试试这个!

string temp="";

public void Initialize()
{
   FileSystemWatcher _fileWatcher = new FileSystemWatcher();
  _fileWatcher.Path = "C:\\Folder";
  _fileWatcher.NotifyFilter = NotifyFilters.LastWrite;
  _fileWatcher.Filter = "Version.txt";
  _fileWatcher.Changed += new FileSystemEventHandler(OnChanged);
  _fileWatcher.EnableRaisingEvents = true;
}

private void OnChanged(object source, FileSystemEventArgs e)
{
   .......
if(temp=="")
{
   //do thing you want.
   temp = e.name //name of text file.
}else if(temp !="" && temp != e.name)
{
   //do thing you want.
   temp = e.name //name of text file.
}else
{
  //second fire ignored.
}

}

我可以通过添加一个函数来检查缓冲区数组中的重复项来做到这一点。

然后使用计时器在数组X时间内未被修改后执行该操作: -每次有东西写入缓冲区时重置计时器 —对tick执行动作

这还捕获了另一种复制类型。如果修改文件夹内的文件，该文件夹也会引发Change事件。

Function is_duplicate(str1 As String) As Boolean
    If lb_actions_list.Items.Count = 0 Then
        Return False
    Else
        Dim compStr As String = lb_actions_list.Items(lb_actions_list.Items.Count - 1).ToString
        compStr = compStr.Substring(compStr.IndexOf("-") + 1).Trim

        If compStr <> str1 AndAlso compStr.parentDir <> str1 & "\" Then
            Return False
        Else
            Return True
        End If
    End If
End Function

Public Module extentions
<Extension()>
Public Function parentDir(ByVal aString As String) As String
    Return aString.Substring(0, CInt(InStrRev(aString, "\", aString.Length - 1)))
End Function
End Module

您可以尝试打开它进行写入，如果成功，则可以假设其他应用程序已经处理了该文件。

private void OnChanged(object source, FileSystemEventArgs e)
{
    try
    {
        using (var fs = File.OpenWrite(e.FullPath))
        {
        }
        //do your stuff
    }
    catch (Exception)
    {
        //no write access, other app not done
    }
}

仅仅打开它以供写入似乎不会引发已更改的事件。所以应该是安全的。

我已经在我的委托中使用以下策略“修复”了这个问题:

// fsw_ is the FileSystemWatcher instance used by my application.

private void OnDirectoryChanged(...)
{
   try
   {
      fsw_.EnableRaisingEvents = false;

      /* do my stuff once asynchronously */
   }

   finally
   {
      fsw_.EnableRaisingEvents = true;
   }
}

我在这里有一个非常快速和简单的解决方法，它对我来说确实有效，无论事件偶尔会被触发一次或两次或多次，检查它:

private int fireCount = 0;
private void inputFileWatcher_Changed(object sender, FileSystemEventArgs e)
    {
       fireCount++;
       if (fireCount == 1)
        {
            MessageBox.Show("Fired only once!!");
            dowork();
        }
        else
        {
            fireCount = 0;
        }
    }
}

这个解决方案适用于我的生产应用程序:

环境:

VB。Net Framework 4.5.2

手动设置对象属性:NotifyFilter = Size

然后使用下面的代码:

Public Class main
    Dim CalledOnce = False
    Private Sub FileSystemWatcher1_Changed(sender As Object, e As IO.FileSystemEventArgs) Handles FileSystemWatcher1.Changed
            If (CalledOnce = False) Then
                CalledOnce = True
                If (e.ChangeType = 4) Then
                    ' Do task...
                CalledOnce = False
            End If
        End Sub
End Sub