如何使用JavaScript将字符转换为ASCII码?

例如:

从“\n”中得到10。


"\n".charCodeAt(0);

string .prototype. charcodeat()可以将字符串字符转换为ASCII数字。例如:

"ABC".charCodeAt(0) // returns 65

相反,使用String.fromCharCode(10)将数字转换为相等的ASCII字符。此函数可以接受多个数字,并连接所有字符,然后返回字符串。例子:

String.fromCharCode(65,66,67); // returns 'ABC'

这里是一个快速的ASCII字符参考:

{
"31": "",      "32": " ",     "33": "!",     "34": "\"",    "35": "#",    
"36": "$",     "37": "%",     "38": "&",     "39": "'",     "40": "(",    
"41": ")",     "42": "*",     "43": "+",     "44": ",",     "45": "-",    
"46": ".",     "47": "/",     "48": "0",     "49": "1",     "50": "2",    
"51": "3",     "52": "4",     "53": "5",     "54": "6",     "55": "7",    
"56": "8",     "57": "9",     "58": ":",     "59": ";",     "60": "<",    
"61": "=",     "62": ">",     "63": "?",     "64": "@",     "65": "A",    
"66": "B",     "67": "C",     "68": "D",     "69": "E",     "70": "F",    
"71": "G",     "72": "H",     "73": "I",     "74": "J",     "75": "K",    
"76": "L",     "77": "M",     "78": "N",     "79": "O",     "80": "P",    
"81": "Q",     "82": "R",     "83": "S",     "84": "T",     "85": "U",    
"86": "V",     "87": "W",     "88": "X",     "89": "Y",     "90": "Z",    
"91": "[",     "92": "\\",    "93": "]",     "94": "^",     "95": "_",    
"96": "`",     "97": "a",     "98": "b",     "99": "c",     "100": "d",    
"101": "e",    "102": "f",    "103": "g",    "104": "h",    "105": "i",    
"106": "j",    "107": "k",    "108": "l",    "109": "m",    "110": "n",    
"111": "o",    "112": "p",    "113": "q",    "114": "r",    "115": "s",    
"116": "t",    "117": "u",    "118": "v",    "119": "w",    "120": "x",    
"121": "y",    "122": "z",    "123": "{",    "124": "|",    "125": "}",    
"126": "~",    "127": ""
}

如果你只有一个字符而不是字符串,你可以使用:

'\n'.charCodeAt();
'\n'.codePointAt();

省略0…

它曾经比'n'. charcodeat(0)慢得多,但我现在已经测试过了,我再也看不到任何区别了(带0和不带0执行了100亿次)。仅在Chrome和Firefox中测试了性能。


虽然其他答案都是正确的,但我更喜欢这样:

function ascii (a) { return a.charCodeAt(0); }

然后,要使用它,简单地:

var lineBreak = ascii("\n");

我正在使用这个小快捷系统:

$(window).keypress(function(event) {
  if (event.ctrlKey && event.which == ascii("s")) {
    savecontent();
    }
  // ...
  });

你甚至可以在map()或其他方法中使用它:

var ints = 'ergtrer'.split('').map(ascii);

对于那些想要获得字符串的所有ASCII码的和的人:

'Foobar'
  .split('')
  .map(char => char.charCodeAt(0))
  .reduce((current, previous) => previous + current)

或者,ES6:

[...'Foobar']
  .map(char => char.charCodeAt(0))
  .reduce((current, previous) => previous + current)

为了支持来自ES6的所有UTF-16(也非bmp /补充字符),string.codePointAt()方法可用;

此方法是charCodeAt的改进版本,它只支持< 65536(216 -单个16位)的unicode码点。


JavaScript将字符串存储为UTF-16(双字节),所以如果你想忽略第二个字节,只需在0000000011111111(即255)上按位&操作符将其剥离:

'a'.charCodeAt(0) & 255 === 97; // because 'a' = 97 0 
'b'.charCodeAt(0) & 255 === 98; // because 'b' = 98 0 
'✓'.charCodeAt(0) & 255 === 19; // because '✓' = 19 39

您可以输入一个字符并使用此代码获取Ascii码

例如输入字符a 你得到Ascii码65

函数myFunction () { var str = . getelementbyid (id1); If (str.value=="") { str.focus (); 返回; } var a="ASCII码== > "; . getelementbyid(“演示”)。innerHTML = a + str.value.charCodeAt (0); } <p>检查ASCII码</p> < p > 输入任意字符: <input type="text" id="id1" name="text1" maxLength="1"> </br> < / p > <按钮onclick = " myFunction ()>获取ASCII码</按钮> < span style=" font - family:宋体;" > < / p >


str.charCodeAt(index)

使用charCodeAt () 下面的示例返回A的Unicode值65。

'ABC'.charCodeAt(0) //返回65


将字符串转换为累积数:

const stringToSum = str => [...str||”A“].reduce((a, x) => and += x.codePointAt(0), 0); console.log(stringToSum(“A”)); 65 console.log(stringToSum(“Roko”)); 411 console.log(stringToSum(“Stack Overflow”));1386

