(flatten($fruits));

输出是:

Array
(
    [a] => apple
    [b] => banana
    [sour] => lemon
)

我需要用HTML输入格式表示PHP多维数组。

$test = [
    'a' => [
        'b' => [
            'c' => ['a', 'b']
        ]
    ],
    'b' => 'c',
    'c' => [
        'd' => 'e'
    ]
];

$flatten = function ($input, $parent = []) use (&$flatten) {
    $return = [];

    foreach ($input as $k => $v) {
        if (is_array($v)) {
            $return = array_merge($return, $flatten($v, array_merge($parent, [$k])));
        } else {
            if ($parent) {
                $key = implode('][', $parent) . '][' . $k . ']';

                if (substr_count($key, ']') != substr_count($key, '[')) {
                    $key = preg_replace('/\]/', '', $key, 1);
                }
            } else {
                $key = $k;
            }           

            $return[$key] = $v;
        }
    }

    return $return;
};

die(var_dump( $flatten($test) ));

array(4) {
  ["a[b][c][0]"]=>
  string(1) "a"
  ["a[b][c][1]"]=>
  string(1) "b"
  ["b"]=>
  string(1) "c"
  ["c[d]"]=>
  string(1) "e"
}

使用递归。希望在看到它有多简单的时候，你对递归的恐惧会在你看到它有多简单的时候消失。

function flatten($array) {
    if (!is_array($array)) {
        // nothing to do if it's not an array
        return array($array);
    }

    $result = array();
    foreach ($array as $value) {
        // explode the sub-array, and add the parts
        $result = array_merge($result, flatten($value));
    }

    return $result;
}


$arr = array('foo', array('nobody', 'expects', array('another', 'level'), 'the', 'Spanish', 'Inquisition'), 'bar');
echo '<ul>';
foreach (flatten($arr) as $value) {
    echo '<li>', $value, '</li>';
}
echo '<ul>';

输出:

<ul><li>foo</li><li>nobody</li><li>expects</li><li>another</li><li>level</li><li>the</li><li>Spanish</li><li>Inquisition</li><li>bar</li><ul>