扁平化数组的Laravel助手是Arr::flatten()

我需要用HTML输入格式表示PHP多维数组。

$test = [
    'a' => [
        'b' => [
            'c' => ['a', 'b']
        ]
    ],
    'b' => 'c',
    'c' => [
        'd' => 'e'
    ]
];

$flatten = function ($input, $parent = []) use (&$flatten) {
    $return = [];

    foreach ($input as $k => $v) {
        if (is_array($v)) {
            $return = array_merge($return, $flatten($v, array_merge($parent, [$k])));
        } else {
            if ($parent) {
                $key = implode('][', $parent) . '][' . $k . ']';

                if (substr_count($key, ']') != substr_count($key, '[')) {
                    $key = preg_replace('/\]/', '', $key, 1);
                }
            } else {
                $key = $k;
            }           

            $return[$key] = $v;
        }
    }

    return $return;
};

die(var_dump( $flatten($test) ));

array(4) {
  ["a[b][c][0]"]=>
  string(1) "a"
  ["a[b][c][1]"]=>
  string(1) "b"
  ["b"]=>
  string(1) "c"
  ["c[d]"]=>
  string(1) "e"
}

扁平化数组的Laravel助手是Arr::flatten()

我只是想指出这是一个折叠，所以可以使用array_reduce

array_reduce($my_array, 'array_merge', array());

编辑:注意，这可以组成平任意数量的水平。我们可以通过以下几种方式做到这一点:

// Reduces one level
$concat   = function($x) { return array_reduce($x, 'array_merge', array()); };

// We can compose $concat with itself $n times, then apply it to $x
// This can overflow the stack for large $n
$compose  = function($f, $g) {
    return function($x) use ($f, $g) { return $f($g($x)); };
};
$identity = function($x) { return $x; };
$flattenA = function($n) use ($compose, $identity, $concat) {
    return  function($x) use ($compose, $identity, $concat, $n) {
        return ($n === 0)? $x
                         : call_user_func(array_reduce(array_fill(0, $n, $concat),
                                                       $compose,
                                                       $identity),
                                          $x);
    };
};

// We can iteratively apply $concat to $x, $n times
$uncurriedFlip     = function($f) {
    return  function($a, $b) use ($f) {
        return $f($b, $a);
    };
};
$iterate  = function($f) use ($uncurriedFlip) {
    return  function($n) use ($uncurriedFlip, $f) {
    return  function($x) use ($uncurriedFlip, $f, $n) {
        return ($n === 0)? $x
                         : array_reduce(array_fill(0, $n, $f),
                                        $uncurriedFlip('call_user_func'),
                                        $x);
    }; };
};
$flattenB = $iterate($concat);

// Example usage:
$apply    = function($f, $x) {
    return $f($x);
};
$curriedFlip = function($f) {
    return  function($a) use ($f) {
    return  function($b) use ($f, $a) {
        return $f($b, $a);
    }; };
};

var_dump(
    array_map(
        call_user_func($curriedFlip($apply),
                       array(array(array('A', 'B', 'C'),
                                   array('D')),
                             array(array(),
                                   array('E')))),
        array($flattenA(2), $flattenB(2))));

当然，我们也可以使用循环，但这个问题要求的是一个组合子函数，类似于array_map或array_values。

对于php 5.2

function flatten(array $array) {
    $result = array();

    if (is_array($array)) {
        foreach ($array as $k => $v) {
            if (is_array($v)) {
                $result = array_merge($result, flatten($v));
            } else {
                $result[] = $v;
            }
        }
    }

    return $result;
}

/**
 * For merging values of a multidimensional array into one 
 *
 * $array = [
 *     0 => [
 *         0 => 'a1',
 *         1 => 'b1',
 *         2 => 'c1',
 *         3 => 'd1'
 *     ],
 *     1 => [
 *         0 => 'a2',
 *         1 => 'b2',
 *         2 => 'c2',
 *     ]
 * ];
 *
 * becomes : 
 *
 * $array = [
 *     0 => 'a1',
 *     1 => 'b1',
 *     2 => 'c1',
 *     3 => 'd1',
 *     4 => 'a2',
 *     5 => 'b2',
 *     6 => 'c2',
 *     
 * ]
 */
array_reduce
(
    $multiArray
    , function ($lastItem, $currentItem) {
        $lastItem = $lastItem ?: array();
        return array_merge($lastItem, array_values($currentItem));
    }
);

依据片段