用例:

假设你想根据用户名生成不同的背景颜色:

const stringToSum = str => [...str||"A"].reduce((a, x) => a += x.codePointAt(0), 0); const UI_userIcon = user => { const hue = (stringToSum(user.name) - 65) % 360; // "A" = hue: 0 console.log(`Hue: ${hue}`); return `<div class="UserIcon" style="background:hsl(${hue}, 80%, 60%)" title="${user.name}"> <span class="UserIcon-letter">${user.name[0].toUpperCase()}</span> </div>`; }; [ {name:"A"}, {name:"Amanda"}, {name:"amanda"}, {name:"Anna"}, ].forEach(user => { document.body.insertAdjacentHTML("beforeend", UI_userIcon(user)); }); .UserIcon { width: 4em; height: 4em; border-radius: 4em; display: inline-flex; justify-content: center; align-items: center; } .UserIcon-letter { font: 700 2em/0 sans-serif; color: #fff; }


将字符串转换为UTF-8的数组(流):

const str_to_arr_of_UTF8 = new TextEncoder().encode("Adfgdfs");
// [65, 100, 102, 103, 100, 102, 115]

注意:ASCII是UTF-8的一个子集,所以这是一个通用的解决方案


对于那些想要获取字符串中所有ASCII码的平均值的人:

const ASCIIAverage = (str) =>Math.floor(str.split("))。map(item => item. charcodeat (0)).reduce((prev,next) => prev+next)/str.length) console.log (ASCIIAverage(“Hello World !”)


如果您只使用128个原始ASCII字符(代码0到127),那么扩展Álvaro González和其他注释,charCodeAt或codePointAt非常好。在此范围之外,代码依赖于字符集,如果希望结果有意义,则需要在计算之前进行字符集转换。

让我们以欧元符号为例:'€'. codepointat(0)返回8364,这远远超出了0-127的范围,并且相对于UTF-16(或UTF-8)字符集。

我移植了一个Visual Basic程序,并注意到它使用Asc函数来获取字符代码。显然,从它的角度来看,它将返回Windows-1252字符集中的字符代码。为了确保获得相同的数字,我需要转换字符串字符集,然后计算代码。

非常简单,例如在Python中:ord('€'.encode('Windows-1252'))。 然而,为了在Javascript中实现同样的效果,我不得不求助于缓冲区和转换库:

iconv = require('iconv-lite');
buf = iconv.encode("€", 'win1252');
buf.forEach(console.log);

charCodeAt(0);

以上代码在大多数情况下都可以工作,但是在使用单词查找基于上述代码的排名时存在一个问题。例如,aa会给出97+97 = 194(实际会是1+1 = 2),而w会给出119(实际会是23),这使得aa > w。 要解决这个问题,从上面的结果减去96,从1开始定位。

字符代码(0) - 96;


正如其他人指出的那样,ASCII只包含128个字符(包括非打印字符)。为了向后兼容,Unicode将ASCII作为其前128个字符,但它还包括更多字符。

如果只获取整数形式的ASCII字符码,您可以执行以下操作:

function ascii_code (character) {
  
  // Get the decimal code
  let code = character.charCodeAt(0);

  // If the code is 0-127 (which are the ASCII codes,
  if (code < 128) {
    
    // Return the code obtained.
    return code;

  // If the code is 128 or greater (which are expanded Unicode characters),
  }else{

    // Return -1 so the user knows this isn't an ASCII character.
    return -1;
  };
};

如果你只寻找字符串中的ASCII字符(例如,slugified一个字符串),你可以这样做:

function ascii_out (str) {
  // Takes a string and removes non-ASCII characters.

  // For each character in the string,
  for (let i=0; i < str.length; i++) {

    // If the character is outside the first 128 characters (which are the ASCII
    // characters),
    if (str.charCodeAt(i) > 127) {

      // Remove this character and all others like it.
      str = str.replace(new RegExp(str[i],"g"),'');

      // Decrement the index, since you just removed the character you were on.
      i--;
    };
  };
  return str
};

来源

https://www.geeksforgeeks.org/ascii-vs-unicode/: ~:文本Unicode % 20 = % 20 % 20普遍% 20字符,编码% 20标准% 20 % 20电子% 20的沟通。 https://www.w3schools.com/jsref/jsref_charcodeat.asp


也许这也很有用(ascii字符按ascii表中的顺序排列):

let ascii_chars = "";
for (let i = 32; i <= 126; ++i) {
    ascii_chars += String.fromCharCode(i);
}
document.write(ascii_chars);

截至2023年

从字符到ASCII码

使用方法charCodeAt

控制台日志(“\ n "。charCodeAt ()

从ASCII码到字符

使用fromCharCode方法

console.log(String.fromCharCode(10))